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Jeff Sanny, Loyola Marymount University
Dr. Jeff Sanny earned a BS in Physics from Harvey Mudd College in 1974 and a PhD in Solid State Physics from the University of California–Los Angeles in 1980. He joined the faculty at Loyola Marymount University in the fall of 1980. During his tenure, he has served as department Chair as well as Associate Dean. Dr. Sanny enjoys teaching introductory physics in particular. He is also passionate about providing students with research experience and has directed an active undergraduate student research group in space physics for many years.

Bill Moebs, PhD
Dr. William Moebs earned a BS and PhD (1959 and 1965) from the University of Michigan. He then joined their staff as a Research Associate for one year, where he continued his doctoral research in particle physics. In 1966, he accepted an appointment to the Physics Department of Indiana Purdue Fort Wayne (IPFW), where he served as Department Chair from 1971 to 1979. In 1979, he moved to Loyola Marymount University (LMU), where he served as Chair of the Physics Department from 1979 to 1986. He retired from LMU in 2000. He has published research in particle physics, chemical kinetics, cell division, atomic physics, and physics teaching.

Contributing authors

David Anderson, Albion College
Daniel Bowman, Ferrum College
Dedra Demaree, Georgetown University
Gerald Friedman, Santa Fe Community College
Lev Gasparov, University of North Florida
Edw. S. Ginsberg, University of Massachusetts
Alice Kolakowska, University of Memphis
Lee LaRue, Paris Junior College
Mark Lattery, University of Wisconsin
Richard Ludlow, Daniel Webster College
Patrick Motl, Indiana University–Kokomo
Tao Pang, University of Nevada–Las Vegas
Kenneth Podolak, Plattsburgh State University
Takashi Sato, Kwantlen Polytechnic University
David Smith, University of the Virgin Islands
Joseph Trout, Richard Stockton College
Kevin Wheelock, Bellevue College


Salameh Ahmad, Rochester Institute of Technology–Dubai
John Aiken, University of Colorado–Boulder
Anand Batra, Howard University
Raymond Benge, Terrant County College
Gavin Buxton, Robert Morris University
Erik Christensen, South Florida State College
Clifton Clark, Fort Hays State University
Nelson Coates, California Maritime Academy
Herve Collin, Kapi’olani Community College
Carl Covatto, Arizona State University
Alexander Cozzani, Imperial Valley College
Danielle Dalafave, The College of New Jersey
Nicholas Darnton, Georgia Institute of Technology
Robert Edmonds, Tarrant County College
William Falls, Erie Community College
Stanley Forrester, Broward College
Umesh Garg, University of Notre Dame
Maurizio Giannotti, Barry University
Bryan Gibbs, Dallas County Community College
Mark Giroux, East Tennessee State University
Matthew Griffiths, University of New Haven
Alfonso Hinojosa, University of Texas–Arlington
Steuard Jensen, Alma College
David Kagan, University of Massachusetts
Jill Leggett, Florida State College–Jacksonville
Sergei Katsev, University of Minnesota–Duluth
Alfredo Louro, University of Calgary
James Maclaren, Tulane University
Ponn Maheswaranathan, Winthrop University
Seth Major, Hamilton College
Oleg Maksimov, Excelsior College
Aristides Marcano, Delaware State University
Marles McCurdy, Tarrant County College
James McDonald, University of Hartford
Ralph McGrew, SUNY–Broome Community College
Paul Miller, West Virginia University
Tamar More, University of Portland
Farzaneh Najmabadi, University of Phoenix
Richard Olenick, The University of Dallas
Christopher Porter, Ohio State University
Liza Pujji, Manakau Institute of Technology
Baishali Ray, Young Harris University
Andrew Robinson, Carleton University
Aruvana Roy, Young Harris University
Abhijit Sarkar, The Catholic University of America
Gajendra Tulsian, Daytona State College
Adria Updike, Roger Williams University
Clark Vangilder, Central Arizona University
Steven Wolf, Texas State University
Alexander Wurm, Western New England University
Lei Zhang, Winston Salem State University
Ulrich Zurcher, Cleveland State University

