<< Chapter < Page Chapter >> Page >
By the end of this section, you will be able to:
  • Simplify expressions using the Quotient Property for Exponents
  • Simplify expressions with zero exponents
  • Simplify expressions using the quotient to a Power Property
  • Simplify expressions by applying several properties
  • Divide monomials

Before you get started, take this readiness quiz.

  1. Simplify: 8 24 .
    If you missed this problem, review [link] .
  2. Simplify: ( 2 m 3 ) 5 .
    If you missed this problem, review [link] .
  3. Simplify: 12 x 12 y .
    If you missed this problem, review [link] .

Simplify expressions using the quotient property for exponents

Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize these properties below.

Summary of exponent properties for multiplication

If a and b are real numbers, and m and n are whole numbers, then

Product Property a m · a n = a m + n Power Property ( a m ) n = a m · n Product to a Power ( a b ) m = a m b m

Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. You have learned to simplify fractions by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property. This property will also help you work with algebraic fractions—which are also quotients.

Equivalent fractions property

If a , b , and c are whole numbers where b 0 , c 0 ,

then a b = a · c b · c and a · c b · c = a b

As before, we’ll try to discover a property by looking at some examples.

Consider x 5 x 2 and x 2 x 3 What do they mean? x · x · x · x · x x · x x · x x · x · x Use the Equivalent Fractions Property. x · x · x · x · x x · x x · x · 1 x · x · x Simplify. x 3 1 x

Notice, in each case the bases were the same and we subtracted exponents.

When the larger exponent was in the numerator, we were left with factors in the numerator.

When the larger exponent was in the denominator, we were left with factors in the denominator—notice the numerator of 1.

We write:

x 5 x 2 x 2 x 3 x 5 2 1 x 3 2 x 3 1 x

This leads to the Quotient Property for Exponents .

Quotient property for exponents

If a is a real number, a 0 , and m and n are whole numbers, then

a m a n = a m n , m > n and a m a n = 1 a n m , n > m

A couple of examples with numbers may help to verify this property.

3 4 3 2 = 3 4 2 5 2 5 3 = 1 5 3 2 81 9 = 3 2 25 125 = 1 5 1 9 = 9 1 5 = 1 5

Simplify: x 9 x 7 3 10 3 2 .

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.


  1. Since 9>7, there are more factors of x in the numerator. x to the ninth power divided by x to the seventh power.
    Use the Quotient Property, a m a n = a m n . x to the power of 9 minus 7.
    Simplify. x squared.

  2. Since 10>2, there are more factors of x in the numerator. 3 to the tenth power divided by 3 squared.
    Use the Quotient Property, a m a n = a m n . 3 to the power of 10 minus 2.
    Simplify. 3 to the eighth power.

    Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Simplify: x 15 x 10 6 14 6 5 .

x 5 6 9

Got questions? Get instant answers now!

Simplify: y 43 y 37 10 15 10 7 .

y 6 10 8

Got questions? Get instant answers now!

Simplify: b 8 b 12 7 3 7 5 .

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.


  1. Since 12>8, there are more factors of b in the denominator. b to the eighth power divided b to the twelfth power.
    Use the Quotient Property, a m a n = 1 a n m . 1 divided by b to the power of 12 minus 8.
    Simplify. 1 divided by b to the fourth power.

  2. Since 5>3, there are more factors of 3 in the denominator. 7 cubed divided by 7 to the fifth power.
    Use the Quotient Property, a m a n = 1 a n m . 1 divided by 7 to the power of 5 minus 3.
    Simplify. 1 divided by 7 squared.
    Simplify. 1 forty-ninth.

    Notice that when the larger exponent is in the denominator, we are left with factors in the denominator.
Got questions? Get instant answers now!
Got questions? Get instant answers now!

Questions & Answers

calculate molarity of NaOH solution when 25.0ml of NaOH titrated with 27.2ml of 0.2m H2SO4
Gasin Reply
what's Thermochemistry
rhoda Reply
the study of the heat energy which is associated with chemical reactions
Kaddija
How was CH4 and o2 was able to produce (Co2)and (H2o
Edafe Reply
explain please
Victory
First twenty elements with their valences
Martine Reply
what is chemistry
asue Reply
what is atom
asue
what is the best way to define periodic table for jamb
Damilola Reply
what is the change of matter from one state to another
Elijah Reply
what is isolation of organic compounds
IKyernum Reply
what is atomic radius
ThankGod Reply
Read Chapter 6, section 5
Dr
Read Chapter 6, section 5
Kareem
Atomic radius is the radius of the atom and is also called the orbital radius
Kareem
atomic radius is the distance between the nucleus of an atom and its valence shell
Amos
Read Chapter 6, section 5
paulino
Bohr's model of the theory atom
Ayom Reply
is there a question?
Dr
when a gas is compressed why it becomes hot?
ATOMIC
It has no oxygen then
Goldyei
read the chapter on thermochemistry...the sections on "PV" work and the First Law of Thermodynamics should help..
Dr
Which element react with water
Mukthar Reply
Mgo
Ibeh
an increase in the pressure of a gas results in the decrease of its
Valentina Reply
definition of the periodic table
Cosmos Reply
What is the lkenes
Da Reply
what were atoms composed of?
Moses Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Elementary algebra' conversation and receive update notifications?

Ask