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The program performs spectral analysis on five separate time series, each 400 samples in length. Each time series contains a pulse and the pulses aredifferent lengths.

Each pulse consists of the sum of two sinusoids at closely spaced frequencies. The frequencies of the two sinusoids are equidistant from a centerfrequency of 0.0625 times the sampling frequency. The total separation between the frequencies of the two sinusoids is the reciprocal of the length of thepulse.

All frequency values are specified as type double as a fraction of the sampling frequency.

The lengths of the pulses are:

  • 25 samples
  • 50 samples
  • 100 samples
  • 200 samples
  • 400 samples

The spectral analysis

The spectral analysis computes the spectra at 400 equally spaced frequencies between zero and the folding frequency (one-half the sampling frequency) .

The results of the spectral analysis are multiplied by the reciprocal of the lengths of the individual pulses to normalize the five plots. Otherwise, theresults for the short pulses would be too small to see on the plots.

Because of the similarity of this program to the previous programs, my discussion of the code will be very brief.

Computation of the frequencies

The code in Listing 7 shows the computation of the frequencies of the sinusoids that will be added together to form each of the five pulses.

Listing 7. Computation of the frequencies.
//Frequencies of the sinusoidsdouble freq1a = 0.0625 - 8.0/len; double freq2a = 0.0625 + 8.0/len;double freq1b = 0.0625 - 4.0/len; double freq2b = 0.0625 + 4.0/len;double freq1c = 0.0625 - 2.0/len; double freq2c = 0.0625 + 2.0/len;double freq1d = 0.0625 - 1.0/len; double freq2d = 0.0625 + 1.0/len;double freq1e = 0.0625 - 0.5/len; double freq2e = 0.0625 + 0.5/len;

Create the pulses

The code in Listing 8 uses those frequency values to create the data for the pulses and to store that data in the arrays used to hold the pulses.

Listing 8. Create the pulses.
//Create the raw data for(int x = 0;x<len/16;x++){ data1[x]= amp*Math.cos(2*pi*x*freq1a) + amp*Math.cos(2*pi*x*freq2a);}//end for loop for(int x = 0;x<len/8;x++){ data2[x]= amp*Math.cos(2*pi*x*freq1b) + amp*Math.cos(2*pi*x*freq2b);}//end for loop for(int x = 0;x<len/4;x++){ data3[x]= amp*Math.cos(2*pi*x*freq1c) + amp*Math.cos(2*pi*x*freq2c);}//end for loop for(int x = 0;x<len/2;x++){ data4[x]= amp*Math.cos(2*pi*x*freq1d) + amp*Math.cos(2*pi*x*freq2d);}//end for loop for(int x = 0;x<len;x++){ data5[x]= amp*Math.cos(2*pi*x*freq1e) + amp*Math.cos(2*pi*x*freq2e);}//end for loop

Other than the code shown in Listing 7 and Listing 8 , the program named Dsp033 is the same as the programs that were previously explained, and I won'tdiscuss it further.

Run the programs

I encourage you to copy, compile, and run the programs provided in this module. Experiment with them, making changes and observing the results of yourchanges.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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John Reply
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Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
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David Reply
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David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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Adjanou
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Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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Maurice Reply
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Maurice
answer
Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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