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Calculating torque on a rigid body

[link] shows several forces acting at different locations and angles on a flywheel. We have | F 1 | = 20 N , | F 2 | = 30 N , | F 3 | = 30 N , and r = 0.5 m . Find the net torque on the flywheel about an axis through the center.

Figure shows a flywheel with three forces acting on it at different locations and angles. Force F3 is applied at the center and is perpendicular to the axis of rotation. Force F2 is applied at the left edge and is perpendicular to the axis of rotation. Force F1 is applied at the center and forms 30 degree angle with the axis of rotation.
Three forces acting on a flywheel.


We calculate each torque individually, using the cross product, and determine the sign of the torque. Then we sum the torques to find the net torque.


We start with F 1 . If we look at [link] , we see that F 1 makes an angle of 90 ° + 60 ° with the radius vector r . Taking the cross product, we see that it is out of the page and so is positive. We also see this from calculating its magnitude:

| τ 1 | = r F 1 sin 150 ° = 0.5 m ( 20 N ) ( 0.5 ) = 5.0 N · m .

Next we look at F 2 . The angle between F 2 and r is 90 ° and the cross product is into the page so the torque is negative. Its value is

| τ 2 | = r F 2 sin 90 ° = −0.5 m ( 30 N ) = −15.0 N · m .

When we evaluate the torque due to F 3 , we see that the angle it makes with r is zero so r × F 3 = 0 . Therefore, F 3 does not produce any torque on the flywheel.

We evaluate the sum of the torques:

τ net = i | τ i | = 5 15 = −10 N · m .


The axis of rotation is at the center of mass of the flywheel. Since the flywheel is on a fixed axis, it is not free to translate. If it were on a frictionless surface and not fixed in place, F 3 would cause the flywheel to translate, as well as F 1 . Its motion would be a combination of translation and rotation.

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Check Your Understanding A large ocean-going ship runs aground near the coastline, similar to the fate of the Costa Concordia , and lies at an angle as shown below. Salvage crews must apply a torque to right the ship in order to float the vessel for transport. A force of 5.0 × 10 5 N acting at point A must be applied to right the ship. What is the torque about the point of contact of the ship with the ground ( [link] )?

Figure shows a ship that lies at an angle on the seashore. A force of 50000 N is applied at 10 degree angle to the normal at a point that 100 meters above the point of contact between the ship and the seashore.
A ship runs aground and tilts, requiring torque to be applied to return the vessel to an upright position.

The angle between the lever arm and the force vector is 80 ° ; therefore, r = 100 m(sin80 ° ) = 98.5 m .

The cross product τ = r × F gives a negative or clockwise torque.

The torque is then τ = r F = −98.5 m ( 5.0 × 10 5 N ) = −4.9 × 10 7 N · m .

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  • The magnitude of a torque about a fixed axis is calculated by finding the lever arm to the point where the force is applied and using the relation | τ | = r F , where r is the perpendicular distance from the axis to the line upon which the force vector lies.
  • The sign of the torque is found using the right hand rule. If the page is the plane containing r and F , then r × F is out of the page for positive torques and into the page for negative torques.
  • The net torque can be found from summing the individual torques about a given axis.

Conceptual questions

What three factors affect the torque created by a force relative to a specific pivot point?

magnitude of the force, length of the lever arm, and angle of the lever arm and force vector

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Give an example in which a small force exerts a large torque. Give another example in which a large force exerts a small torque.

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When reducing the mass of a racing bike, the greatest benefit is realized from reducing the mass of the tires and wheel rims. Why does this allow a racer to achieve greater accelerations than would an identical reduction in the mass of the bicycle’s frame?

The moment of inertia of the wheels is reduced, so a smaller torque is needed to accelerate them.

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Questions & Answers

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He is a physicist who formulated the atomic model of an Atom
And made 3 postulates
Check university physics vol 3 > Nuclear physics
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actually it is apparent change in the frequency of light or sound as object move towards or away.
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what is the formula for frictional force
bassey Reply
I believe, correct me if I am wrong, but Ffr=Fn*mu
frictional force ,mathematically Fforce (Ffr) =K∆R where by K stands for coefficient of friction ,R stands for normal force/reaction NB: R = mass of a body ( m) x Acc.due gravity (g) The formula will hold the meaning if and only if the body is relatively moving with zero angle (∅ = 0°C)
What is concept associated with linear motion
Adeoye Reply
what causes friction?
uneven surfaces cause friction Elijah
rough surfacea
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freezing point depression deals with the particles in the matter(liquid) loosing energy.....while boiling elevation is the particles of the matter(liquid)gaining energy
What is motion
Adeoye Reply
moving place to place
change position with respect to surrounding
to which
to where ?
the phenomenon of an object to changes its position with respect to the reference point with passage of time then it is called as motion
it's just a change in position
reference point -it is a fixed point respect to which can say that a object is at rest or motion
A change in position
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Sadia Reply
what is thrust
Aarti Reply
when an object is immersed in liquid, it experiences an upward force which is called as upthrust.
@Phanindra Thapa No, that is buoyancy that you're talking about...
thrust is simply a push
it is a force that is exerted by liquid.
what is the difference between upthrust and buoyancy?
The force exerted by a liquid is called buoyancy. not thrust. there are many different types of thrust and I think you should Google it instead of asking here.
hey Kumar, don't discourage somebody like that. I think this conversation is all about discussion...remember that the more we discuss the more we know...
thrust is an upward force acting on an object immersed in a liquid.
uptrust and buoyancy are the same
the question isn't asking about up thrust. he simply asked what is thrust
a Thrust is simply a push
the perpendicular force applied on the body
thrust is a force of depression while
what is friction?
while upthrust is a force that act on a body when it is fully or partially submerged in a liquid
mathematically upthrust (u) = Real weight (wr) - Apparent weight (wa) u = wr- wa.
friction is a force which opposes relative motion.
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