Use grouping to factor and solve the quadratic equation:
First, multiply
Then list the factors of
The only pair of factors that sums to
is
Rewrite the equation replacing the
b term,
with two terms using 3 and 12 as coefficients of
x . Factor the first two terms, and then factor the last two terms.
Solving a polynomial of higher degree by factoring
Solve the equation by factoring:
This equation does not look like a quadratic, as the highest power is 3, not 2. Recall that the first thing we want to do when solving any equation is to factor out the GCF, if one exists. And it does here. We can factor out
from all of the terms and then proceed with grouping.
Use grouping on the expression in parentheses.
Now, we use the zero-product property. Notice that we have three factors.
When there is no linear term in the equation, another method of solving a quadratic equation is by using the
square root property , in which we isolate the
term and take the square root of the number on the other side of the equals sign. Keep in mind that sometimes we may have to manipulate the equation to isolate the
term so that the square root property can be used.
The square root property
With the
term isolated, the square root property states that:
where
k is a nonzero real number.
Given a quadratic equation with an
term but no
term, use the square root property to solve it.
Isolate the
term on one side of the equal sign.
Take the square root of both sides of the equation, putting a
sign before the expression on the side opposite the squared term.
Simplify the numbers on the side with the
sign.
Solving a simple quadratic equation using the square root property
Solve the quadratic using the square root property:
Take the square root of both sides, and then simplify the radical. Remember to use a
sign before the radical symbol.
Not all quadratic equations can be factored or can be solved in their original form using the square root property. In these cases, we may use a method for solving a
quadratic equation known as
completing the square . Using this method, we add or subtract terms to both sides of the equation until we have a perfect square trinomial on one side of the equal sign. We then apply the square root property. To complete the square, the leading coefficient,
a , must equal 1. If it does not, then divide the entire equation by
a . Then, we can use the following procedures to solve a quadratic equation by completing the square.
Questions & Answers
A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?