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Key concepts

  • If r ( t ) represents the position of an object at time t , then r ( t ) represents the velocity and r″ ( t ) represents the acceleration of the object at time t. The magnitude of the velocity vector is speed.
  • The acceleration vector always points toward the concave side of the curve defined by r ( t ) . The tangential and normal components of acceleration a T and a N are the projections of the acceleration vector onto the unit tangent and unit normal vectors to the curve.
  • Kepler’s three laws of planetary motion describe the motion of objects in orbit around the Sun. His third law can be modified to describe motion of objects in orbit around other celestial objects as well.
  • Newton was able to use his law of universal gravitation in conjunction with his second law of motion and calculus to prove Kepler’s three laws.

Key equations

  • Velocity
    v ( t ) = r ( t )
  • Acceleration
    a ( t ) = v ( t ) = r″ ( t )
  • Speed
    v ( t ) = v ( t ) = r ( t ) = d s d t
  • Tangential component of acceleration
    a T = a · T = v · a v
  • Normal component of acceleration
    a N = a · N = v × a v = a 2 a T 2

Given r ( t ) = ( 3 t 2 2 ) i + ( 2 t sin ( t ) ) j , find the velocity of a particle moving along this curve.

This figure is a curve in the xy plane. The curve begins in the fourth quadrant towards the y-axis, intersects below 0 to the x axis, then bends around to intersect the positive y-axis and increasing through the first quadrant.

v ( t ) = ( 6 t ) i + ( 2 cos ( t ) ) j

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Given r ( t ) = ( 3 t 2 2 ) i + ( 2 t sin ( t ) ) j , find the acceleration vector of a particle moving along the curve in the preceding exercise.

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Given the following position functions, find the velocity, acceleration, and speed in terms of the parameter t .

r ( t ) = 3 cos t , 3 sin t , t 2

v ( t ) = −3 sin t , 3 cos t , 2 t , a ( t ) = −3 cos t , −3 sin t , 2 , speed = 9 + 4 t 2

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r ( t ) = e t i + t 2 j + tan t k

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r ( t ) = 2 cos t j + 3 sin t k . The graph is shown here:

This figure is a curve in 3 dimensions. It is inside of a box. The box represents an octant. The curve has three pieces with vertical asymptotes in the box.

v ( t ) = −2 sin t j + 3 cos t k , a ( t ) = −2 cos t j 3 sin t k , speed = 4 sin 2 ( t ) + 9 cos 2 ( t )

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Find the velocity, acceleration, and speed of a particle with the given position function.

r ( t ) = t 2 1 , t

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r ( t ) = e t , e t

v ( t ) = e t i e t j , a ( t ) = e t i + e t j , v ( t ) e 2 t + e −2 t

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r ( t ) = sin t , t , cos t . The graph is shown here:

This figure is a curve in 3 dimensions. It is inside of a box. The box represents an octant. The curve begins in the bottom of the box, from the lower left, and bends through the box to the other side, in the lower right.
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The position function of an object is given by r ( t ) = t 2 , 5 t , t 2 16 t . At what time is the speed a minimum?

t = 4

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Let r ( t ) = r cosh ( ω t ) i + r sinh ( ω t ) j . Find the velocity and acceleration vectors and show that the acceleration is proportional to r ( t ) .

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Consider the motion of a point on the circumference of a rolling circle. As the circle rolls, it generates the cycloid r ( t ) = ( ω t sin ( ω t ) ) i + ( 1 cos ( ω t ) ) j , where ω is the angular velocity of the circle and b is the radius of the circle:

This figure is a curve in the first octant. It is semicircles connected representing humps. It begins at the origin and touches the x axis at 4pi, and 8pi.

Find the equations for the velocity, acceleration, and speed of the particle at any time.

v ( t ) = ( ω ω cos ( ω t ) ) i + ( ω sin ( ω t ) ) j ,
a ( t ) = ( ω 2 sin ( ω t ) ) i + ( ω 2 cos ( ω t ) ) j ,
speed = ω 2 2 ω 2 cos ( ω t ) + ω 2 cos 2 ( ω t ) + ω 2 sin 2 ( ω t ) = 2 ω 2 ( 1 cos ( ω t ) )

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A person on a hang glider is spiraling upward as a result of the rapidly rising air on a path having position vector r ( t ) = ( 3 cos t ) i + ( 3 sin t ) j + t 2 k . The path is similar to that of a helix, although it is not a helix. The graph is shown here:

This figure is a curve in 3 dimensions. It is inside of a box. The box represents an octant. The curve is connected in the box, from the lower left, and bends through the box to the upper right.

Find the following quantities:

The velocity and acceleration vectors

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The glider’s speed at any time

v ( t ) = 9 + 4 t 2

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The times, if any, at which the glider’s acceleration is orthogonal to its velocity

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Given that r ( t ) = e −5 t sin t , e −5 t cos t , 4 e −5 t is the position vector of a moving particle, find the following quantities:

The velocity of the particle

v ( t ) = e −5 t ( cos t 5 sin t ) , e −5 t ( sin t + 5 cos t ) , −20 e −5 t

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Practice Key Terms 6

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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