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The proportionality to the fourth power of the absolute temperature is a remarkably strong temperature dependence. It allows the detection of even small temperature variations. Images called thermographs can be used medically to detect regions of abnormally high temperature in the body, perhaps indicative of disease. Similar techniques can be used to detect heat leaks in homes ( [link] ), optimize performance of blast furnaces, improve comfort levels in work environments, and even remotely map Earth’s temperature profile.

Figure shows a photograph of a building overlaid by its thermograph. The thermograph shows different areas of the building in different colours. The windows are yellow with red frames.
A thermograph of part of a building shows temperature variations, indicating where heat transfer to the outside is most severe. Windows are a major region of heat transfer to the outside of homes. (credit: US Army)

The Stefan-Boltzmann equation needs only slight refinement to deal with a simple case of an object’s absorption of radiation from its surroundings. Assuming that an object with a temperature T 1 is surrounded by an environment with uniform temperature T 2 , the net rate of heat transfer by radiation    is

P net = σ e A ( T 2 4 T 1 4 ) ,

where e is the emissivity of the object alone. In other words, it does not matter whether the surroundings are white, gray, or black: The balance of radiation into and out of the object depends on how well it emits and absorbs radiation. When T 2 > T 1 , the quantity P net is positive, that is, the net heat transfer is from hot to cold.

Before doing an example, we have a complication to discuss: different emissivities at different wavelengths. If the fraction of incident radiation an object reflects is the same at all visible wavelengths, the object is gray; if the fraction depends on the wavelength, the object has some other color. For instance, a red or reddish object reflects red light more strongly than other visible wavelengths. Because it absorbs less red, it radiates less red when hot. Differential reflection and absorption of wavelengths outside the visible range have no effect on what we see, but they may have physically important effects. Skin is a very good absorber and emitter of infrared radiation, having an emissivity of 0.97 in the infrared spectrum. Thus, in spite of the obvious variations in skin color, we are all nearly black in the infrared. This high infrared emissivity is why we can so easily feel radiation on our skin. It is also the basis for the effectiveness of night-vision scopes used by law enforcement and the military to detect human beings.

Calculating the net heat transfer of a person

What is the rate of heat transfer by radiation of an unclothed person standing in a dark room whose ambient temperature is 22.0 ° C ? The person has a normal skin temperature of 33.0 ° C and a surface area of 1.50 m 2 . The emissivity of skin is 0.97 in the infrared, the part of the spectrum where the radiation takes place.

Strategy

We can solve this by using the equation for the rate of radiative heat transfer.

Solution

Insert the temperature values T 2 = 295 K and T 1 = 306 K , so that

Q t = σ e A ( T 2 4 T 1 4 ) = ( 5.67 × 10 −8 J/s · m 2 · K 4 ) ( 0.97 ) ( 1.50 m 2 ) [ ( 295 K ) 4 ( 306 K ) 4 ] = −99 J/s = −99 W .

Significance

This value is a significant rate of heat transfer to the environment (note the minus sign), considering that a person at rest may produce energy at the rate of 125 W and that conduction and convection are also transferring energy to the environment. Indeed, we would probably expect this person to feel cold. Clothing significantly reduces heat transfer to the environment by all mechanisms, because clothing slows down both conduction and convection, and has a lower emissivity (especially if it is light-colored) than skin.

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Practice Key Terms 9

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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