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Simplify: ( 2 x 4 ) 5 ( 4 x 3 ) 2 ( x 3 ) 5 .

2 x

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Divide monomials

You have now been introduced to all the properties of exponents and used them to simplify expressions. Next, you’ll see how to use these properties to divide monomials. Later, you’ll use them to divide polynomials.

Find the quotient: 56 x 7 ÷ 8 x 3 .

Solution

56 x 7 ÷ 8 x 3 Rewrite as a fraction. 56 x 7 8 x 3 Use fraction multiplication. 56 8 x 7 x 3 Simplify and use the Quotient Property. 7 x 4

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Find the quotient: 42 y 9 ÷ 6 y 3 .

7 y 6

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Find the quotient: 48 z 8 ÷ 8 z 2 .

6 z 6

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Find the quotient: 45 a 2 b 3 −5 a b 5 .

Solution

When we divide monomials with more than one variable, we write one fraction for each variable.

45 a 2 b 3 −5 a b 5 Use fraction multiplication. 45 −5 · a 2 a · b 3 b 5 Simplify and use the Quotient Property. −9 · a · 1 b 2 Multiply. 9 a b 2

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Find the quotient: −72 a 7 b 3 8 a 12 b 4 .

9 a 5 b

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Find the quotient: −63 c 8 d 3 7 c 12 d 2 .

−9 d c 4

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Find the quotient: 24 a 5 b 3 48 a b 4 .

Solution

24 a 5 b 3 48 a b 4 Use fraction multiplication. 24 48 · a 5 a · b 3 b 4 Simplify and use the Quotient Property. 1 2 · a 4 · 1 b Multiply. a 4 2 b

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Find the quotient: 16 a 7 b 6 24 a b 8 .

2 a 6 3 b 2

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Find the quotient: 27 p 4 q 7 −45 p 12 q .

3 q 6 5 p 8

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Once you become familiar with the process and have practiced it step by step several times, you may be able to simplify a fraction in one step.

Find the quotient: 14 x 7 y 12 21 x 11 y 6 .

Solution

Be very careful to simplify 14 21 by dividing out a common factor, and to simplify the variables by subtracting their exponents.

14 x 7 y 12 21 x 11 y 6 Simplify and use the Quotient Property. 2 y 6 3 x 4

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Find the quotient: 28 x 5 y 14 49 x 9 y 12 .

4 y 2 7 x 4

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Find the quotient: 30 m 5 n 11 48 m 10 n 14 .

5 8 m 5 n 3

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In all examples so far, there was no work to do in the numerator or denominator before simplifying the fraction. In the next example, we’ll first find the product of two monomials in the numerator before we simplify the fraction. This follows the order of operations. Remember, a fraction bar is a grouping symbol.

Find the quotient: ( 6 x 2 y 3 ) ( 5 x 3 y 2 ) ( 3 x 4 y 5 ) .

Solution

( 6 x 2 y 3 ) ( 5 x 3 y 2 ) ( 3 x 4 y 5 ) Simplify the numerator. 30 x 5 y 5 3 x 4 y 5 Simplify. 10 x

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Find the quotient: ( 6 a 4 b 5 ) ( 4 a 2 b 5 ) 12 a 5 b 8 .

2 a b 2

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Find the quotient: ( −12 x 6 y 9 ) ( −4 x 5 y 8 ) −12 x 10 y 12 .

−4 x y 5

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Access these online resources for additional instruction and practice with dividing monomials:

Key concepts

  • Quotient Property for Exponents:
    • If a is a real number, a 0 , and m , n are whole numbers, then:
      a m a n = a m n , m > n and a m a n = 1 a m n , n > m
  • Zero Exponent
    • If a is a non-zero number, then a 0 = 1 .

  • Quotient to a Power Property for Exponents :
    • If a and b are real numbers, b 0 , and m is a counting number, then:
      ( a b ) m = a m b m
    • To raise a fraction to a power, raise the numerator and denominator to that power.

  • Summary of Exponent Properties
    • If a , b are real numbers and m , n are whole numbers, then
      Product Property a m · a n = a m + n Power Property ( a m ) n = a m · n Product to a Power ( a b ) m = a m b m Quotient Property a m b m = a m n , a 0 , m > n a m a n = 1 a n m , a 0 , n > m Zero Exponent Definition a o = 1 , a 0 Quotient to a Power Property ( a b ) m = a m b m , b 0

Practice makes perfect

Simplify Expressions Using the Quotient Property for Exponents

In the following exercises, simplify.

x 18 x 3 5 12 5 3

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y 20 y 10 7 16 7 2

y 10 7 14

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p 21 p 7 4 16 4 4

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u 24 u 3 9 15 9 5

u 21 9 10

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q 18 q 36 10 2 10 3

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t 10 t 40 8 3 8 5

1 t 30 1 64

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x x 7 10 10 3

1 x 6 1 100

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Simplify Expressions with Zero Exponents

In the following exercises, simplify.


13 0
k 0

1 1

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27 0
( 27 0 )

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15 0
( 15 0 )

−1 −1

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( 25 x ) 0
25 x 0

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( 6 y ) 0
6 y 0

1 6

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( 12 x ) 0
( −56 p 4 q 3 ) 0

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7 y 0 ( 17 y ) 0
( −93 c 7 d 15 ) 0

7 1

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12 n 0 18 m 0
( 12 n ) 0 ( 18 m ) 0

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15 r 0 22 s 0
( 15 r ) 0 ( 22 s ) 0

−7 0

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Simplify Expressions Using the Quotient to a Power Property

In the following exercises, simplify.

