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                     cos ( α β ) = cos α cos β + sin α sin β                   cos ( α + β ) = ( cos α cos β sin α sin β ) ____________________________________________________ cos ( α β ) cos ( α + β ) = 2 sin α sin β

Then, we divide by 2 to isolate the product of sines:

sin α sin β = 1 2 [ cos ( α β ) cos ( α + β ) ]

Similarly we could express the product of cosines in terms of sine or derive other product-to-sum formulas.

The product-to-sum formulas

The product-to-sum formulas are as follows:

cos α cos β = 1 2 [ cos ( α β ) + cos ( α + β ) ]
sin α cos β = 1 2 [ sin ( α + β ) + sin ( α β ) ]
sin α sin β = 1 2 [ cos ( α β ) cos ( α + β ) ]
cos α sin β = 1 2 [ sin ( α + β ) sin ( α β ) ]

Express the product as a sum or difference

Write cos ( 3 θ ) cos ( 5 θ ) as a sum or difference.

We have the product of cosines, so we begin by writing the related formula. Then we substitute the given angles and simplify.

cos α cos β = 1 2 [ cos ( α β ) + cos ( α + β ) ] cos ( 3 θ ) cos ( 5 θ ) = 1 2 [ cos ( 3 θ 5 θ ) + cos ( 3 θ + 5 θ ) ] = 1 2 [ cos ( 2 θ ) + cos ( 8 θ ) ] Use even-odd identity .
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Use the product-to-sum formula to evaluate cos 11 π 12 cos π 12 .

2 3 4

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Expressing sums as products

Some problems require the reverse of the process we just used. The sum-to-product formulas allow us to express sums of sine or cosine as products. These formulas can be derived from the product-to-sum identities. For example, with a few substitutions, we can derive the sum-to-product identity for sine . Let u + v 2 = α and u v 2 = β .

Then,

α + β = u + v 2 + u v 2 = 2 u 2 = u α β = u + v 2 u v 2 = 2 v 2 = v

Thus, replacing α and β in the product-to-sum formula with the substitute expressions, we have

sin α cos β = 1 2 [ sin ( α + β ) + sin ( α β ) ] sin ( u + v 2 ) cos ( u v 2 ) = 1 2 [ sin u + sin v ] Substitute for ( α + β )  and  ( α β ) 2 sin ( u + v 2 ) cos ( u v 2 ) = sin u + sin v

The other sum-to-product identities are derived similarly.

Sum-to-product formulas

The sum-to-product formulas are as follows:

sin α + sin β = 2 sin ( α + β 2 ) cos ( α β 2 )
sin α sin β = 2 sin ( α β 2 ) cos ( α + β 2 )
cos α cos β = −2 sin ( α + β 2 ) sin ( α β 2 )
cos α + cos β = 2 cos ( α + β 2 ) cos ( α β 2 )

Writing the difference of sines as a product

Write the following difference of sines expression as a product: sin ( 4 θ ) sin ( 2 θ ) .

We begin by writing the formula for the difference of sines.

sin α sin β = 2 sin ( α β 2 ) cos ( α + β 2 )

Substitute the values into the formula, and simplify.

sin ( 4 θ ) sin ( 2 θ ) = 2 sin ( 4 θ 2 θ 2 ) cos ( 4 θ + 2 θ 2 ) = 2 sin ( 2 θ 2 ) cos ( 6 θ 2 ) = 2 sin θ cos ( 3 θ )
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Use the sum-to-product formula to write the sum as a product: sin ( 3 θ ) + sin ( θ ) .

2 sin ( 2 θ ) cos ( θ )

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Evaluating using the sum-to-product formula

Evaluate cos ( 15° ) cos ( 75° ) . Check the answer with a graphing calculator.

We begin by writing the formula for the difference of cosines.

cos α cos β = 2 sin ( α + β 2 ) sin ( α β 2 )

Then we substitute the given angles and simplify.

cos ( 15° ) cos ( 75° ) = −2 sin ( 15° + 75° 2 ) sin ( 15° 75° 2 ) = −2 sin ( 45° ) sin ( −30° ) = −2 ( 2 2 ) ( 1 2 ) = 2 2
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Proving an identity

Prove the identity:

cos ( 4 t ) cos ( 2 t ) sin ( 4 t ) + sin ( 2 t ) = tan t

We will start with the left side, the more complicated side of the equation, and rewrite the expression until it matches the right side.

cos ( 4 t ) cos ( 2 t ) sin ( 4 t ) + sin ( 2 t ) = 2 sin ( 4 t + 2 t 2 ) sin ( 4 t 2 t 2 ) 2 sin ( 4 t + 2 t 2 ) cos ( 4 t 2 t 2 ) = 2 sin ( 3 t ) sin t 2 sin ( 3 t ) cos t = 2 sin ( 3 t ) sin t 2 sin ( 3 t ) cos t = sin t cos t = tan t
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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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