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The ion Li 2+ makes an atomic transition from an n = 4 state to an n = 2 state. (a) What is the energy of the photon emitted during the transition? (b) What is the wavelength of the photon?

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The red light emitted by a ruby laser has a wavelength of 694.3 nm. What is the difference in energy between the initial state and final state corresponding to the emission of the light?

The wavelength of the laser is given by:
λ = h c Δ E ,
where E γ is the energy of the photon and Δ E is the magnitude of the energy difference. Solving for the latter, we get:
Δ E = −2.795 eV .
The negative sign indicates that the electron lost energy in the transition.

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The yellow light from a sodium-vapor street lamp is produced by a transition of sodium atoms from a 3 p state to a 3s state. If the difference in energies of those two states is 2.10 eV, what is the wavelength of the yellow light?

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Estimate the wavelength of the K α X-ray from calcium.

Δ E L K ( Z 1 ) 2 ( 10.2 eV ) = 3.68 × 10 3 eV .

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Estimate the frequency of the K α X-ray from cesium.

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X-rays are produced by striking a target with a beam of electrons. Prior to striking the target, the electrons are accelerated by an electric field through a potential energy difference:

Δ U = e Δ V ,

where e is the charge of an electron and Δ V is the voltage difference. If Δ V = 15,000 volts, what is the minimum wavelength of the emitted radiation?

According to the conservation of the energy, the potential energy of the electron is converted completely into kinetic energy. The initial kinetic energy of the electron is zero (the electron begins at rest). So, the kinetic energy of the electron just before it strikes the target is:
K = e Δ V .
If all of this energy is converted into braking radiation, the frequency of the emitted radiation is a maximum, therefore:
f max = e Δ V h .
When the emitted frequency is a maximum, then the emitted wavelength is a minimum, so:
λ min = 0.1293 nm .

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For the preceding problem, what happens to the minimum wavelength if the voltage across the X-ray tube is doubled?

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Suppose the experiment in the preceding problem is conducted with muons. What happens to the minimum wavelength?

A muon is 200 times heavier than an electron, but the minimum wavelength does not depend on mass, so the result is unchanged.

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An X-ray tube accelerates an electron with an applied voltage of 50 kV toward a metal target. (a) What is the shortest-wavelength X-ray radiation generated at the target? (b) Calculate the photon energy in eV. (c) Explain the relationship of the photon energy to the applied voltage.

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A color television tube generates some X-rays when its electron beam strikes the screen. What is the shortest wavelength of these X-rays, if a 30.0-kV potential is used to accelerate the electrons? (Note that TVs have shielding to prevent these X-rays from exposing viewers.)

4.13 × 10 −11 m

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An X-ray tube has an applied voltage of 100 kV. (a) What is the most energetic X-ray photon it can produce? Express your answer in electron volts and joules. (b) Find the wavelength of such an X-ray.

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The maximum characteristic X-ray photon energy comes from the capture of a free electron into a K shell vacancy. What is this photon energy in keV for tungsten, assuming that the free electron has no initial kinetic energy?

72.5 keV

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What are the approximate energies of the K α and K β X-rays for copper?

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Compare the X-ray photon wavelengths for copper and gold.

The atomic numbers for Cu and Au are Z = 29 and 79, respectively. The X-ray photon frequency for gold is greater than copper by a factor:
( f Au f Cu ) 2 = ( 79 1 29 1 ) 2 8 .
Therefore, the X-ray wavelength of Au is about eight times shorter than for copper.

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The approximate energies of the K α and K β X-rays for copper are E K α = 8.00 keV and E K β = 9.48 keV, respectively. Determine the ratio of X-ray frequencies of gold to copper, then use this value to estimate the corresponding energies of K α and K β X-rays for gold.

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Practice Key Terms 5

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Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
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