<< Chapter < Page Chapter >> Page >
F ( t ) = F max e t 2 / ( 2 τ 2 ) .

(The parameter τ represents how rapidly the force decreases to zero.) The average force is

F ave = 1 Δ t 0 t max F max e t 2 / ( 2 τ 2 ) d t

where Δ t = t max 0 s . Since we already have a numeric value for F ave , we can use the result of the integral to obtain F max .

Choosing τ = 1 e t max (this is a common choice, as you will see in later chapters), and guessing that t max = 2 s , this integral evaluates to

F avg = 0.458 F max .

Thus, the maximum force has a magnitude of

0.458 F max = 3.33 × 10 12 N F max = 7.27 × 10 12 N .

The complete force function, including the direction, is

F ( t ) = ( 7.27 × 10 12 N ) e t 2 / ( 8 s 2 ) y ^ .

This is the force Earth applied to the meteor; by Newton’s third law, the force the meteor applied to Earth is

F ( t ) = ( 7.27 × 10 12 N ) e t 2 / ( 8 s 2 ) y ^

which is the answer to the original question.

Significance

The graph of this function contains important information. Let’s graph (the magnitude of) both this function and the average force together ( [link] ).

A graph of the force and the average force as a function of time of the meteor impact. The horizontal axis is time in seconds and ranges from 0 to 2 seconds. The vertical axis is Force in Newtons and ranges from 0 to 8 times 10 to the 12. At t=0 the force starts at a little under 8 times 10 to the 12 and decreases to almost 0 at t=2. The average force is constant at about 3.5 times 10 to the 12. The areas under each of the curves are shaded and we are told the areas are equal.
A graph of the average force (in red) and the force as a function of time (blue) of the meteor impact. The areas under the curves are equal to each other, and are numerically equal to the applied impulse.

Notice that the area under each plot has been filled in. For the plot of the (constant) force F ave , the area is a rectangle, corresponding to F ave Δ t = J . As for the plot of F ( t ), recall from calculus that the area under the plot of a function is numerically equal to the integral of that function, over the specified interval; so here, that is 0 t max F ( t ) d t = J . Thus, the areas are equal, and both represent the impulse that the meteor applied to Earth during the two-second impact. The average force on Earth sounds like a huge force, and it is. Nevertheless, Earth barely noticed it. The acceleration Earth obtained was just

a = F ave M Earth = ( 3.33 × 10 12 N ) j ^ 5.97 × 10 24 kg = ( 5.6 × 10 −13 m s 2 ) j ^

which is completely immeasurable. That said, the impact created seismic waves that nowadays could be detected by modern monitoring equipment.

The benefits of impulse

A car traveling at 27 m/s collides with a building. The collision with the building causes the car to come to a stop in approximately 1 second. The driver, who weighs 860 N, is protected by a combination of a variable-tension seatbelt and an airbag ( [link] ). (In effect, the driver collides with the seatbelt and airbag and not with the building.) The airbag and seatbelt slow his velocity, such that he comes to a stop in approximately 2.5 s.

  1. What average force does the driver experience during the collision?
  2. Without the seatbelt and airbag, his collision time (with the steering wheel) would have been approximately 0.20 s. What force would he experience in this case?
Before the collision, a car is traveling at velocity v sub I equals 27 meters per second to the right. After the collision, the car has velocity v sub f = 0 and the passenger feels a force minus F to the left.
The motion of a car and its driver at the instant before and the instant after colliding with the wall. The restrained driver experiences a large backward force from the seatbelt and airbag, which causes his velocity to decrease to zero. (The forward force from the seatback is much smaller than the backward force, so we neglect it in the solution.)

Strategy

We are given the driver’s weight, his initial and final velocities, and the time of collision; we are asked to calculate a force. Impulse seems the right way to tackle this; we can combine [link] and [link] .

Practice Key Terms 2

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, University physics volume 1. OpenStax CNX. Sep 19, 2016 Download for free at http://cnx.org/content/col12031/1.5
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'University physics volume 1' conversation and receive update notifications?

Ask