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Learning objectives

By the end of this section, you will be able to:

  • Describe the effects of magnetic fields on moving charges.
  • Use the right-hand rule 1 to determine the velocity of a charge, the direction of the magnetic field, and the direction of magnetic force on a moving charge.
  • Calculate the magnetic force on a moving charge.

The information presented in this section supports the following AP® learning objectives and science practices:

  • 2.D.1.1 The student is able to apply mathematical routines to express the force exerted on a moving charged object by a magnetic field. (S.P. 2.2)
  • 3.C.3.1 The student is able to use right-hand rules to analyze a situation involving a current-carrying conductor and a moving electrically charged object to determine the direction of the magnetic force exerted on the charged object due to the magnetic field created by the current-carrying conductor. (S.P. 1.4)

What is the mechanism by which one magnet exerts a force on another? The answer is related to the fact that all magnetism is caused by current, the flow of charge. Magnetic fields exert forces on moving charges , and so they exert forces on other magnets, all of which have moving charges.

Right hand rule 1

The magnetic force on a moving charge is one of the most fundamental known. Magnetic force is as important as the electrostatic or Coulomb force. Yet the magnetic force is more complex, in both the number of factors that affects it and in its direction, than the relatively simple Coulomb force. The magnitude of the magnetic force     F size 12{F} {} on a charge q size 12{q} {} moving at a speed v size 12{v} {} in a magnetic field of strength B size 12{B} {} is given by

F = qvB sin θ , size 12{F= ital "qvB""sin"θ} {}

where θ size 12{θ} {} is the angle between the directions of v and B . size 12{B} {} This force is often called the Lorentz force    . In fact, this is how we define the magnetic field strength B size 12{B} {} —in terms of the force on a charged particle moving in a magnetic field. The SI unit for magnetic field strength B size 12{B} {} is called the tesla    (T) after the eccentric but brilliant inventor Nikola Tesla (1856–1943). To determine how the tesla relates to other SI units, we solve F = qvB sin θ size 12{F= ital "qvB""sin"θ} {} for B size 12{B} {} .

B = F qv sin θ size 12{B= { {F} over { ital "qv""sin"θ} } } {}

Because sin θ size 12{θ} {} is unitless, the tesla is

1 T = 1 N C m/s = 1 N A m size 12{"1 T"= { {"1 N"} over {C cdot "m/s"} } = { {1" N"} over {A cdot m} } } {}

(note that C/s = A).

Another smaller unit, called the gauss    (G), where 1 G = 10 4 T size 12{1`G="10" rSup { size 8{ - 4} } `T} {} , is sometimes used. The strongest permanent magnets have fields near 2 T; superconducting electromagnets may attain 10 T or more. The Earth’s magnetic field on its surface is only about 5 × 10 5 T size 12{5 times "10" rSup { size 8{ - 5} } `T} {} , or 0.5 G.

The direction of the magnetic force F size 12{F} {} is perpendicular to the plane formed by v size 12{v} {} and B , as determined by the right hand rule 1 (or RHR-1), which is illustrated in [link] . RHR-1 states that, to determine the direction of the magnetic force on a positive moving charge, you point the thumb of the right hand in the direction of v , the fingers in the direction of B , and a perpendicular to the palm points in the direction of F . One way to remember this is that there is one velocity, and so the thumb represents it. There are many field lines, and so the fingers represent them. The force is in the direction you would push with your palm. The force on a negative charge is in exactly the opposite direction to that on a positive charge.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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