6.1 Finding the factors of a monomial

The product is 84 and one factor is 6. What is the other factor?

The product is $14x^3{y}^2{z}^5$ and one factor is $7xyz$ . What is the other factor?

$30,6$

$45,9$

$10a,5$

$16a,8$

$21b,7b$

$15a,5a$

$20x^3,4$

$30y^4,6$

$8x^4,4x$

$16y^5,2y$

$6x^{2}y,3x$

$9a^4{b}^5,9a^4$

$15x^2{b}^4{c}^7,5x^{2}b{c}^6$

$25a^3{b}^{2}c,5ac$

$18x^2{b}^5,-2x{b}^4$

$22b^8{c}^6{d}^3,-11b^8{c}^4$

$-60x^5{b}^3{f}^9,-15x^2{b}^2{f}^2$

$39x^4{y}^5{z}^{11},3x{y}^3{z}^{10}$

$147a^{20}{b}^6{c}^{18}{d}^2,21a^{3}bd$

$-121a^6{b}^8{c}^{10},11b^2{c}^5$

$\frac{1}{8}{x}^4{y}^3,\frac{1}{2}x{y}^3$

$7x^2{y}^3{z}^2,7x^2{y}^{3}z$

$5a^4{b}^7{c}^3{d}^2,5a^4{b}^7{c}^{3}d$

$14x^4{y}^3{z}^7,14x^4{y}^3{z}^7$

$12a^3{b}^2{c}^8,12a^3{b}^2{c}^8$

$6{(a+1)}^2(a+5),3{(a+1)}^2$

$8{(x+y)}^3(x-2y),2(x-2y)$

$14{(a-3)}^6{(a+4)}^2,2{(a-3)}^2(a+4)$

$26{(x-5y)}^{10}{(x-3y)}^{12},-2{(x-5y)}^7{(x-3y)}^7$

$34{(1-a)}^4{(1+a)}^8,-17{(1-a)}^4{(1+a)}^2$

$(x+y)(x-y),x-y$

$(a+3)(a-3),a-3$

$48x^{n+3}{y}^{2n-1},8x^3{y}^{n+5}$

$0.0024x^{4n}{y}^{3n+5}{z}^2,0.03x^{3n}{y}^5$

( [link] ) Simplify ${\left(x^4{y}^0{z}^2\right)}^3$ .

( [link] ) Simplify $-\left\{-\left[-\left(-\left|6\right|\right)\right]\right\}$ .

( [link] ) Find the product. ${\left(2x-4\right)}^2$ .