




Card 21 / 21:
y intercept
a point where a graph intercepts the y axis; an ordered pair with an x coordinate of zero

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Questions & Answers
Cos 45 = 1/ √ 2
sec 30 = 2/√3
cosec 30 = 2.
=1/√2 / 2/√3+2
=1/√2/2+2√3/√3
=1/√2*√3/2+2√3
=√3/√2(2+2√3)
=√3/2√2+2√6  (1)
=√3 (2√62√2)/((2√6)+2√2))(2√62√2)
=2√3(√6√2)/(2√6)²(2√2)²
=2√3(√6√2)/248
=2√3(√6√2)/16
=√18√16/8
=3√2√6/8 (2)
exercise 1.2 solution b....isnt it lacking
what is onetoone function
what is the procedure in solving quadratic equetion at least 6?
Almighty formula or by factorization...or by graphical analysis
Damian
I need to learn this trigonometry from A level.. can anyone help here?
cos(a+b)+cos(ab)/sin(a+b)sin(ab)=cotb ... pls some one should help me with this..thanks in anticipation
f(x)=x/x+2 given g(x)=1+2x/1x show that gf(x)=1+2x/3
sebd me some questions about anything ill solve for yall
cos(a+b)+cos(ab)/sin(a+b)sin(ab)= cotb
favour
how to solve x²=2x+8 factorization?
x=2x+8
x2x=2x+82x
x2x=8
x=8
x/1=8/1
x=8
prove:
if x=8
8=2(8)+8
8=16+8
8=8
(PROVEN)
Manifoldee
×=2x8 minus both sides by 2x
Manifoldee
so, x2x=2x+82x
Manifoldee
then cancel out 2x and 2x, cuz 2x2x is obviously zero
Manifoldee
so it would be like this: x2x=8
Manifoldee
then we all know that beside the variable is a number (1): (1)x2x=8
Manifoldee
so we will going to minus that 12=1
Manifoldee
so it would be x=8
Manifoldee
so next step is to cancel out negative number beside x so we get positive x
Manifoldee
so by doing it you need to divide both side by 1 so it would be like this: (1x/1)=(8/1)
Manifoldee
SO THE ANSWER IS X=8
Manifoldee
so we should prove it
Manifoldee
x=2x+8
x2x=8
x=8
x=8 by mantu from India
mantu
lol i just saw its x²
Manifoldee
x²=2x8
x²2x=8
x²=8
x²=8
square root(x²)=square root(8)
x=sq. root(8)
Manifoldee
I mean x²=2x+8 by factorization method
Kristof
I think x=2 or x=4
Kristof
x= 2x+8
×=82x
 2x + x = 8
 x = 8 both sides divided  1
×/1 = 8/1
× =  8 //// from somalia
Mohamed
1KI POWER 1/3 PLEASE SOLUTIONS
can u tell me concepts
Gaurav
Find the possible value of 8.5 using moivre's theorem
which of these functions is not uniformly cintinuous on (0, 1)? sinx
which of these functions is not uniformly continuous on 0,1
Source:
OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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