<< Chapter < Page Chapter >> Page >

Refraction at a convex surface

Consider a point source of light at point P in front of a convex surface made of glass (see [link] ). Let R be the radius of curvature, n 1 be the refractive index of the medium in which object point P is located, and n 2 be the refractive index of the medium with the spherical surface. We want to know what happens as a result of refraction at this interface.

Figure shows a section of a sphere. The refractive index of air is n subscript 1 and that of the sphere is n subscript 2. Centre of the sphere is C and radius is R. A ray originating from point P on the optical axis outside the sphere strikes the convex surface of the sphere and is refracted within it. It intersects the axis at point P prime within the sphere, on the other side of the center. A dotted line labeled normal to interface connects the center of the sphere to the point of incidence. It makes an angle phi with the optical axis. The incident and refracted rays make angles alpha and beta respectively with the optical axis and angles theta 1 and theta 2 respectively with the normal to interface.
Refraction at a convex surface ( n 2 > n 1 ) .

Because of the symmetry involved, it is sufficient to examine rays in only one plane. The figure shows a ray of light that starts at the object point P , refracts at the interface, and goes through the image point P . We derive a formula relating the object distance d o , the image distance d i , and the radius of curvature R .

Applying Snell’s law to the ray emanating from point P gives n 1 sin θ 1 = n 2 sin θ 2 . We work in the small-angle approximation, so sin θ θ and Snell’s law then takes the form

n 1 θ 1 n 2 θ 2 .

From the geometry of the figure, we see that

θ 1 = α + ϕ , θ 2 = ϕ β .

Inserting these expressions into Snell’s law gives

n 1 ( α + ϕ ) n 2 ( ϕ β ) .

Using the diagram, we calculate the tangent of the angles α , β , and ϕ :

tan α h d o , tan β h d i , tan ϕ h R .

Again using the small-angle approximation, we find that tan θ θ , so the above relationships become

α h d o , β h d i , ϕ h R .

Putting these angles into Snell’s law gives

n 1 ( h d o + h R ) = n 2 ( h R h d i ) .

We can write this more conveniently as

n 1 d o + n 2 d i = n 2 n 1 R .

If the object is placed at a special point called the first focus , or the object focus F 1 , then the image is formed at infinity, as shown in part (a) of [link] .

Figure a shows a section of a sphere and a point F1 outside it, on the optical axis. Rays originating from F1 strike the convex surface and are refracted within the sphere as parallel rays. The distance of F1 from the surface is f subscript 1. Figure b shows rays parallel to the optical axis striking the convex surface and being refracted. They converge at point F2 within the sphere. F2 lies on the optical axis between the surface and the center of the sphere. The distance of F2 from the surface is f subscript 2. In both figures the refractive index of air is n1 and that of the sphere is n2 greater than n1.
(a) First focus (called the “object focus”) for refraction at a convex surface. (b) Second focus (called “image focus”) for refraction at a convex surface.

We can find the location f 1 of the first focus F 1 by setting d i = in the preceding equation.

n 1 f 1 + n 2 = n 2 n 1 R
f 1 = n 1 R n 2 n 1

Similarly, we can define a second focus or image focus F 2 where the image is formed for an object that is far away [part (b)]. The location of the second focus F 2 is obtained from [link] by setting d o = :

n 1 + n 2 f 2 = n 2 n 1 R
f 2 = n 2 R n 2 n 1 .

Note that the object focus is at a different distance from the vertex than the image focus because n 1 n 2 .

Sign convention for single refracting surfaces

Although we derived this equation for refraction at a convex surface, the same expression holds for a concave surface, provided we use the following sign convention:

  1. R > 0 if surface is convex toward object; otherwise, R < 0 .
  2. d i > 0 if image is real and on opposite side from the object; otherwise, d i < 0 .

Summary

This section explains how a single refracting interface forms images.

  • When an object is observed through a plane interface between two media, then it appears at an apparent distance h i that differs from the actual distance h o : h i = ( n 2 / n 1 ) h o .
  • An image is formed by the refraction of light at a spherical interface between two media of indices of refraction n 1 and n 2 .
  • Image distance depends on the radius of curvature of the interface, location of the object, and the indices of refraction of the media.

Conceptual questions

Derive the formula for the apparent depth of a fish in a fish tank using Snell’s law.

Got questions? Get instant answers now!

Use a ruler and a protractor to find the image by refraction in the following cases. Assume an air-glass interface. Use a refractive index of 1 for air and of 1.5 for glass. ( Hint : Use Snell’s law at the interface.)

(a) A point object located on the axis of a concave interface located at a point within the focal length from the vertex.

(b) A point object located on the axis of a concave interface located at a point farther than the focal length from the vertex.

(c) A point object located on the axis of a convex interface located at a point within the focal length from the vertex.

(d) A point object located on the axis of a convex interface located at a point farther than the focal length from the vertex.

