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In this section you will:
  • Graph plane curves described by parametric equations by plotting points.
  • Graph parametric equations.

It is the bottom of the ninth inning, with two outs and two men on base. The home team is losing by two runs. The batter swings and hits the baseball at 140 feet per second and at an angle of approximately 45° to the horizontal. How far will the ball travel? Will it clear the fence for a game-winning home run? The outcome may depend partly on other factors (for example, the wind), but mathematicians can model the path of a projectile and predict approximately how far it will travel using parametric equations . In this section, we’ll discuss parametric equations and some common applications, such as projectile motion problems.

Photo of a baseball batter swinging.
Parametric equations can model the path of a projectile. (credit: Paul Kreher, Flickr)

Graphing parametric equations by plotting points

In lieu of a graphing calculator or a computer graphing program, plotting points to represent the graph of an equation is the standard method. As long as we are careful in calculating the values, point-plotting is highly dependable.

Given a pair of parametric equations, sketch a graph by plotting points.

  1. Construct a table with three columns: t , x ( t ) , and y ( t ) .
  2. Evaluate x and y for values of t over the interval for which the functions are defined.
  3. Plot the resulting pairs ( x , y ) .

Sketching the graph of a pair of parametric equations by plotting points

Sketch the graph of the parametric equations x ( t ) = t 2 + 1 , y ( t ) = 2 + t .

Construct a table of values for t , x ( t ) , and y ( t ) , as in [link] , and plot the points in a plane.

t x ( t ) = t 2 + 1 y ( t ) = 2 + t
5 26 3
4 17 2
3 10 1
2 5 0
1 2 1
0 1 2
1 2 3
2 5 4
3 10 5
4 17 6
5 26 7

The graph is a parabola with vertex at the point ( 1 , 2 ) , opening to the right. See [link] .

Graph of the given parabola opening to the right.
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Sketch the graph of the parametric equations x = t , y = 2 t + 3 , 0 t 3.

Graph of the given parametric equations with the restricted domain - it looks like the right half of an upward opening parabola.
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Sketching the graph of trigonometric parametric equations

Construct a table of values for the given parametric equations and sketch the graph:

x = 2 cos t y = 4 sin t

Construct a table like that in [link] using angle measure in radians as inputs for t , and evaluating x and y . Using angles with known sine and cosine values for t makes calculations easier.

t x = 2 cos t y = 4 sin t
0 x = 2 cos ( 0 ) = 2 y = 4 sin ( 0 ) = 0
π 6 x = 2 cos ( π 6 ) = 3 y = 4 sin ( π 6 ) = 2
π 3 x = 2 cos ( π 3 ) = 1 y = 4 sin ( π 3 ) = 2 3
π 2 x = 2 cos ( π 2 ) = 0 y = 4 sin ( π 2 ) = 4
2 π 3 x = 2 cos ( 2 π 3 ) = 1 y = 4 sin ( 2 π 3 ) = 2 3
5 π 6 x = 2 cos ( 5 π 6 ) = 3 y = 4 sin ( 5 π 6 ) = 2
π x = 2 cos ( π ) = 2 y = 4 sin ( π ) = 0
7 π 6 x = 2 cos ( 7 π 6 ) = 3 y = 4 sin ( 7 π 6 ) = 2
4 π 3 x = 2 cos ( 4 π 3 ) = 1 y = 4 sin ( 4 π 3 ) = 2 3
3 π 2 x = 2 cos ( 3 π 2 ) = 0 y = 4 sin ( 3 π 2 ) = 4
5 π 3 x = 2 cos ( 5 π 3 ) = 1 y = 4 sin ( 5 π 3 ) = 2 3
11 π 6 x = 2 cos ( 11 π 6 ) = 3 y = 4 sin ( 11 π 6 ) = 2
2 π x = 2 cos ( 2 π ) = 2 y = 4 sin ( 2 π ) = 0

[link] shows the graph.

Graph of the given equations - a vertical ellipse.

By the symmetry shown in the values of x and y , we see that the parametric equations represent an ellipse . The ellipse is mapped in a counterclockwise direction as shown by the arrows indicating increasing t values.

