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y = x 2 2 ,   x > 0

Because x is the distance from the center of the parabola to either side, the entire width of the water at the top will be 2 x . The trough is 3 feet (36 inches) long, so the surface area will then be:

Area = l w = 36 2 x = 72 x = 72 2 y

This example illustrates two important points:

  1. When finding the inverse of a quadratic, we have to limit ourselves to a domain on which the function is one-to-one.
  2. The inverse of a quadratic function is a square root function. Both are toolkit functions and different types of power functions.

Functions involving roots are often called radical functions . While it is not possible to find an inverse of most polynomial functions, some basic polynomials do have inverses. Such functions are called invertible functions , and we use the notation f 1 ( x ) .

Warning: f 1 ( x ) is not the same as the reciprocal of the function f ( x ) . This use of “–1” is reserved to denote inverse functions. To denote the reciprocal of a function f ( x ) , we would need to write ( f ( x ) ) 1 = 1 f ( x ) .

An important relationship between inverse functions is that they “undo” each other. If f 1 is the inverse of a function f , then f is the inverse of the function f 1 . In other words, whatever the function f does to x , f 1 undoes it—and vice-versa.

f 1 ( f ( x ) ) = x , for all  x  in the domain of  f

and

f ( f 1 ( x ) ) = x , for all  x  in the domain of  f 1

Note that the inverse switches the domain and range of the original function.

Verifying two functions are inverses of one another

Two functions, f and g , are inverses of one another if for all x in the domain of f and g .

g ( f ( x ) ) = f ( g ( x ) ) = x

Given a polynomial function, find the inverse of the function by restricting the domain in such a way that the new function is one-to-one.

  1. Replace f ( x ) with y .
  2. Interchange x and y .
  3. Solve for y , and rename the function f 1 ( x ) .

Verifying inverse functions

Show that f ( x ) = 1 x + 1 and f 1 ( x ) = 1 x 1 are inverses, for x 0 , −1 .

We must show that f 1 ( f ( x ) ) = x and f ( f 1 ( x ) ) = x .

f 1 ( f ( x ) ) = f 1 ( 1 x + 1 ) = 1 1 x + 1 1 = ( x + 1 ) 1 = x f ( f −1 ( x ) ) = f ( 1 x 1 ) = 1 ( 1 x 1 ) + 1 = 1 1 x = x

Therefore, f ( x ) = 1 x + 1 and f 1 ( x ) = 1 x 1 are inverses.

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Show that f ( x ) = x + 5 3 and f 1 ( x ) = 3 x 5 are inverses.

f 1 ( f ( x ) ) = f 1 ( x + 5 3 ) = 3 ( x + 5 3 ) 5 = ( x 5 ) + 5 = x and f ( f 1 ( x ) ) = f ( 3 x 5 ) = ( 3 x 5 ) + 5 3 = 3 x 3 = x

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Finding the inverse of a cubic function

Find the inverse of the function f ( x ) = 5 x 3 + 1.

This is a transformation of the basic cubic toolkit function, and based on our knowledge of that function, we know it is one-to-one. Solving for the inverse by solving for x .

y = 5 x 3 + 1 x = 5 y 3 + 1 x 1 = 5 y 3 x 1 5 = y 3 f 1 ( x ) = x 1 5 3
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Find the inverse function of f ( x ) = x + 4 3 .

f 1 ( x ) = x 3 4

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Restricting the domain to find the inverse of a polynomial function

So far, we have been able to find the inverse functions of cubic functions without having to restrict their domains. However, as we know, not all cubic polynomials are one-to-one. Some functions that are not one-to-one may have their domain restricted so that they are one-to-one, but only over that domain. The function over the restricted domain would then have an inverse function    . Since quadratic functions are not one-to-one, we must restrict their domain in order to find their inverses.

Questions & Answers

If c is the cost function for a particular product, find the marginal cost functions and their values at x=10 a. c(x) = 800+ 0.04x + 0.0002x² b. c(x) = 250 + 100x + 0.001x²
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9(y+8)-27 is 9y+45. Why can't you reduce that to y+5? I know that's wrong but can't explain why
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when you reduce an equation to its simplest terms, you can't change the value of the equation. reducing it to y + 5 is equivalent to dividing it by 9 which changes the value. you can multiply it by 1 or 9/9 which would give 9(y + 5). multiplying it by one does not change the value.
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Given a polynomial expression, factor out the greatest common factor.
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The denominator of a certain fraction is 9 more than the numerator. If 6 is added to both terms of the fraction, the value of the fraction becomes 2/3. Find the original fraction. 2. The sum of the least and greatest of 3 consecutive integers is 60. What are the valu
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1. x + 6 2 -------------- = _ x + 9 + 6 3 x + 6 3 ----------- x -- (cross multiply) x + 15 2 3(x + 6) = 2(x + 15) 3x + 18 = 2x + 30 (-2x from both) x + 18 = 30 (-18 from both) x = 12 Test: 12 + 6 18 2 -------------- = --- = --- 12 + 9 + 6 27 3
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Mark and Don are planning to sell each of their marble collections at a garage sale. If Don has 1 more than 3 times the number of marbles Mark has, how many does each boy have to sell if the total number of marbles is 113?
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Mark = x,. Don = 3x + 1 x + 3x + 1 = 113 4x = 112, x = 28 Mark = 28, Don = 85, 28 + 85 = 113
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Practice Key Terms 1

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Source:  OpenStax, College algebra. OpenStax CNX. Feb 06, 2015 Download for free at https://legacy.cnx.org/content/col11759/1.3
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