# 7.4 The other trigonometric functions  (Page 5/14)

 Page 5 / 14

## Period of a function

The period     $\text{\hspace{0.17em}}P\text{\hspace{0.17em}}$ of a repeating function $\text{\hspace{0.17em}}f\text{\hspace{0.17em}}$ is the number representing the interval such that $\text{\hspace{0.17em}}f\left(x+P\right)=f\left(x\right)\text{\hspace{0.17em}}$ for any value of $\text{\hspace{0.17em}}x.$

The period of the cosine, sine, secant, and cosecant functions is $\text{\hspace{0.17em}}2\pi .$

The period of the tangent and cotangent functions is $\text{\hspace{0.17em}}\pi .$

## Finding the values of trigonometric functions

Find the values of the six trigonometric functions of angle $\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ based on [link] .

Find the values of the six trigonometric functions of angle $\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$ based on [link] .

$\begin{array}{l}\mathrm{sin}t=-1,\mathrm{cos}t=0,\mathrm{tan}t=\text{Undefined}\\ \mathrm{sec}t=\text{Undefined,}\mathrm{csc}t=-1,\mathrm{cot}t=0\end{array}$

## Finding the value of trigonometric functions

If $\text{\hspace{0.17em}}\mathrm{sin}\left(t\right)=-\frac{\sqrt{3}}{2}\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}\text{cos}\left(t\right)=\frac{1}{2},\text{find}\text{\hspace{0.17em}}\text{sec}\left(t\right),\text{csc}\left(t\right),\text{tan}\left(t\right),\text{cot}\left(t\right).$

$\text{\hspace{0.17em}}\mathrm{sin}\left(t\right)=\frac{\sqrt{2}}{2}\text{\hspace{0.17em}}\text{and}\text{\hspace{0.17em}}\mathrm{cos}\left(t\right)=\frac{\sqrt{2}}{2},\text{find}\text{\hspace{0.17em}}\text{sec}\left(t\right),\text{csc}\left(t\right),\text{tan}\left(t\right),\text{and}\text{\hspace{0.17em}}\text{cot}\left(t\right)$

$\mathrm{sec}t=\sqrt{2},\mathrm{csc}t=\sqrt{2},\mathrm{tan}t=1,\mathrm{cot}t=1$

## Evaluating trigonometric functions with a calculator

We have learned how to evaluate the six trigonometric functions for the common first-quadrant angles and to use them as reference angles for angles in other quadrants. To evaluate trigonometric functions of other angles, we use a scientific or graphing calculator or computer software. If the calculator has a degree mode and a radian mode, confirm the correct mode is chosen before making a calculation.

Evaluating a tangent function with a scientific calculator as opposed to a graphing calculator or computer algebra system is like evaluating a sine or cosine: Enter the value and press the TAN key. For the reciprocal functions, there may not be any dedicated keys that say CSC, SEC, or COT. In that case, the function must be evaluated as the reciprocal of a sine, cosine, or tangent.

If we need to work with degrees and our calculator or software does not have a degree mode, we can enter the degrees multiplied by the conversion factor $\text{\hspace{0.17em}}\frac{\pi }{180}\text{\hspace{0.17em}}$ to convert the degrees to radians. To find the secant of $\text{\hspace{0.17em}}30°,$ we could press

Given an angle measure in radians, use a scientific calculator to find the cosecant.

1. If the calculator has degree mode and radian mode, set it to radian mode.
2. Enter: $\text{\hspace{0.17em}}1\text{/}$
3. Enter the value of the angle inside parentheses.
4. Press the SIN key.
5. Press the = key.

Given an angle measure in radians, use a graphing utility/calculator to find the cosecant.

• If the graphing utility has degree mode and radian mode, set it to radian mode.
• Enter: $\text{\hspace{0.17em}}1\text{/}$
• Press the SIN key.
• Enter the value of the angle inside parentheses.
• Press the ENTER key.

## Evaluating the cosecant using technology

Evaluate the cosecant of $\text{\hspace{0.17em}}\frac{5\pi }{7}.$

For a scientific calculator, enter information as follows:

Evaluate the cotangent of $\text{\hspace{0.17em}}-\frac{\pi }{8}.$

$\approx -2.414$

Access these online resources for additional instruction and practice with other trigonometric functions.

Cos45/sec30+cosec30=
Cos 45 = 1/ √ 2 sec 30 = 2/√3 cosec 30 = 2. =1/√2 / 2/√3+2 =1/√2/2+2√3/√3 =1/√2*√3/2+2√3 =√3/√2(2+2√3) =√3/2√2+2√6 --------- (1) =√3 (2√6-2√2)/((2√6)+2√2))(2√6-2√2) =2√3(√6-√2)/(2√6)²-(2√2)² =2√3(√6-√2)/24-8 =2√3(√6-√2)/16 =√18-√16/8 =3√2-√6/8 ----------(2)
exercise 1.2 solution b....isnt it lacking
I dnt get dis work well
what is one-to-one function
what is the procedure in solving quadratic equetion at least 6?
Almighty formula or by factorization...or by graphical analysis
Damian
I need to learn this trigonometry from A level.. can anyone help here?
yes am hia
Miiro
tanh2x =2tanhx/1+tanh^2x
cos(a+b)+cos(a-b)/sin(a+b)-sin(a-b)=cotb ... pls some one should help me with this..thanks in anticipation
f(x)=x/x+2 given g(x)=1+2x/1-x show that gf(x)=1+2x/3
proof
AUSTINE
sebd me some questions about anything ill solve for yall
cos(a+b)+cos(a-b)/sin(a+b)-sin(a-b)= cotb
favour
how to solve x²=2x+8 factorization?
x=2x+8 x-2x=2x+8-2x x-2x=8 -x=8 -x/-1=8/-1 x=-8 prove: if x=-8 -8=2(-8)+8 -8=-16+8 -8=-8 (PROVEN)
Manifoldee
x=2x+8
Manifoldee
×=2x-8 minus both sides by 2x
Manifoldee
so, x-2x=2x+8-2x
Manifoldee
then cancel out 2x and -2x, cuz 2x-2x is obviously zero
Manifoldee
so it would be like this: x-2x=8
Manifoldee
then we all know that beside the variable is a number (1): (1)x-2x=8
Manifoldee
so we will going to minus that 1-2=-1
Manifoldee
so it would be -x=8
Manifoldee
so next step is to cancel out negative number beside x so we get positive x
Manifoldee
so by doing it you need to divide both side by -1 so it would be like this: (-1x/-1)=(8/-1)
Manifoldee
so -1/-1=1
Manifoldee
so x=-8
Manifoldee
Manifoldee
so we should prove it
Manifoldee
x=2x+8 x-2x=8 -x=8 x=-8 by mantu from India
mantu
lol i just saw its x²
Manifoldee
x²=2x-8 x²-2x=8 -x²=8 x²=-8 square root(x²)=square root(-8) x=sq. root(-8)
Manifoldee
I mean x²=2x+8 by factorization method
Kristof
I think x=-2 or x=4
Kristof
x= 2x+8 ×=8-2x - 2x + x = 8 - x = 8 both sides divided - 1 -×/-1 = 8/-1 × = - 8 //// from somalia
Mohamed
i am in
Cliff
hii
Amit
how are you
Dorbor
well
Biswajit
can u tell me concepts
Gaurav
Find the possible value of 8.5 using moivre's theorem
which of these functions is not uniformly cintinuous on (0, 1)? sinx
helo
Akash
hlo
Akash
Hello
Hudheifa
which of these functions is not uniformly continuous on 0,1