<< Chapter < Page Chapter >> Page >
By the end of this section, you will be able to:
  • Use the concepts of vibrational and rotational energy to describe energy transitions in a diatomic molecule
  • Explain key features of a vibrational-rotational energy spectrum of a diatomic molecule
  • Estimate allowed energies of a rotating molecule
  • Determine the equilibrium separation distance between atoms in a diatomic molecule from the vibrational-rotational absorption spectrum

Molecular energy levels are more complicated than atomic energy levels because molecules can also vibrate and rotate. The energies associated with such motions lie in different ranges and can therefore be studied separately. Electronic transitions are of order 1 eV, vibrational transitions are of order 10 −2 eV , and rotational transitions are of order 10 −3 eV . For complex molecules, these energy changes are difficult to characterize, so we begin with the simple case of a diatomic molecule.

According to classical mechanics, the energy of rotation of a diatomic molecule is given by

E r = L 2 2 I ,

where I is the moment of inertia and L is the angular momentum. According to quantum mechanics, the rotational angular momentum is quantized:

L = l ( l + 1 ) ( l = 0 , 1 , 2 , 3 ,... ) ,

where l is the orbital angular quantum number. The allowed rotational energy level    of a diatomic molecule is therefore

E r = l ( l + 1 ) 2 2 I = l ( l + 1 ) E 0 r ( l = 0 , 1 , 2 , 3 ,... ) ,

where the characteristic rotational energy of a molecule is defined as

E 0 r = 2 2 I .

For a diatomic molecule, the moment of inertia with reduced mass μ is

I = μ r 0 2 ,

where r 0 is the total distance between the atoms. The energy difference between rotational levels is therefore

Δ E r = E l + 1 E l = 2 ( l + 1 ) E 0 r .

A detailed study of transitions between rotational energy levels brought about by the absorption or emission of radiation (a so-called electric dipole transition    ) requires that

Δ l = ± 1 .

This rule, known as a selection rule    , limits the possible transitions from one quantum state to another. [link] is the selection rule for rotational energy transitions. It applies only to diatomic molecules that have an electric dipole moment. For this reason, symmetric molecules such as H 2 and N 2 do not experience rotational energy transitions due to the absorption or emission of electromagnetic radiation.

The rotational energy of hcl

Determine the lowest three rotational energy levels of a hydrogen chloride (HCl) molecule.

Strategy

Hydrogen chloride (HCl) is a diatomic molecule with an equilibrium separation distance of 0.127 nm. Rotational energy levels depend only on the momentum of inertia I and the orbital angular momentum quantum number l (in this case, l = 0 , 1, and 2). The momentum of inertia depends, in turn, on the equilibrium separation distance (which is given) and the reduced mass, which depends on the masses of the H and Cl atoms.

Solution

First, we compute the reduced mass. If Particle 1 is hydrogen and Particle 2 is chloride, we have

μ = m 1 m 2 m 1 + m 2 = ( 1.0 u ) ( 35.4 u ) 1.0 u + 35.4 u = 0.97 u = 0.97 u ( 931.5 MeV c 2 1 u ) = 906 MeV c 2 .

The corresponding rest mass energy is therefore

μ c 2 = 9.06 × 10 8 eV .

This allows us to calculate the characteristic energy:

E 0 r = 2 2 I = 2 2 ( μ r 0 2 ) = ( c ) 2 2 ( μ c 2 ) r 0 2 = ( 197.3 eV · nm ) 2 2 ( 9.06 × 10 8 eV ) ( 0.127 nm ) 2 = 1.33 × 10 −3 eV .

(Notice how this expression is written in terms of the rest mass energy. This technique is common in modern physics calculations.) The rotational energy levels are given by

E r = l ( l + 1 ) 2 2 I = l ( l + 1 ) E 0 r ,

where l is the orbital quantum number. The three lowest rotational energy levels of an HCl molecule are therefore

l = 0 ; E r = 0 eV ( no rotation ) ,
l = 1 ; E r = 2 E 0 r = 2.66 × 10 −3 eV ,
l = 2 ; E r = 6 E 0 r = 7.99 × 10 −3 eV .

Significance

The rotational spectrum is associated with weak transitions (1/1000 to 1/100 of an eV). By comparison, the energy of an electron in the ground state of hydrogen is −13.6 eV .

Got questions? Get instant answers now!

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
khuthadzo hii
Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
please help me with vectors in two dimensions
Mulaudzi Reply
how to calculate normal force
Mulaudzi
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 4

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'University physics volume 3' conversation and receive update notifications?

Ask