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Graph the parametric equations: x = 5 cos t , y = 3 sin t .

Graph of the given equations - a horizontal ellipse.
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Graphing parametric equations and rectangular form together

Graph the parametric equations x = 5 cos t and y = 2 sin t . First, construct the graph using data points generated from the parametric form . Then graph the rectangular form of the equation. Compare the two graphs.

Construct a table of values like that in [link] .

t x = 5 cos t y = 2 sin t
0 x = 5 cos ( 0 ) = 5 y = 2 sin ( 0 ) = 0
1 x = 5 cos ( 1 ) 2.7 y = 2 sin ( 1 ) 1.7
2 x = 5 cos ( 2 ) −2.1 y = 2 sin ( 2 ) 1.8
3 x = 5 cos ( 3 ) −4.95 y = 2 sin ( 3 ) 0.28
4 x = 5 cos ( 4 ) −3.3 y = 2 sin ( 4 ) −1.5
5 x = 5 cos ( 5 ) 1.4 y = 2 sin ( 5 ) −1.9
−1 x = 5 cos ( −1 ) 2.7 y = 2 sin ( −1 ) −1.7
−2 x = 5 cos ( −2 ) −2.1 y = 2 sin ( −2 ) −1.8
−3 x = 5 cos ( −3 ) −4.95 y = 2 sin ( −3 ) −0.28
−4 x = 5 cos ( −4 ) −3.3 y = 2 sin ( −4 ) 1.5
−5 x = 5 cos ( −5 ) 1.4 y = 2 sin ( −5 ) 1.9

Plot the ( x , y ) values from the table. See [link] .

Graph of the given ellipse in parametric and rectangular coordinates - it is the same thing in both images.

Next, translate the parametric equations to rectangular form. To do this, we solve for t in either x ( t ) or y ( t ) , and then substitute the expression for t in the other equation. The result will be a function y ( x ) if solving for t as a function of x , or x ( y ) if solving for t as a function of y .

x = 5 cos t x 5 = cos t Solve for  cos t . y = 2 sin t   Solve for  sin t . y 2 = sin t

Then, use the Pythagorean Theorem    .

cos 2 t + sin 2 t = 1 ( x 5 ) 2 + ( y 2 ) 2 = 1 x 2 25 + y 2 4 = 1
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Questions & Answers

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Aditi Reply
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Adamu Reply
4
DB
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Joeval Reply
-16a+6b+2c
Will
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Joeval
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Ayush Reply
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Miranda
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Miranda
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master
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master
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Y
master
X2-2X+8-4X2+12X-20=0 (X2-4X2)+(-2X+12X)+(-20+8)= 0 -3X2+10X-12=0 3X2-10X+12=0 Use quadratic formula To find the answer answer (5±Root11i)/3
master
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master
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Mukhtar
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Lukman Reply
What is the correct rational algebraic expression of the given "a fraction whose denominator is 10 more than the numerator y?
Racelle Reply
y/y+10
Mr
Find nth derivative of eax sin (bx + c).
Anurag Reply
Find area common to the parabola y2 = 4ax and x2 = 4ay.
Anurag
A rectangular garden is 25ft wide. if its area is 1125ft, what is the length of the garden
Jhovie Reply
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Miranda
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Jhovie
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Yaona
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Miranda
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Miranda
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jai
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Miranda
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Propessor Reply
I think the formula for calculating algebraic is the statement of the equality of two expression stimulate by a set of addition, multiplication, soustraction, division, raising to a power and extraction of Root. U believe by having those in the equation you will be in measure to calculate it
Miranda
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sita Reply
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Propessor
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Miranda
the Cayley hamilton Theorem state if A is a square matrix and if f(x) is its characterics polynomial then f(x)=0 in another ways evey square matrix is a root of its chatacteristics polynomial.
Miranda
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jai
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Propessor
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What is algebra
Pearl Reply
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Miranda
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Jeffrey
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Miranda
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Jeffrey
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Miranda
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Jeffrey
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Miranda
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Jeffrey
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Miranda
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Miranda
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Steve
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Jeffrey
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Nelson Reply
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Miranda
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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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