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Due to the comprehensive nature of the material, we are offering the book in three volumes for flexibility and efficiency.

Coverage and scope

Our University Physics textbook adheres to the scope and sequence of most two- and three-semester physics courses nationwide. We have worked to make physics interesting and accessible to students while maintaining the mathematical rigor inherent in the subject. With this objective in mind, the content of this textbook has been developed and arranged to provide a logical progression from fundamental to more advanced concepts, building upon what students have already learned and emphasizing connections between topics and between theory and applications. The goal of each section is to enable students not just to recognize concepts, but to work with them in ways that will be useful in later courses and future careers. The organization and pedagogical features were developed and vetted with feedback from science educators dedicated to the project.


Unit 1: Mechanics

  • Chapter 1: Units and Measurement
  • Chapter 2: Vectors
  • Chapter 3: Motion Along a Straight Line
  • Chapter 4: Motion in Two and Three Dimensions
  • Chapter 5: Newton’s Laws of Motion
  • Chapter 6: Applications of Newton’s Laws
  • Chapter 7: Work and Kinetic Energy
  • Chapter 8: Potential Energy and Conservation of Energy
  • Chapter 9: Linear Momentum and Collisions
  • Chapter 10: Fixed-Axis Rotation
  • Chapter 11: Angular Momentum
  • Chapter 12: Static Equilibrium and Elasticity
  • Chapter 13: Gravitation
  • Chapter 14: Fluid Mechanics

Unit 2: Waves and Acoustics

  • Chapter 15: Oscillations
  • Chapter 16: Waves
  • Chapter 17: Sound


Unit 1: Thermodynamics

  • Chapter 1: Temperature and Heat
  • Chapter 2: The Kinetic Theory of Gases
  • Chapter 3: The First Law of Thermodynamics
  • Chapter 4: The Second Law of Thermodynamics

Unit 2: Electricity and Magnetism

  • Chapter 5: Electric Charges and Fields
  • Chapter 6: Gauss’s Law
  • Chapter 7: Electric Potential
  • Chapter 8: Capacitance
  • Chapter 9: Current and Resistance
  • Chapter 10: Direct-Current Circuits
  • Chapter 11: Magnetic Forces and Fields
  • Chapter 12: Sources of Magnetic Fields
  • Chapter 13: Electromagnetic Induction
  • Chapter 14: Inductance
  • Chapter 15: Alternating-Current Circuits
  • Chapter 16: Electromagnetic Waves


Unit 1: Optics

  • Chapter 1: The Nature of Light
  • Chapter 2: Geometric Optics and Image Formation
  • Chapter 3: Interference
  • Chapter 4: Diffraction

Unit 2: Modern Physics

  • Chapter 5: Relativity
  • Chapter 6: Photons and Matter Waves
  • Chapter 7: Quantum Mechanics
  • Chapter 8: Atomic Structure
  • Chapter 9: Condensed Matter Physics
  • Chapter 10: Nuclear Physics
  • Chapter 11: Particle Physics and Cosmology

Pedagogical foundation

Throughout University Physics you will find derivations of concepts that present classical ideas and techniques, as well as modern applications and methods. Most chapters start with observations or experiments that place the material in a context of physical experience. Presentations and explanations rely on years of classroom experience on the part of long-time physics professors, striving for a balance of clarity and rigor that has proven successful with their students. Throughout the text, links enable students to review earlier material and then return to the present discussion, reinforcing connections between topics. Key historical figures and experiments are discussed in the main text (rather than in boxes or sidebars), maintaining a focus on the development of physical intuition. Key ideas, definitions, and equations are highlighted in the text and listed in summary form at the end of each chapter. Examples and chapter-opening images often include contemporary applications from daily life or modern science and engineering that students can relate to, from smart phones to the internet to GPS devices.

