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In some applications, such as graphic equalizers, it is useful to place filters in parallel as shown in [link] . Can the parallel combination of filters be characterized by a single equivalent filter h e q ( t ) ? The answer is yes and results by noting that

y ( t ) = i = 1 N x ( t ) * h i ( t ) = i = 1 N - x ( t - τ ) h i ( τ ) d τ = - x ( t - τ ) i = 1 N h i ( τ ) d τ

Therefore, the last equation in [link] shows that

h e q ( t ) = i = 1 N h i ( t )
Parallel filter structure. We wish to find an equivalent filter with impulse response h e q ( t ) .

The equivalent transfer function for the parallel filter structure is given by

H e q ( j Ω ) = i = 1 N H i ( j Ω )

Next we wish to find an equivalent filter for the cascaded structure shown in [link] .

Cascaded filter structure. We wish to find an equivalent filter with impulse response h e q ( t ) .

This can be done by finding an expression for the intermediate value y 1 ( t ) :

y 1 ( t ) = - x ( t - τ ) h 1 ( τ ) d τ

The output of the cascaded structure is given by

y ( t ) = - y 1 ( t - γ ) h 2 ( γ ) d γ

substituting [link] into [link] gives

y ( t ) = - - x ( t - γ - τ ) h 1 ( τ ) d τ h 2 ( γ ) d γ

Reversing the order of integration and rearranging slightly gives

y ( t ) = - - x ( t - γ - τ ) h 1 ( τ ) h 2 ( γ ) d γ d τ

Now let ξ = γ + τ , solving for τ gives τ = ξ - γ and d ξ = d τ . Substituting these quantities into [link] leads to

y ( t ) = - x ( t - ξ ) - h 1 ( ξ - γ ) h 2 ( γ ) d γ d ξ

Notice that we can factor x ( t - ξ ) from the inner integral since x ( t - ξ ) does not depend on γ . The integral in the brackets is recognized as h 1 ( t ) * h 2 ( t ) evaluated at ξ . Therefore for the cascaded system, the equivalent impulse response is given by

h e q ( t ) = - h 1 ( t - γ ) h 2 ( γ ) d γ

This can be generalized to any number of cascaded filters giving

h e q ( t ) = h 1 ( t ) * h 1 ( t ) * * h N ( t )

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Source:  OpenStax, Signals, systems, and society. OpenStax CNX. Oct 07, 2012 Download for free at http://cnx.org/content/col10965/1.15
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