2.1 Symbols and notations  (Page 2/2)

$3(1+8)$

$4[2(11-5)]$

$6\{2[2(10-9)]\}$

$\frac{1+19}{2+3}$

$25+8(3)$

$2+3(18-5\cdot 2)$

$4+3[2+3(1+8÷4)]$

$\frac{19+2\{5+2[18+6(4+1)]\}}{5\cdot 6-3(5)-2}$

$2+3(6)$

$18-7(8-3)$

$8\cdot 4÷16+5$

$(21+4)÷5\cdot 2$

$3(8+2)÷6+3$

$6(4+1)÷(16÷8)-15$

$6(4-1)+8(3+7)-20$

$(8)(5)+2(14)+(1)(10)$

$61-22+4[3(10)+11]$

$\frac{(1+16-3)}{7}+5(12)$

$\frac{8(6+20)}{8}+\frac{3(6+16)}{22}$

$18÷2+55$

$21÷7÷3$

$85÷5\cdot 5-85$

$(300-25)÷(6-3)$

$4\cdot 3+8\cdot 28-(3+17)+11(6)$

$2\{(7+7)+6[4(8+2)]\}$

$0+10(0)+15[4(3)+1]$

$6.1(2.2+1.8)$

$\frac{5.9}{2}+0.6$

$(4+7)(8-3)$

$(10+5)(10+5)-4(60-4)$

$\left(\frac{5}{12}-\frac{1}{4}\right)+\left(\frac{1}{6}+\frac{2}{3}\right)$

$4\left(\frac{3}{5}-\frac{8}{15}\right)+9\left(\frac{1}{3}+\frac{1}{4}\right)$

$\frac{0}{5}+\frac{0}{1}+0[2+4(0)]$

$0\cdot 9+4\cdot 0÷7+0[2(2-2)]$

$\begin{array}{ccc}x\ge y& \text{and}& x>y\end{array}$

$\begin{array}{ccc}x=y& \text{and}& y=x\end{array}$

Represent the product of 3 and $x$ five different ways.

Represent the sum of $a$ and $b$ two different ways.

Ten minus three

$x$ plus sixteen

51 divided by $a$

81 times $x$

3 times $(x+y)$

$(x+b)$ times $(x+7)$

3 times $x$ times $y$

$x$ divided by (7 times $b$ )

$(a+b)$ divided by $(a+4)$

A number minus eight equals seventeen.

Five times a number, minus one, equals zero.

A number divided by six is greater than or equal to forty-four.

Sixteen minus twice a number equals five.

$6-4(4)(1)\le 10$

$5(4+2\cdot 10)\ge 110$

$8\cdot 6-48\le 0$

$\frac{20+4.3}{16}<5$

$2[6(1+4)-8]>3(11+6)$

$6[4+8+3(26-15)]$ $3[7(10-4)]$

The number of different ways 5 people can be arranged in a row is $5\cdot 4\cdot 3\cdot 2\cdot 1$ . How many ways is this?

A box contains 10 computer chips. Three chips are to be chosen at random. The number of ways this can be done is

$\frac{10\cdot 9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}$

How many ways is this?

The probability of obtaining four of a kind in a five-card poker hand is

$\frac{13\cdot 48}{(52\cdot 51\cdot 50\cdot 49\cdot 48)÷(5\cdot 4\cdot 3\cdot 2\cdot 1)}$

What is this probability?

Three people are on an elevator in a five story building. If each person randomly selects a floor on which to get off, the probability that at least two people get off on the same floor is

$1-\frac{5\cdot 4\cdot 3}{5\cdot 5\cdot 5}$

What is this probability?