Questions & Answers

At time to = 0 the current to the DC motor is reverse, resulting in angular displacement of the motor shafts given by angle = (198rad/s)t - (24rad/s^2)t^2 - (2rad/s^3)t^3 At what time is the angular velocity of the motor shaft zero
Princston Reply
what is angular velocity
In three experiments, three different horizontal forces are ap- plied to the same block lying on the same countertop. The force magnitudes are F1 " 12 N, F2 " 8 N, and F3 " 4 N. In each experi- ment, the block remains stationary in spite of the applied force. Rank the forces according to (a) the
state Hooke's law of elasticity
Aarti Reply
Hooke's law states that the extension produced is directly proportional to the applied force provided that the elastic limit is not exceeded. F=ke;
You are welcome
what is drag force
A backward acting force that tends to resist thrust
solve:A person who weighs 720N in air is lowered in to tank of water to about chin level .He sits in a harness of negligible mass suspended from a scale that reads his apparent weight .He then dumps himself under water submerging his body .If his weight while submerged is 34.3N. find his density
Ian Reply
please help me solve this 👆👆👆
The weight inside the tank is lesser due to the buoyancy force by the water displaced. Weight of water displaced = His weight outside - his weight inside tank = 720 - 34.3 = 685.7N Now, the density of water = 997kg/m³ (this is a known value) Volume of water displaced = Mass/Density (next com)
density or relative density
Upthrust =720-34.3=685.7N mass of water displayed = 685.7/g vol of water displayed = 685.7/g/997 hence, density of man = 720/g / (685.7/g/997) =1046.6 kg/m3
R.d=weight in air/upthrust in water =720/34.3=20.99 R.d=density of substance/density of water 20.99=x/1 x=20.99g/cm^3
Kg /cubic meters
how please
Upthrust = 720-34.3=685.7N vol of water = 685.7/g/density of water = 685.7/g/997 so density of man = 720/g /(685.7/g/997) =1046.8 kg/m3
is there anyway i can see your calculations
Upthrust =720-34.3=685.7
Upthrust 720-34.3
Vol of water = 685.7/g/997
Hence density of man = 720/g / (685.7/g/997)
=1046.8 kg/m3
so the density of water is 997
Okay, thanks
try finding the volume then
Vol of man = vol of water displayed
I've done that; I got 0.0687m^3
okay i got it thanks
u welcome
HELLO kindly assist me on this...(MATHS) show that the function f(x)=[0 for xor=0]is continuous from the right of x->0 but not from the left of x->0
Duncan Reply
I do not get the question can you make it clearer
Same here, the function looks very ambiguous. please restate the question properly.
please help me solve this problem.a hiker begins a trip by first walking 25kmSE from her car.she stops and sets her tent for the night . on the second day, she walks 40km in a direction 60°NorthofEast,at which she discovers a forest ranger's tower.find components of hiker's displacement for each day
Liteboho Reply
Take a paper. put a point (name is A), now draw a line in the South east direction from A. Assume the line is 25 km long. that is the first stop (name the second point B) From B, turn 60 degrees to the north of East and draw another line, name that C. that line is 40 km long. (contd.)
Now, you know how to calculate displacements, I hope? the displacement between two points is the shortest distance between the two points. go ahead and do the calculations necessary. Good luck!
thank you so much Sharath Kumar
thank you, have also learned alot
No issues at all. I love the subject and teaching it is fun. Cheers!
cheers too
hii too
you mean
solution problems
what is the definition of model
matthew Reply
please is there any way that i can understand physics very well i know am not support to ask this kind of question....
prove using vector algebra that the diagonals of a rhombus perpendicular to each other.
Baijnath Reply
A projectile is thrown with a speed of v at an angle of theta has a range of R on the surface of the earth. For same v and theta,it's range on the surface of moon will be
Roshani Reply
what is soln..
Using some kinematics, time taken for the projectile to reach ground is (2*v*g*Sin (∆)) (here, g is gravity on Earth and ∆ is theta) therefore, on Earth, R = 2*v²*g*Sin(∆)*Cos(∆) on moon, the only difference is the gravity. Gravity on moon = 0.166*g substituting that value in R, we get the new R
Some corrections to my old post. Time taken to reach ground = 2*v*Sin (∆)/g R = (2*v²*Sin(∆)*Cos(∆))/g I put the g in the numerator by mistake in my old post. apologies for that. R on moon = (R on Earth)/(0.166)
state Newton's first law of motion
Awal Reply
Every body will continue in it's state of rest or of uniform motion in a straight line, unless it is compelled to change that state by an external force.
if you want this to become intuitive to you then you should state it
changing the state of rest or uniform motion of a body
if a body is in rest or motion it is always rest or motion, upto external force appied on it. it explains inertia
what is a vector
a ship move due north at 100kmhr----1 on a River flowing be due east on at 25kmperhr. cal the magnitude of the resultant velocity of the ship.
Emmanuel Reply
The result is a simple vector addition. The angle between the vectors is 90 degrees, so we can use Pythagoras theorem to get the result. V magnitude = sqrt(100*100 + 25*25) = 103.077 km/hr. the direction of the resultant vector can be found using trigonometry. Tan (theta) = 25/100.
state Newton's first law of motion
Kansiime Reply
An object continues to be in its state of rest or motion unless compelled by some external force
First law (law of inertia)- If a body is at rest, it would remain at rest and if the body is in the motion, it would be moving with the same velocity until or unless no external force is applied on it. If force F^=0 acceleration a^=0 or v^=0 or constant.
how would you measure displacement in your car?
Grace Reply
what is constellation
Charles Reply
The product of a. (vector b× vector a)
Umesh Reply
I want to join the conversation
Kumaga Reply
Two charges 1uc and 3uc are separated 4m apart. find the point on the line connecting them at which their electric field intensity balances each other

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