(e) Repeat (a)–(d) for a point object off the axis.

answers may vary

Got questions? Get instant answers now!

Problems

An object is located in air 30 cm from the vertex of a concave surface made of glass with a radius of curvature 10 cm. Where does the image by refraction form and what is its magnification? Use n air = 1 and n glass = 1.5 .

Got questions? Get instant answers now!

An object is located in air 30 cm from the vertex of a convex surface made of glass with a radius of curvature 80 cm. Where does the image by refraction form and what is its magnification?

d i = −55 cm ; m = + 1.8

Got questions? Get instant answers now!

An object is located in water 15 cm from the vertex of a concave surface made of glass with a radius of curvature 10 cm. Where does the image by refraction form and what is its magnification? Use n water = 4 / 3 and n glass = 1.5 .

Got questions? Get instant answers now!

An object is located in water 30 cm from the vertex of a convex surface made of Plexiglas with a radius of curvature of 80 cm. Where does the image form by refraction and what is its magnification? n water = 4 / 3 and n Plexiglas = 1.65 .

d i = −41 cm, m = 1.4

Got questions? Get instant answers now!

An object is located in air 5 cm from the vertex of a concave surface made of glass with a radius of curvature 20 cm. Where does the image form by refraction and what is its magnification? Use n air = 1 and n glass = 1.5 .

Got questions? Get instant answers now!

Derive the spherical interface equation for refraction at a concave surface. ( Hint : Follow the derivation in the text for the convex surface.)

proof

Got questions? Get instant answers now!

Questions & Answers

how does Neisseria cause meningitis
Nyibol Reply
what is microbiologist
Muhammad Reply
what is errata
Muhammad
is the branch of biology that deals with the study of microorganisms.
Ntefuni Reply
What is microbiology
Mercy Reply
studies of microbes
Louisiaste
when we takee the specimen which lumbar,spin,
Ziyad Reply
How bacteria create energy to survive?
Muhamad Reply
Bacteria doesn't produce energy they are dependent upon their substrate in case of lack of nutrients they are able to make spores which helps them to sustain in harsh environments
_Adnan
But not all bacteria make spores, l mean Eukaryotic cells have Mitochondria which acts as powerhouse for them, since bacteria don't have it, what is the substitution for it?
Muhamad
they make spores
Louisiaste
what is sporadic nd endemic, epidemic
Aminu Reply
the significance of food webs for disease transmission
Abreham
food webs brings about an infection as an individual depends on number of diseased foods or carriers dully.
Mark
explain assimilatory nitrate reduction
Esinniobiwa Reply
Assimilatory nitrate reduction is a process that occurs in some microorganisms, such as bacteria and archaea, in which nitrate (NO3-) is reduced to nitrite (NO2-), and then further reduced to ammonia (NH3).
Elkana
This process is called assimilatory nitrate reduction because the nitrogen that is produced is incorporated in the cells of microorganisms where it can be used in the synthesis of amino acids and other nitrogen products
Elkana
Examples of thermophilic organisms
Shu Reply
Give Examples of thermophilic organisms
Shu
advantages of normal Flora to the host
Micheal Reply
Prevent foreign microbes to the host
Abubakar
they provide healthier benefits to their hosts
ayesha
They are friends to host only when Host immune system is strong and become enemies when the host immune system is weakened . very bad relationship!
Mark
what is cell
faisal Reply
cell is the smallest unit of life
Fauziya
cell is the smallest unit of life
Akanni
ok
Innocent
cell is the structural and functional unit of life
Hasan
is the fundamental units of Life
Musa
what are emergency diseases
Micheal Reply
There are nothing like emergency disease but there are some common medical emergency which can occur simultaneously like Bleeding,heart attack,Breathing difficulties,severe pain heart stock.Hope you will get my point .Have a nice day ❣️
_Adnan
define infection ,prevention and control
Innocent
I think infection prevention and control is the avoidance of all things we do that gives out break of infections and promotion of health practices that promote life
Lubega
Heyy Lubega hussein where are u from?
_Adnan
en français
Adama
which site have a normal flora
ESTHER Reply
Many sites of the body have it Skin Nasal cavity Oral cavity Gastro intestinal tract
Safaa
skin
Asiina
skin,Oral,Nasal,GIt
Sadik
How can Commensal can Bacteria change into pathogen?
Sadik
How can Commensal Bacteria change into pathogen?
Sadik
all
Tesfaye
by fussion
Asiina
what are the advantages of normal Flora to the host
Micheal
what are the ways of control and prevention of nosocomial infection in the hospital
Micheal
what is inflammation
Shelly Reply
part of a tissue or an organ being wounded or bruised.
Wilfred
what term is used to name and classify microorganisms?
Micheal Reply
Binomial nomenclature
adeolu
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 3

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'University physics volume 3' conversation and receive update notifications?

Ask