A quantity
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ varies inversely with the square of
$\text{\hspace{0.17em}}x.\text{\hspace{0.17em}}$ If
$\text{\hspace{0.17em}}y=8\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}x=3,\text{\hspace{0.17em}}$ find
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ is 4.
Many situations are more complicated than a basic direct variation or inverse variation model. One variable often depends on multiple other variables. When a variable is dependent on the product or quotient of two or more variables, this is called
joint variation . For example, the cost of busing students for each school trip varies with the number of students attending and the distance from the school. The variable
$\text{\hspace{0.17em}}c,$ cost, varies jointly with the number of students,
$\text{\hspace{0.17em}}n,$ and the distance,
$\text{\hspace{0.17em}}d.\text{\hspace{0.17em}}$
Joint variation
Joint variation occurs when a variable varies directly or inversely with multiple variables.
For instance, if
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ varies directly with both
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z,\text{\hspace{0.17em}}$ we have
$\text{\hspace{0.17em}}x=kyz.\text{\hspace{0.17em}}$ If
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ varies directly with
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ and inversely with
$z,$ we have
$\text{\hspace{0.17em}}x=\frac{ky}{z}.\text{\hspace{0.17em}}$ Notice that we only use one constant in a joint variation equation.
Solving problems involving joint variation
A quantity
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ varies directly with the square of
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ and inversely with the cube root of
$\text{\hspace{0.17em}}z.\text{\hspace{0.17em}}$ If
$\text{\hspace{0.17em}}x=6\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}y=2\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=8,\text{\hspace{0.17em}}$ find
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}y=1\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=27.\text{\hspace{0.17em}}$
Begin by writing an equation to show the relationship between the variables.
$$x=\frac{k{y}^{2}}{\sqrt[3]{z}}$$
Substitute
$\text{\hspace{0.17em}}x=6,\text{\hspace{0.17em}}$$y=2,\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=8\text{\hspace{0.17em}}$ to find the value of the constant
$\text{\hspace{0.17em}}k.\text{\hspace{0.17em}}$
Now we can substitute the value of the constant into the equation for the relationship.
$$x=\frac{3{y}^{2}}{\sqrt[3]{z}}$$
To find
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}y=1\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=27,\text{\hspace{0.17em}}$ we will substitute values for
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z\text{\hspace{0.17em}}$ into our equation.
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ varies directly with the square of
$\text{\hspace{0.17em}}y\text{\hspace{0.17em}}$ and inversely with
$\text{\hspace{0.17em}}z.\text{\hspace{0.17em}}$ If
$\text{\hspace{0.17em}}x=40\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}y=4\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=2,\text{\hspace{0.17em}}$ find
$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$ when
$\text{\hspace{0.17em}}y=10\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}z=25.$
Someone should please solve it for me
Add 2over ×+3 +y-4 over 5
simplify (×+a)with square root of two -×root 2 all over a
multiply 1over ×-y{(×-y)(×+y)} over ×y
For the first question, I got (3y-2)/15
Second one, I got Root 2
Third one, I got 1/(y to the fourth power)
I dont if it's right cause I can barely understand the question.
Is under distribute property, inverse function, algebra and addition and multiplication function; so is a combined question
graph the following linear equation using intercepts method.
2x+y=4
Ashley
how
Wargod
what?
John
ok, one moment
UriEl
how do I post your graph for you?
UriEl
it won't let me send an image?
UriEl
also for the first one... y=mx+b so.... y=3x-2
UriEl
y=mx+b
you were already given the 'm' and 'b'.
so..
y=3x-2
Tommy
Please were did you get y=mx+b from
Abena
y=mx+b is the formula of a straight line.
where m = the slope & b = where the line crosses the y-axis. In this case, being that the "m" and "b", are given, all you have to do is plug them into the formula to complete the equation.
Tommy
thanks Tommy
Nimo
"7"has an open circle and "10"has a filled in circle who can I have a set builder notation
I've run into this:
x = r*cos(angle1 + angle2)
Which expands to:
x = r(cos(angle1)*cos(angle2) - sin(angle1)*sin(angle2))
The r value confuses me here, because distributing it makes:
(r*cos(angle2))(cos(angle1) - (r*sin(angle2))(sin(angle1))
How does this make sense? Why does the r distribute once
this is an identity when 2 adding two angles within a cosine. it's called the cosine sum formula. there is also a different formula when cosine has an angle minus another angle it's called the sum and difference formulas and they are under any list of trig identities
Brad
strategies to form the general term
carlmark
consider r(a+b) = ra + rb. The a and b are the trig identity.
Mike
How can you tell what type of parent function a graph is ?
generally by how the graph looks and understanding what the base parent functions look like and perform on a graph
William
if you have a graphed line, you can have an idea by how the directions of the line turns, i.e. negative, positive, zero
William
y=x will obviously be a straight line with a zero slope
William
y=x^2 will have a parabolic line opening to positive infinity on both sides of the y axis
vice versa with y=-x^2 you'll have both ends of the parabolic line pointing downward heading to negative infinity on both sides of the y axis
William
y=x will be a straight line, but it will have a slope of one. Remember, if y=1 then x=1, so for every unit you rise you move over positively one unit. To get a straight line with a slope of 0, set y=1 or any integer.
Aaron
yes, correction on my end, I meant slope of 1 instead of slope of 0
Typically a function 'f' will take 'x' as input, and produce 'y' as output. As
'f(x)=y'.
According to Google,
"The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain."
Thomas
Sorry, I don't know where the "Â"s came from. They shouldn't be there. Just ignore them. :-)
Thomas
GREAT ANSWER THOUGH!!!
Darius
Thanks.
Thomas
Â
Thomas
It is the Â that should not be there. It doesn't seem to show if encloses in quotation marks.
"Â" or 'Â' ... Â
I've been struggling so much through all of this. my final is in four weeks 😭
Tiffany
this book is an excellent resource! have you guys ever looked at the online tutoring? there's one that is called "That Tutor Guy" and he goes over a lot of the concepts
Darius
thank you I have heard of him. I should check him out.
Tiffany
is there any question in particular?
Joe
I have always struggled with math. I get lost really easy, if you have any advice for that, it would help tremendously.
Tiffany
Sure, are you in high school or college?
Darius
Hi, apologies for the delayed response. I'm in college.
The center is at (3,4) a focus is at (3,-1) and the lenght of the major axis is 26 what will be the answer?
Rima
I done know
Joe
What kind of answer is that😑?
Rima
I had just woken up when i got this message
Joe
Can you please help me. Tomorrow is the deadline of my assignment then I don't know how to solve that
Rima
i have a question.
Abdul
how do you find the real and complex roots of a polynomial?
Abdul
@abdul with delta maybe which is b(square)-4ac=result then the 1st root -b-radical delta over 2a and the 2nd root -b+radical delta over 2a. I am not sure if this was your question but check it up
Nare
This is the actual question: Find all roots(real and complex) of the polynomial f(x)=6x^3 + x^2 - 4x + 1
Abdul
@Nare please let me know if you can solve it.
Abdul
I have a question
juweeriya
hello guys I'm new here? will you happy with me
mustapha
The average annual population increase of a pack of wolves is 25.