pH= pka + log (A^-) / (HA) e.g. pH in stomach = ~2 and pKa asprin= ~3.5 2=3.5 + log (A-)/(HA) log (A-)/(HA) = -1.5 10^-1.5 = 0.03 [Proportion of unionised molecules for every 1 ionised] 1/0.03 = 33 %
e.g. pH in stomach = ~2 and pKa asprin= ~3.5
2=3.5 + log (A-)/(HA)
log (A-)/(HA) = -1.5
10^-1.5 = 0.03 [Proportion of unionised molecules for every 1 ionised]
1/0.03 = 33 %
Pharmacology (Test) [Excluding Nervous System]
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