<< Chapter < Page Chapter >> Page >

The concept of a radioactive decay chain is important in this determination. In the case of 238 U, it decays over many steps to 206 Pb. In the process, it goes through 234m Pa, 234 Pa, and 234 Th. These three isotopes have detectable gamma emissions that are capable of being used quantitatively. As can be seen in [link] , the half-life of these three emitters is much less than the half-life of 238 U. As a result, these should exist in secular equilibrium with 238 U. Given this, the ratio of activity of 238 U to each daughter products should be 1:1. They can thus be used as a surrogate for measuring 238 U decay directly via gamma spectroscopy. The total activity of the 238 U can be determined by [link] , where A is the total activity of 238 U, R is the count rate of the given daughter isotope, and B is the probability of decay via that mode. The count rate may need to be corrected for self-absorption of the sample is particularly thick. It may also need to be corrected for detector efficiency if the instrument does not have some sort of internal calibration.

Half-lives of pertinent radioisotopes in the 238 U decay chain
Isotope Half-life
238 U 4.5 x 10 9 years
234 Th 24.1 days
234m Pa 1.17 minutes

A gamma spectrum of a sample is obtained. The 63.29 keV photopeak associated with 234 Th was found to have a count rate of 5.980 kBq. What is the total activity of 238 U present in the sample?

234 Th exists in secular equilibrium with 238 U. The total activity of 234 Th must be equal to the activity of the 238 U. First, the observed activity must be converted to the total activity using Equation A=R/B. It is known that the emission probability for the 63.29 kEv gamma-ray for 234 Th is 4.84%. Therefore, the total activity of 238 U in the sample is 123.6 kBq.

Got questions? Get instant answers now!

The count rate of 235 U can be observed directly with gamma spectroscopy. This can be converted, as was done in the case of 238 U above, to the total activity of 235 U present in the sample. Given that the natural abundances of 238 U and 235 U are known, the ratio of the expected activity of 238 U to 235 U can be calculated to be 21.72 : 1. If the calculated ratio of disintegration rates varies significantly from this expected value, then the sample can be determined to be depleted or enriched.

As shown above, the activity of 238 U in a sample was calculated to be 123.6 kBq. If the gamma spectrum of this sample shows a count rate 23.73 kBq at the 185.72 keV photopeak for 235 U, can this sample be considered enriched uranium? The emission probability for this photopeak is 57.2%.

As shown in the example above, the count rate can be converted to a total activity for 235 U. This yields a total activity of 41.49 kBq for 235 U. The ratio of activities of 238 U and 235 U can be calculated to be 2.979. This is lower than the expected ratio of 21.72, indicating that the 235 U content of the sample greater than the natural abundance of 235 U.

Got questions? Get instant answers now!

This type of calculation is not unique to 238 U. It can be used in any circumstance where the ratio of two isotopes needs to be compared so long as the isotope itself or a daughter product it is in secular equilibrium with has a usable gamma-ray photopeak.

Determination of the age of highly-enriched uranium

Particularly in the investigation of trafficked radioactive materials, particularly fissile materials, it is of interest to determine how long it has been since the sample was enriched. This can help provide an idea of the source of the fissile material—if it was enriched for the purpose of trade or if it was from cold war era enrichment, etc.

When uranium is enriched, 235 U is concentrated in the enriched sample by removing it from natural uranium. This process will separate the uranium from its daughter products that it was in secular equilibrium with. In addition, when 235 U is concentrated in the sample, 234 U is also concentrated due to the particulars of the enrichment process. The 234 U that ends up in the enriched sample will decay through several intermediates to 214 Bi. By comparing the activities of 234 U and 214 Bi or 226 Ra, the age of the sample can be determined.

In [link] , A Bi is the activity of 214 Bi, A Ra is the activity of 226 Ra, A U is the activity of 234 U, λ Th is the decay constant for 230 Th, λ Ra is the decay constant for 226 Ra, and T is the age of the sample. This is a simplified form of a more complicated equation that holds true over all practical sample ages (on the order of years) due to the very long half-lives of the isotopes in question. The results of this can be graphically plotted as they are in [link] .

Ratio of 226 Ra/ 234 U (= 214 Bi/ 234 U) plotted versus age based on [link] . This can be used to determine how long ago a sample was enriched based on the activities of 234 U and 226 Ra or 214 Bi in the sample.

