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Additional problems

A vector field E (not necessarily an electric field; note units) is given by E = 3 x 2 k ^ . Calculate S E · n ^ d a , where S is the area shown below. Assume that n ^ = k ^ .

A square S with length of each side equal to a is shown in the xy plane.
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Repeat the preceding problem, with E = 2 x i ^ + 3 x 2 k ^ .

E · n ^ d A = a 4

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A circular area S is concentric with the origin, has radius a , and lies in the yz -plane. Calculate S E · n ^ d A for E = 3 z 2 i ^ .

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(a) Calculate the electric flux through the open hemispherical surface due to the electric field E = E 0 k ^ (see below). (b) If the hemisphere is rotated by 90 ° around the x -axis, what is the flux through it?

A hemisphere with radius R is shown with its base in the xy plane and center of base at the origin. An arrow is shown beside it, labeled vector E equal to E0 k hat.

a. E · n ^ d A = E 0 r 2 π ; b. zero, since the flux through the upper half cancels the flux through the lower half of the sphere

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Suppose that the electric field of an isolated point charge were proportional to 1 / r 2 + σ rather than 1 / r 2 . Determine the flux that passes through the surface of a sphere of radius R centered at the charge. Would Gauss’s law remain valid?

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The electric field in a region is given by E = a / ( b + c x ) i ^ , where a = 200 N · m/C, b = 2.0 m, and c = 2.0 . What is the net charge enclosed by the shaded volume shown below?

Figure shows a cuboid with one corner on the origin of the coordinate axes. Its length along the x axis is 2 m, along y axis is 1.5 m and along z axis is 1 m. An arrow outside the cuboid points along the x axis. It is labeled vector E.

Φ = q enc ε 0 ; There are two contributions to the surface integral: one at the side of the rectangle at x = 0 and the other at the side at x = 2.0 m ;
E ( 0 ) [ 1.5 m 2 ] + E ( 2.0 m ) [ 1.5 m 2 ] = q enc ε 0 = −100 Nm 2 / C
where the minus sign indicates that at x = 0 , the electric field is along positive x and the unit normal is along negative x . At x = 2 , the unit normal and the electric field vector are in the same direction: q enc = ε 0 Φ = −8.85 × 10 −10 C .

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Two equal and opposite charges of magnitude Q are located on the x -axis at the points + a and – a , as shown below. What is the net flux due to these charges through a square surface of side 2 a that lies in the yz -plane and is centered at the origin? ( Hint: Determine the flux due to each charge separately, then use the principle of superposition. You may be able to make a symmetry argument.)

A shaded square is shown in the yz plane with its center at the origin. Its side parallel to z axis is labeled to be of length 2a. A charge labeled plus Q is shown on the positive x axis at a distance a from the origin. A charge labeled minus Q is shown on the negative x axis at a distance a from the origin.
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A fellow student calculated the flux through the square for the system in the preceding problem and got 0. What went wrong?

didn’t keep consistent directions for the area vectors, or the electric fields

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A 10 cm × 10 cm piece of aluminum foil of 0.1 mm thickness has a charge of 20 μ C that spreads on both wide side surfaces evenly. You may ignore the charges on the thin sides of the edges. (a) Find the charge density. (b) Find the electric field 1 cm from the center, assuming approximate planar symmetry.

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Two 10 cm × 10 cm pieces of aluminum foil of thickness 0.1 mm face each other with a separation of 5 mm. One of the foils has a charge of +30 μ C and the other has 30 μ C . (a) Find the charge density at all surfaces, i.e., on those facing each other and those facing away. (b) Find the electric field between the plates near the center assuming planar symmetry.

a. σ = 3.0 × 10 −3 C / m 2 , + 3 × 10 −3 C/m 2 on one and −3 × 10 −3 C/m 2 on the other; b. E = 3.39 × 10 8 N / C

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Two large copper plates facing each other have charge densities ± 4.0 C/m 2 on the surface facing the other plate, and zero in between the plates. Find the electric flux through a 3 cm × 4 cm rectangular area between the plates, as shown below, for the following orientations of the area. (a) If the area is parallel to the plates, and (b) if the area is tilted θ = 30 ° from the parallel direction. Note, this angle can also be θ = 180 ° + 30 ° .

Figure shows two parallel plates and a dotted line exactly between the two, parallel to them. A third plate forms an angle theta with the dotted line.
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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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