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Factor a. 2 x 2 + 9 x + 9 b. 6 x 2 + x 1

a. ( 2 x + 3 ) ( x + 3 ) b. ( 3 x −1 ) ( 2 x + 1 )

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Factoring a perfect square trinomial

A perfect square trinomial is a trinomial that can be written as the square of a binomial. Recall that when a binomial is squared, the result is the square of the first term added to twice the product of the two terms and the square of the last term.

a 2 + 2 a b + b 2 = ( a + b ) 2 and a 2 2 a b + b 2 = ( a b ) 2

We can use this equation to factor any perfect square trinomial.

Perfect square trinomials

A perfect square trinomial can be written as the square of a binomial:

a 2 + 2 a b + b 2 = ( a + b ) 2

Given a perfect square trinomial, factor it into the square of a binomial.

  1. Confirm that the first and last term are perfect squares.
  2. Confirm that the middle term is twice the product of a b .
  3. Write the factored form as ( a + b ) 2 .

Factoring a perfect square trinomial

Factor 25 x 2 + 20 x + 4.

Notice that 25 x 2 and 4 are perfect squares because 25 x 2 = ( 5 x ) 2 and 4 = 2 2 . Then check to see if the middle term is twice the product of 5 x and 2. The middle term is, indeed, twice the product: 2 ( 5 x ) ( 2 ) = 20 x . Therefore, the trinomial is a perfect square trinomial and can be written as ( 5 x + 2 ) 2 .

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Factor 49 x 2 14 x + 1.

( 7 x −1 ) 2

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Factoring a difference of squares

A difference of squares is a perfect square subtracted from a perfect square. Recall that a difference of squares can be rewritten as factors containing the same terms but opposite signs because the middle terms cancel each other out when the two factors are multiplied.

a 2 b 2 = ( a + b ) ( a b )

We can use this equation to factor any differences of squares.

Differences of squares

A difference of squares can be rewritten as two factors containing the same terms but opposite signs.

a 2 b 2 = ( a + b ) ( a b )

Given a difference of squares, factor it into binomials.

  1. Confirm that the first and last term are perfect squares.
  2. Write the factored form as ( a + b ) ( a b ) .

Factoring a difference of squares

Factor 9 x 2 25.

Notice that 9 x 2 and 25 are perfect squares because 9 x 2 = ( 3 x ) 2 and 25 = 5 2 . The polynomial represents a difference of squares and can be rewritten as ( 3 x + 5 ) ( 3 x 5 ) .

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Factor 81 y 2 100.

( 9 y + 10 ) ( 9 y 10 )

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Is there a formula to factor the sum of squares?

No. A sum of squares cannot be factored.

Factoring the sum and difference of cubes

Now, we will look at two new special products: the sum and difference of cubes. Although the sum of squares cannot be factored, the sum of cubes can be factored into a binomial and a trinomial.

a 3 + b 3 = ( a + b ) ( a 2 a b + b 2 )

Similarly, the sum of cubes can be factored into a binomial and a trinomial, but with different signs.

a 3 b 3 = ( a b ) ( a 2 + a b + b 2 )

We can use the acronym SOAP to remember the signs when factoring the sum or difference of cubes. The first letter of each word relates to the signs: S ame O pposite A lways P ositive. For example, consider the following example.

x 3 2 3 = ( x 2 ) ( x 2 + 2 x + 4 )

The sign of the first 2 is the same as the sign between x 3 2 3 . The sign of the 2 x term is opposite the sign between x 3 2 3 . And the sign of the last term, 4, is always positive .

Sum and difference of cubes

We can factor the sum of two cubes as

a 3 + b 3 = ( a + b ) ( a 2 a b + b 2 )

We can factor the difference of two cubes as

a 3 b 3 = ( a b ) ( a 2 + a b + b 2 )

Questions & Answers

The sequence is {1,-1,1-1.....} has
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Sin(A+B) = sinBcosA+cosBsinA
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Prove it
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June needs 45 gallons of punch. 2 different coolers. Bigger cooler is 5 times as large as smaller cooler. How many gallons in each cooler?
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find the sum of 28th term of the AP 3+10+17+---------
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Prove that (sinA/1-cosA - 1-cosA/sinA) (cosA/1-sinA - 1-sinA/cosA) = 4
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In a triangle ABC prove that. (b+c)cosA+(c+a)cosB+(a+b)cisC=a+b+c.
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the polar co-ordinate of the point (-1, -1)
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Practice Key Terms 2

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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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