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The visible strip of the electromagnetic spectrum is highlighted and shown in the picture. The wave length range is from eight hundred nanometers on the left to three hundred nanometers on the right. The divisions between infrared, visible, and ultraviolet are not perfectly distinct. The colors in the visible strip are also not perfectly distinct; they are marked as bands labeled from red on the left to violet on the right.
A small part of the electromagnetic spectrum that includes its visible components. The divisions between infrared, visible, and ultraviolet are not perfectly distinct, nor are those between the seven rainbow colors.

Living things—plants and animals—have evolved to utilize and respond to parts of the electromagnetic spectrum they are embedded in. Visible light is the most predominant and we enjoy the beauty of nature through visible light. Plants are more selective. Photosynthesis makes use of parts of the visible spectrum to make sugars.

Integrated concept problem: correcting vision with lasers

During laser vision correction, a brief burst of 193-nm ultraviolet light is projected onto the cornea of a patient. It makes a spot 0.80 mm in diameter and evaporates a layer of cornea 0 . 30 μ m size 12{0 "." "30" mm} {} thick. Calculate the energy absorbed, assuming the corneal tissue has the same properties as water; it is initially at 34º C size 12{"34"°C} {} . Assume the evaporated tissue leaves at a temperature of 100º C size 12{"100"°C} {} .

Strategy

The energy from the laser light goes toward raising the temperature of the tissue and also toward evaporating it. Thus we have two amounts of heat to add together. Also, we need to find the mass of corneal tissue involved.

Solution

To figure out the heat required to raise the temperature of the tissue to 100º C size 12{"100"°C} {} , we can apply concepts of thermal energy. We know that

Q = mc Δ T , size 12{ ital "Q "= ital " mc"ΔT} {}

where Q is the heat required to raise the temperature, Δ T size 12{DT} {} is the desired change in temperature, m size 12{m} {} is the mass of tissue to be heated, and c size 12{c} {} is the specific heat of water equal to 4186 J/kg/K.

Without knowing the mass m at this point, we have

Q = m ( 4186 J/kg/K ) ( 100º C 34º C ) = m ( 276,276 J/kg ) = m ( 276 kJ/kg ). size 12{Q=m \( "4186 J/kg/K" \) \( "100"°C - "34"°C \) =m \( "276,276 J/kg" \) =m \( "276 kJ" \) } {}

The latent heat of vaporization of water is 2256 kJ/kg, so that the energy needed to evaporate mass m size 12{m} {} is

Q v = mL v = m ( 2256 kJ/kg ) . size 12{Q rSub { size 8{v} } = mL rSub { size 8{v} } = m \( "2256" \) " kJ"} {}

To find the mass m size 12{m} {} , we use the equation ρ = m / V size 12{ρ= {m} slash {V} } {} , where ρ size 12{ρ} {} is the density of the tissue and V size 12{V} {} is its volume. For this case,

m = ρ V = (1000 kg/m 3 ) ( area × thickness (m 3 )) = (1000 kg/ m 3 ) ( π ( 0.80 × 10 3 m ) 2 / 4 ) ( 0 . 30 × 10 6 m ) = 0.151 × 10 9 kg. alignl { stack { size 12{m = ρ"V "=" 1000 kg/m" rSup { size 8{3} } \( "area"´"thickness" \) } {} #="1000" \( p \( 0 "." "80"´"10" rSup { size 8{ +- 3} } " m" \) rSup { size 8{2} } /4 \) \( 0 "." "30"´"10" rSup { size 8{-6} } " m" \) {} # =0 "." "151"´"10" rSup { size 8{ +- 9} } " kg" "." {}} } {}

Therefore, the total energy absorbed by the tissue in the eye is the sum of Q size 12{Q} {} and Q v size 12{Q rSub { size 8{v} } } {} :

Q tot = m ( c Δ T + L v ) = ( 0.151 × 10 9 kg ) ( 276 kJ/kg + 2256 kJ/kg ) = 382 × 10 9 kJ . size 12{Q rSub { size 8{"tot"} } = m \( cD"T "+" L" rSub { size 8{v} } \) =0 "." "151"´"10" rSup { size 8{-9} } \( "276"+"2256" \) ="382"´"10" rSup { size 8{-9} } " kJ"} {}

Discussion

The lasers used for this eye surgery are excimer lasers, whose light is well absorbed by biological tissue. They evaporate rather than burn the tissue, and can be used for precision work. Most lasers used for this type of eye surgery have an average power rating of about one watt. For our example, if we assume that each laser burst from this pulsed laser lasts for 10 ns, and there are 400 bursts per second, then the average power is Q tot × 400 = 150 mW size 12{Q rSub { size 8{"tot"} } ´"400"="150"" mW"} {} .

Optics is the study of the behavior of visible light and other forms of electromagnetic waves. Optics falls into two distinct categories. When electromagnetic radiation, such as visible light, interacts with objects that are large compared with its wavelength, its motion can be represented by straight lines like rays. Ray optics is the study of such situations and includes lenses and mirrors.

When electromagnetic radiation interacts with objects about the same size as the wavelength or smaller, its wave nature becomes apparent. For example, observable detail is limited by the wavelength, and so visible light can never detect individual atoms, because they are so much smaller than its wavelength. Physical or wave optics is the study of such situations and includes all wave characteristics.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
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David Reply
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David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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what are the types of wave
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answer
Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
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Source:  OpenStax, College physics. OpenStax CNX. Jul 27, 2015 Download for free at http://legacy.cnx.org/content/col11406/1.9
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