( 3 4 ) 3 ( p 2 ) 5 ( x y ) 6

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( 2 5 ) 2 ( x 3 ) 4 ( a b ) 5

4 25 x 4 81 a 5 b 5

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( a 3 b ) 4 ( 5 4 m ) 2

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( x 2 y ) 3 ( 10 3 q ) 4

x 3 8 y 3 10,000 81 q 4

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Simplify Expressions by Applying Several Properties

In the following exercises, simplify.

( y 4 z 10 ) 5

y 20 z 50

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( 3 m 5 5 n ) 3

27 m 15 125 n 3

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( 5 u 7 2 v 3 ) 4

625 u 28 16 v 12

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( t 2 ) 5 ( t 4 ) 2 ( t 3 ) 7

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( q 3 ) 6 ( q 2 ) 3 ( q 4 ) 8

1 q 8

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( −2 p 2 ) 4 ( 3 p 4 ) 2 ( −6 p 3 ) 2

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( −2 k 3 ) 2 ( 6 k 2 ) 4 ( 9 k 4 ) 2

64 k 6

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( −4 m 3 ) 2 ( 5 m 4 ) 3 ( −10 m 6 ) 3

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( −10 n 2 ) 3 ( 4 n 5 ) 2 ( 2 n 8 ) 2

−4,000

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Divide Monomials

In the following exercises, divide the monomials.

−72 u 12 ÷ 1 2 u 4

−6 u 8

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45 a 6 b 8 −15 a 10 b 2

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54 x 9 y 3 −18 x 6 y 15

3 x 3 y 12

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20 m 8 n 4 30 m 5 n 9

−2 m 3 3 n 5

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18 a 4 b 8 −27 a 9 b 5

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45 x 5 y 9 −60 x 8 y 6

−3 y 3 4 x 3

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64 q 11 r 9 s 3 48 q 6 r 8 s 5

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65 a 10 b 8 c 5 42 a 7 b 6 c 8

65 a 3 b 2 42 c 3

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( 10 m 5 n 4 ) ( 5 m 3 n 6 ) 25 m 7 n 5

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( −18 p 4 q 7 ) ( −6 p 3 q 8 ) −36 p 12 q 10

−3 q 5 p 5

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( 6 a 4 b 3 ) ( 4 a b 5 ) ( 12 a 2 b ) ( a 3 b )

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( 4 u 2 v 5 ) ( 15 u 3 v ) ( 12 u 3 v ) ( u 4 v )

5 v 4 u 2

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Mixed Practice


24 a 5 + 2 a 5
24 a 5 2 a 5
24 a 5 · 2 a 5
24 a 5 ÷ 2 a 5

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15 n 10 + 3 n 10
15 n 10 3 n 10
15 n 10 · 3 n 10
15 n 10 ÷ 3 n 10

18 n 10
12 n 10
45 n 20
5

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p 4 · p 6
( p 4 ) 6

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q 5 · q 3
( q 5 ) 3

q 8
q 15

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z 6 z 5
z 5 z 6

z 1 z

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( 8 x 5 ) ( 9 x ) ÷ 6 x 3

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( 4 y ) ( 12 y 7 ) ÷ 8 y 2

6 y 6

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27 a 7 3 a 3 + 54 a 9 9 a 5

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32 c 11 4 c 5 + 42 c 9 6 c 3

15 c 6

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32 y 5 8 y 2 60 y 10 5 y 7

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48 x 6 6 x 4 35 x 9 7 x 7

3 x 2

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63 r 6 s 3 9 r 4 s 2 72 r 2 s 2 6 s

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56 y 4 z 5 7 y 3 z 3 45 y 2 z 2 5 y

y z 2

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Everyday math

Memory One megabyte is approximately 10 6 bytes. One gigabyte is approximately 10 9 bytes. How many megabytes are in one gigabyte?

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Memory One gigabyte is approximately 10 9 bytes. One terabyte is approximately 10 12 bytes. How many gigabytes are in one terabyte?

10 3

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Writing exercises

Jennifer thinks the quotient a 24 a 6 simplifies to a 4 . What is wrong with her reasoning?

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Maurice simplifies the quotient d 7 d by writing d 7 d = 7 . What is wrong with his reasoning?

Answers will vary.

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When Drake simplified 3 0 and ( −3 ) 0 he got the same answer. Explain how using the Order of Operations correctly gives different answers.

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Robert thinks x 0 simplifies to 0. What would you say to convince Robert he is wrong?

Answers will vary.

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Self check

After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This is a table that has six rows and four columns. In the first row, which is a header row, the cells read from left to right “I can…,” “Confidently,” “With some help,” and “No-I don’t get it!” The first column below “I can…” reads “simplify expressions using the Quotient Property for Exponents,” “simplify expressions with zero exponents,” “simplify expressions using the Quotient to a Power Property,” “simplify expressions by applying several properties,” and “divide monomials.” The rest of the cells are blank.

On a scale of 1-10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
Haryormhidey Reply
how many start and codon
Esrael Reply
what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
Nassze Reply
how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
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