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Shown below is a small particle of mass 20 g that is moving at a speed of 10.0 m/s when it collides and sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about its axis through its center and is perpendicular to the page. The cylinder has a mass of 0.5 kg and a radius of 10 cm, and is initially at rest. (a) What is the angular velocity of the system after the collision? (b) How much kinetic energy is lost in the collision?

Views of a particle colliding with a cylinder are shown before and after the collision. The cylinder’s face is in the plane of the page. Before, the particle is moving horizontally toward the top edge of the cylinder at 10 meters per second. The cylinder is at rest. After, the particle is stuck to the cylinder, which is rotating clockwise.
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A bug of mass 0.020 kg is at rest on the edge of a solid cylindrical disk ( M = 0.10 kg, R = 0.10 m ) rotating in a horizontal plane around the vertical axis through its center. The disk is rotating at 10.0 rad/s. The bug crawls to the center of the disk. (a) What is the new angular velocity of the disk? (b) What is the change in the kinetic energy of the system? (c) If the bug crawls back to the outer edge of the disk, what is the angular velocity of the disk then? (d) What is the new kinetic energy of the system? (e) What is the cause of the increase and decrease of kinetic energy?

a. I disk = 5.0 × 10 −4 kg · m 2 ,
I bug = 2.0 × 10 −4 kg · m 2 ,
( I disk + I bug ) ω 1 = I disk ω 2 , ω 2 = 14.0 rad / s
b. Δ K = 0.014 J ;
c. ω 3 = 10.0 rad / s back to the original value;
d. 1 2 ( I disk + I bug ) ω 3 2 = 0.035 J back to the original value;
e. work of the bug crawling on the disk

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A uniform rod of mass 200 g and length 100 cm is free to rotate in a horizontal plane around a fixed vertical axis through its center, perpendicular to its length. Two small beads, each of mass 20 g, are mounted in grooves along the rod. Initially, the two beads are held by catches on opposite sides of the rod’s center, 10 cm from the axis of rotation. With the beads in this position, the rod is rotating with an angular velocity of 10.0 rad/s. When the catches are released, the beads slide outward along the rod. (a) What is the rod’s angular velocity when the beads reach the ends of the rod? (b) What is the rod’s angular velocity if the beads fly off the rod?

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A merry-go-round has a radius of 2.0 m and a moment of inertia 300 kg · m 2 . A boy of mass 50 kg runs tangent to the rim at a speed of 4.0 m/s and jumps on. If the merry-go-round is initially at rest, what is the angular velocity after the boy jumps on?

L i = 400.0 kg · m 2 / s ,
L f = 500.0 kg · m 2 ω ,
ω = 0.80 rad / s

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A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.500 rev/s. What is its angular velocity after a 22.0-kg child gets onto it by grabbing its outer edge? The child is initially at rest.

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Three children are riding on the edge of a merry-go-round that is 100 kg, has a 1.60-m radius, and is spinning at 20.0 rpm. The children have masses of 22.0, 28.0, and 33.0 kg. If the child who has a mass of 28.0 kg moves to the center of the merry-go-round, what is the new angular velocity in rpm?

I 0 = 340.48 kg · m 2 ,
I f = 268.8 kg · m 2 ,
ω f = 25.33 rpm

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(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400 kg · m 2 . (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity decreases to 1.25 rev/s. (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.00 rev/s. What average torque was exerted if this takes 15.0 s?

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Practice Key Terms 1

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Source:  OpenStax, University physics volume 1. OpenStax CNX. Sep 19, 2016 Download for free at http://cnx.org/content/col12031/1.5
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