Exercise : The gamma spectrum for a sample is obtained. The count rate of the 121 keV 234 U photopeak is 4500 counts per second and the associated emission probability is 0.0342%. The count rate of the 609.3 keV 214 Bi photopeak is 5.83 counts per second and the emission probability is 46.1%. How old is the sample?

Solution : The observed count rates can be converted to the total activities for each radionuclide. Doing so yields a total activity for 234 U of 4386 kBq and a total activity for 214 Bi of 12.65 Bq. This gives a ratio of 9.614 x 10 -7 . Using [link] , as graphed this indicates that the sample must have been enriched 22.0 years prior to analysis.

Got questions? Get instant answers now!


  • G. Choppin, J.-O. Liljenzin, and J. Rydberg. Radiochemistry and Nuclear Chemistry, Elsevier Press, Oxford (2006).
  • W. Loveland, D. J. Morrissey, and G. T. Seaborg. Modern Nuclear Chemistry, Wiley, New Jersey (2006).
  • K. Mayer, M. Wallenius, and I. Ray. Analyst , 2005, 130 , 433.
  • J. T. Mihalczo, J. A. Mullens, J. K. Mattingly, and T. E. Valentine. Nucl. Instrum. Meth. A , 2000, 450 , 531.
  • J. T. Mihalczo, J. K. Mattingly, J. S. Neal, and J. A. Mullens, Nucl. Instrum. Meth. B , 2004, 213 , 378.
  • K. J. Moody, I. A. Hutcheon, and P. M. Grant. Nuclear Forensic Analysis , CRC Press, Boca Raton (2005).
  • C. T. Nguyen. Nucl. Instrum. Meth. B, 2005, 229 , 103.
  • C. T. Nguyen, and J. Zsigrai. Nucl. Instrum. Meth. B, 2006, 246 , 417.
  • D. Reilly, N. Ensslin, and H. Smith, Jr. Passive Nondestructive Assay of Nuclear Materials , National Technical Information Service, Springfield, VA (1991).
  • M. Wallenius, A. Morgenstern, C. Apostolidis, and K. Mayer. Anal. Bioanal. Chem., 2002 , 374 , 379.

Questions & Answers

Application of nanotechnology in medicine
what is variations in raman spectra for nanomaterials
Jyoti Reply
I only see partial conversation and what's the question here!
Crow Reply
what about nanotechnology for water purification
RAW Reply
please someone correct me if I'm wrong but I think one can use nanoparticles, specially silver nanoparticles for water treatment.
yes that's correct
I think
what is the stm
Brian Reply
is there industrial application of fullrenes. What is the method to prepare fullrene on large scale.?
industrial application...? mmm I think on the medical side as drug carrier, but you should go deeper on your research, I may be wrong
How we are making nano material?
what is a peer
What is meant by 'nano scale'?
What is STMs full form?
scanning tunneling microscope
how nano science is used for hydrophobicity
Do u think that Graphene and Fullrene fiber can be used to make Air Plane body structure the lightest and strongest. Rafiq
what is differents between GO and RGO?
what is simplest way to understand the applications of nano robots used to detect the cancer affected cell of human body.? How this robot is carried to required site of body cell.? what will be the carrier material and how can be detected that correct delivery of drug is done Rafiq
analytical skills graphene is prepared to kill any type viruses .
what is Nano technology ?
Bob Reply
write examples of Nano molecule?
The nanotechnology is as new science, to scale nanometric
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Is there any normative that regulates the use of silver nanoparticles?
Damian Reply
what king of growth are you checking .?
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
Stoney Reply
why we need to study biomolecules, molecular biology in nanotechnology?
Adin Reply
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
what school?
biomolecules are e building blocks of every organics and inorganic materials.
anyone know any internet site where one can find nanotechnology papers?
Damian Reply
sciencedirect big data base
Introduction about quantum dots in nanotechnology
Praveena Reply
what does nano mean?
Anassong Reply
nano basically means 10^(-9). nanometer is a unit to measure length.
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
Privacy Information Security Software Version 1.1a
advantages of NAA
Sai Reply
how I can reaction of mercury?
Sham Reply

Get the best Physical methods in ch... course in your pocket!

Source:  OpenStax, Physical methods in chemistry and nano science. OpenStax CNX. May 05, 2015 Download for free at http://legacy.cnx.org/content/col10699/1.21
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Physical methods in chemistry and nano science' conversation and receive update notifications?