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If tan x = −8 , and x is in quadrant IV.

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For the following exercises, find the values of the six trigonometric functions if the conditions provided hold.

cos ( 2 θ ) = 3 5 and 90° θ 180°

cos θ = 2 5 5 , sin θ = 5 5 , tan θ = 1 2 , csc θ = 5 , sec θ = 5 2 , cot θ = 2

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cos ( 2 θ ) = 1 2 and 180° θ 270°

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For the following exercises, simplify to one trigonometric expression.

2 sin ( π 4 ) 2 cos ( π 4 )

2 sin ( π 2 )

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4 sin ( π 8 ) cos ( π 8 )

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For the following exercises, find the exact value using half-angle formulas.

sin ( π 8 )

2 2 2

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sin ( 11 π 12 )

2 3 2

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tan ( 3 π 8 )

1 2

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For the following exercises, find the exact values of a) sin ( x 2 ) , b) cos ( x 2 ) , and c) tan ( x 2 ) without solving for x .

If tan x = 4 3 , and x is in quadrant IV.

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If sin x = 12 13 , and x is in quadrant III.

a) 3 13 13 b) 2 13 13 c) 3 2

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If csc x = 7 , and x is in quadrant II.

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If sec x = 4 , and x is in quadrant II.

a) 10 4 b) 6 4 c) 15 3

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For the following exercises, use [link] to find the requested half and double angles.

Image of a right triangle. The base is length 12, and the height is length 5. The angle between the base and the height is 90 degrees, the angle between the base and the hypotenuse is theta, and the angle between the height and the hypotenuse is alpha degrees.

Find sin ( 2 θ ) , cos ( 2 θ ) , and tan ( 2 θ ).

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Find sin ( 2 α ) , cos ( 2 α ) , and tan ( 2 α ).

120 169 , 119 169 , 120 119

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Find sin ( θ 2 ) , cos ( θ 2 ) , and tan ( θ 2 ) .

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Find sin ( α 2 ) , cos ( α 2 ) , and tan ( α 2 ) .

2 13 13 , 3 13 13 , 2 3

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For the following exercises, simplify each expression. Do not evaluate.

cos 2 ( 28° ) sin 2 ( 28° )

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2 cos 2 ( 37° ) 1

cos ( 74° )

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1 2 sin 2 ( 17° )

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cos 2 ( 9 x ) sin 2 ( 9 x )

cos ( 18 x )

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4 sin ( 8 x ) cos ( 8 x )

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6 sin ( 5 x ) cos ( 5 x )

3 sin ( 10 x )

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For the following exercises, prove the given identity.

( sin t cos t ) 2 = 1 sin ( 2 t )

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sin ( 2 x ) = 2 sin ( x ) cos ( x )

2 sin ( x ) cos ( x ) = 2 ( sin ( x ) cos ( x ) ) = sin ( 2 x )

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cot x tan x = 2 cot ( 2 x )

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sin ( 2 θ ) 1 + cos ( 2 θ ) tan 2 θ = tan θ

sin ( 2 θ ) 1 + cos ( 2 θ ) tan 2 θ = 2 sin ( θ ) cos ( θ ) 1 + cos 2 θ sin 2 θ tan 2 θ = 2 sin ( θ ) cos ( θ ) 2 cos 2 θ tan 2 θ = sin ( θ ) cos θ tan 2 θ = cot ( θ ) tan 2 θ = tan θ

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For the following exercises, rewrite the expression with an exponent no higher than 1.

cos 2 ( 6 x )

1 + cos ( 12 x ) 2

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sin 4 ( 3 x )

3 + cos ( 12 x ) 4 cos ( 6 x ) 8

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cos 4 x sin 2 x

2 + cos ( 2 x ) 2 cos ( 4 x ) cos ( 6 x ) 32

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Technology

For the following exercises, reduce the equations to powers of one, and then check the answer graphically.

tan 4 x

3 + cos ( 4 x ) 4 cos ( 2 x ) 3 + cos ( 4 x ) + 4 cos ( 2 x )

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sin 2 x cos 2 x

1 cos ( 4 x ) 8

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tan 4 x cos 2 x

3 + cos ( 4 x ) 4 cos ( 2 x ) 4 ( cos ( 2 x ) + 1 )

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cos 2 ( 2 x ) sin x

( 1 + cos ( 4 x ) ) sin x 2

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tan 2 ( x 2 ) sin x

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For the following exercises, algebraically find an equivalent function, only in terms of sin x and/or cos x , and then check the answer by graphing both functions.

sin ( 4 x )

4 sin x cos x ( cos 2 x sin 2 x )

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Extensions

For the following exercises, prove the identities.

sin ( 2 x ) = 2 tan x 1 + tan 2 x

2 tan x 1 + tan 2 x = 2 sin x cos x 1 + sin 2 x cos 2 x = 2 sin x cos x cos 2 x + sin 2 x cos 2 x = 2 sin x cos x . cos 2 x 1 = 2 sin x cos x = sin ( 2 x )

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cos ( 2 α ) = 1 tan 2 α 1 + tan 2 α

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tan ( 2 x ) = 2 sin x cos x 2 cos 2 x 1

2 sin x cos x 2 cos 2 x 1 = sin ( 2 x ) cos ( 2 x ) = tan ( 2 x )

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( sin 2 x 1 ) 2 = cos ( 2 x ) + sin 4 x

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sin ( 3 x ) = 3 sin x cos 2 x sin 3 x

sin ( x + 2 x ) = sin x cos ( 2 x ) + sin ( 2 x ) cos x = sin x ( cos 2 x sin 2 x ) + 2 sin x cos x cos x = sin x cos 2 x sin 3 x + 2 sin x cos 2 x = 3 sin x cos 2 x sin 3 x

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cos ( 3 x ) = cos 3 x 3 sin 2 x cos x

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1 + cos ( 2 t ) sin ( 2 t ) cos t = 2 cos t 2 sin t 1

1 + cos ( 2 t ) sin ( 2 t ) cos t = 1 + 2 cos 2 t 1 2 sin t cos t cos t = 2 cos 2 t cos t ( 2 sin t 1 ) = 2 cos t 2 sin t 1

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sin ( 16 x ) = 16 sin x cos x cos ( 2 x ) cos ( 4 x ) cos ( 8 x )

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cos ( 16 x ) = ( cos 2 ( 4 x ) sin 2 ( 4 x ) sin ( 8 x ) ) ( cos 2 ( 4 x ) sin 2 ( 4 x ) + sin ( 8 x ) )

( cos 2 ( 4 x ) sin 2 ( 4 x ) sin ( 8 x ) ) ( cos 2 ( 4 x ) sin 2 ( 4 x ) + sin ( 8 x ) ) = = ( cos ( 8 x ) sin ( 8 x ) ) ( cos ( 8 x ) + sin ( 8 x ) ) = cos 2 ( 8 x ) sin 2 ( 8 x ) = cos ( 16 x )

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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
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Practice Key Terms 3

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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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