<< Chapter < Page Chapter >> Page >

Find the particular solution to the differential equation y = 4 x 2 that passes through ( −3 , −30 ) , given that y = C + 4 x 3 3 is a general solution.

Got questions? Get instant answers now!

Find the particular solution to the differential equation y = 3 x 3 that passes through ( 1 , 4.75 ) , given that y = C + 3 x 4 4 is a general solution.

y = 4 + 3 x 4 4

Got questions? Get instant answers now!

Find the particular solution to the differential equation y = 3 x 2 y that passes through ( 0 , 12 ) , given that y = C e x 3 is a general solution.

Got questions? Get instant answers now!

Find the particular solution to the differential equation y = 2 x y that passes through ( 0 , 1 2 ) , given that y = C e x 2 is a general solution.

y = 1 2 e x 2

Got questions? Get instant answers now!

Find the particular solution to the differential equation y = ( 2 x y ) 2 that passes through ( 1 , 1 2 ) , given that y = 3 C + 4 x 3 is a general solution.

Got questions? Get instant answers now!

Find the particular solution to the differential equation y x 2 = y that passes through ( 1 , 2 e ) , given that y = C e 1 / x is a general solution.

y = 2 e 1 / x

Got questions? Get instant answers now!

Find the particular solution to the differential equation 8 d x d t = −2 cos ( 2 t ) cos ( 4 t ) that passes through ( π , π ) , given that x = C 1 8 sin ( 2 t ) 1 32 sin ( 4 t ) is a general solution.

Got questions? Get instant answers now!

Find the particular solution to the differential equation d u d t = tan u that passes through ( 1 , π 2 ) , given that u = sin −1 ( e C + t ) is a general solution.

u = sin −1 ( e −1 + t )

Got questions? Get instant answers now!

Find the particular solution to the differential equation d y d t = e ( t + y ) that passes through ( 1 , 0 ) , given that y = ln ( C e t ) is a general solution.

Got questions? Get instant answers now!

Find the particular solution to the differential equation y ( 1 x 2 ) = 1 + y that passes through ( 0 , −2 ) , given that y = C x + 1 1 x 1 is a general solution.

y = x + 1 1 x 1

Got questions? Get instant answers now!

For the following problems, find the general solution to the differential equation.

y = ln x + tan x

y = C x + x ln x ln ( cos x )

Got questions? Get instant answers now!

y = 4 x

y = C + 4 x ln ( 4 )

Got questions? Get instant answers now!

y = sin −1 ( 2 x )

Got questions? Get instant answers now!

y = 2 t t 2 + 16

y = 2 3 t 2 + 16 ( t 2 + 16 ) + C

Got questions? Get instant answers now!

x = coth t + ln t + 3 t 2

Got questions? Get instant answers now!

x = t 4 + t

x = 2 15 4 + t ( 3 t 2 + 4 t 32 ) + C

Got questions? Get instant answers now!

Solve the following initial-value problems starting from y ( t = 0 ) = 1 and y ( t = 0 ) = −1 . Draw both solutions on the same graph.

d y d t = t

y = 1 t 2 2 , y = t 2 2 1

Got questions? Get instant answers now!

d y d t = y

y = e t , y = e t

Got questions? Get instant answers now!

Solve the following initial-value problems starting from y 0 = 10 . At what time does y increase to 100 or drop to 1 ?

d y d t = 4 t

y = 2 ( t 2 + 5 ) , t = 3 5

Got questions? Get instant answers now!

d y d t = −2 y

y = 10 e −2 t , t = 1 2 ln ( 1 10 )

Got questions? Get instant answers now!

d y d t = e −4 t

y = 1 4 ( 41 e −4 t ) , never

Got questions? Get instant answers now!

Recall that a family of solutions includes solutions to a differential equation that differ by a constant. For the following problems, use your calculator to graph a family of solutions to the given differential equation. Use initial conditions from y ( t = 0 ) = −10 to y ( t = 0 ) = 10 increasing by 2 . Is there some critical point where the behavior of the solution begins to change?

[T] x y = y

Solution changes from increasing to decreasing at y ( 0 ) = 0

Got questions? Get instant answers now!

[T] y = x + y ( Hint: y = C e x x 1 is the general solution)

Solution changes from increasing to decreasing at y ( 0 ) = 0

Got questions? Get instant answers now!

[T] y = x ln x + sin x

Got questions? Get instant answers now!

Find the general solution to describe the velocity of a ball of mass 1 lb that is thrown upward at a rate a ft/sec.

v ( t ) = −32 t + a

Got questions? Get instant answers now!

In the preceding problem, if the initial velocity of the ball thrown into the air is a = 25 ft/s, write the particular solution to the velocity of the ball. Solve to find the time when the ball hits the ground.

Got questions? Get instant answers now!

You throw two objects with differing masses m 1 and m 2 upward into the air with the same initial velocity a ft/s. What is the difference in their velocity after 1 second?

0 ft/s

Got questions? Get instant answers now!

[T] You throw a ball of mass 1 kilogram upward with a velocity of a = 25 m/s on Mars, where the force of gravity is g = −3.711 m/s 2 . Use your calculator to approximate how much longer the ball is in the air on Mars.

Got questions? Get instant answers now!

[T] For the previous problem, use your calculator to approximate how much higher the ball went on Mars.

4.86 meters

Got questions? Get instant answers now!

[T] A car on the freeway accelerates according to a = 15 cos ( π t ) , where t is measured in hours. Set up and solve the differential equation to determine the velocity of the car if it has an initial speed of 51 mph. After 40 minutes of driving, what is the driver’s velocity?

Got questions? Get instant answers now!

[T] For the car in the preceding problem, find the expression for the distance the car has traveled in time t , assuming an initial distance of 0 . How long does it take the car to travel 100 miles? Round your answer to hours and minutes.

x = 50 t 15 π 2 cos ( π t ) + 3 π 2 , 2 hours 1 minute

Got questions? Get instant answers now!

[T] For the previous problem, find the total distance traveled in the first hour.

Got questions? Get instant answers now!

Substitute y = B e 3 t into y y = 8 e 3 t to find a particular solution.

y = 4 e 3 t

Got questions? Get instant answers now!

Substitute y = a cos ( 2 t ) + b sin ( 2 t ) into y + y = 4 sin ( 2 t ) to find a particular solution.

Got questions? Get instant answers now!

Substitute y = a + b t + c t 2 into y + y = 1 + t 2 to find a particular solution.

y = 1 2 t + t 2

Got questions? Get instant answers now!

Substitute y = a e t cos t + b e t sin t into y = 2 e t cos t to find a particular solution.

Got questions? Get instant answers now!

Solve y = e k t with the initial condition y ( 0 ) = 0 and solve y = 1 with the same initial condition. As k approaches 0 , what do you notice?

y = 1 k ( e k t 1 ) and y = x

Got questions? Get instant answers now!
Practice Key Terms 8

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Calculus volume 2. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11965/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Calculus volume 2' conversation and receive update notifications?

Ask