Questions & Answers

Given two vectors, vector C which is 3 units, and vector D which is 5 units. If the two vectors form an angle of 45o, determine C D and direction.
At time to = 0 the current to the DC motor is reverse, resulting in angular displacement of the motor shafts given by angle = (198rad/s)t - (24rad/s^2)t^2 - (2rad/s^3)t^3 At what time is the angular velocity of the motor shaft zero
Princston Reply
what is angular velocity
In three experiments, three different horizontal forces are ap- plied to the same block lying on the same countertop. The force magnitudes are F1 " 12 N, F2 " 8 N, and F3 " 4 N. In each experi- ment, the block remains stationary in spite of the applied force. Rank the forces according to (a) the
Given two vectors, vector C which is 3 units, and vector D which is 5 units. If the two vectors form an angle of 45o, determine C D and direction.
CD=5.83 n direction is NE
state Hooke's law of elasticity
Aarti Reply
Hooke's law states that the extension produced is directly proportional to the applied force provided that the elastic limit is not exceeded. F=ke;
You are welcome
what is drag force
A backward acting force that tends to resist thrust
solve:A person who weighs 720N in air is lowered in to tank of water to about chin level .He sits in a harness of negligible mass suspended from a scale that reads his apparent weight .He then dumps himself under water submerging his body .If his weight while submerged is 34.3N. find his density
Ian Reply
please help me solve this 👆👆👆
The weight inside the tank is lesser due to the buoyancy force by the water displaced. Weight of water displaced = His weight outside - his weight inside tank = 720 - 34.3 = 685.7N Now, the density of water = 997kg/m³ (this is a known value) Volume of water displaced = Mass/Density (next com)
density or relative density
Upthrust =720-34.3=685.7N mass of water displayed = 685.7/g vol of water displayed = 685.7/g/997 hence, density of man = 720/g / (685.7/g/997) =1046.6 kg/m3
R.d=weight in air/upthrust in water =720/34.3=20.99 R.d=density of substance/density of water 20.99=x/1 x=20.99g/cm^3
Kg /cubic meters
how please
Upthrust = 720-34.3=685.7N vol of water = 685.7/g/density of water = 685.7/g/997 so density of man = 720/g /(685.7/g/997) =1046.8 kg/m3
is there anyway i can see your calculations
Upthrust =720-34.3=685.7
Upthrust 720-34.3
Vol of water = 685.7/g/997
Hence density of man = 720/g / (685.7/g/997)
=1046.8 kg/m3
so the density of water is 997
Okay, thanks
try finding the volume then
Vol of man = vol of water displayed
I've done that; I got 0.0687m^3
okay i got it thanks
u welcome
HELLO kindly assist me on this...(MATHS) show that the function f(x)=[0 for xor=0]is continuous from the right of x->0 but not from the left of x->0
Duncan Reply
I do not get the question can you make it clearer
Same here, the function looks very ambiguous. please restate the question properly.
please help me solve this problem.a hiker begins a trip by first walking 25kmSE from her car.she stops and sets her tent for the night . on the second day, she walks 40km in a direction 60°NorthofEast,at which she discovers a forest ranger's tower.find components of hiker's displacement for each day
Liteboho Reply
Take a paper. put a point (name is A), now draw a line in the South east direction from A. Assume the line is 25 km long. that is the first stop (name the second point B) From B, turn 60 degrees to the north of East and draw another line, name that C. that line is 40 km long. (contd.)
Now, you know how to calculate displacements, I hope? the displacement between two points is the shortest distance between the two points. go ahead and do the calculations necessary. Good luck!
thank you so much Sharath Kumar
thank you, have also learned alot
No issues at all. I love the subject and teaching it is fun. Cheers!
cheers too
hii too
you mean
solution problems
what is the definition of model
matthew Reply
please is there any way that i can understand physics very well i know am not support to ask this kind of question....
prove using vector algebra that the diagonals of a rhombus perpendicular to each other.
Baijnath Reply
A projectile is thrown with a speed of v at an angle of theta has a range of R on the surface of the earth. For same v and theta,it's range on the surface of moon will be
Roshani Reply
what is soln..
Using some kinematics, time taken for the projectile to reach ground is (2*v*g*Sin (∆)) (here, g is gravity on Earth and ∆ is theta) therefore, on Earth, R = 2*v²*g*Sin(∆)*Cos(∆) on moon, the only difference is the gravity. Gravity on moon = 0.166*g substituting that value in R, we get the new R
Some corrections to my old post. Time taken to reach ground = 2*v*Sin (∆)/g R = (2*v²*Sin(∆)*Cos(∆))/g I put the g in the numerator by mistake in my old post. apologies for that. R on moon = (R on Earth)/(0.166)
state Newton's first law of motion
Awal Reply
Every body will continue in it's state of rest or of uniform motion in a straight line, unless it is compelled to change that state by an external force.
if you want this to become intuitive to you then you should state it
changing the state of rest or uniform motion of a body
if a body is in rest or motion it is always rest or motion, upto external force appied on it. it explains inertia
what is a vector
a ship move due north at 100kmhr----1 on a River flowing be due east on at 25kmperhr. cal the magnitude of the resultant velocity of the ship.
Emmanuel Reply
The result is a simple vector addition. The angle between the vectors is 90 degrees, so we can use Pythagoras theorem to get the result. V magnitude = sqrt(100*100 + 25*25) = 103.077 km/hr. the direction of the resultant vector can be found using trigonometry. Tan (theta) = 25/100.
state Newton's first law of motion
Kansiime Reply
An object continues to be in its state of rest or motion unless compelled by some external force
First law (law of inertia)- If a body is at rest, it would remain at rest and if the body is in the motion, it would be moving with the same velocity until or unless no external force is applied on it. If force F^=0 acceleration a^=0 or v^=0 or constant.
how would you measure displacement in your car?
Grace Reply
By speed of car ×time used in displacement
what is constellation
Charles Reply
constellation is collection of stars in the galaxy
can we regard torque as a force?
Emmanuel Reply
Torque is only referred a force to rotate objects.
I need lessons on Simple harmonic motion
when I click on the links in the topics noting shows. what should I do.
Emmanuel Reply

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Source:  OpenStax, University physics volume 1. OpenStax CNX. Sep 19, 2016 Download for free at http://cnx.org/content/col12031/1.5
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