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Stationary skater A pushes stationary skater B, who then accelerates at 5.0 m/s 2 . Skater A does not move. Since forces act in action-reaction pairs, explain why Skater A did not move?

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The current in a river exerts a force of 9.0 N on a balloon floating in the river. A wind exerts a force of 13.0 N on the balloon in the opposite direction. Draw a free-body diagram to show the forces acting on the balloon. Use your free-body diagram to predict the effect on the balloon.

The diagram consists of a black dot in the center and two small red arrows pointing up (Fb) and down (Fg) and two long red arrows pointing right (Fc = 9.0 N) and left (Fw=13.0 N).

In the diagram, F g represents the force due to gravity on the balloon, and F b represents the buoyant force. These two forces are equal in magnitude and opposite in direction. F c represents the force of the current. F w represents the force of the wind. The net force on the balloon will be F w F c = 4.0 N and the balloon will accelerate in the direction the wind is blowing.

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A force is applied to accelerate an object on a smooth icy surface. When the force stops, which of the following will be true? (Assume zero friction.)

  1. The object’s acceleration becomes zero.
  2. The object’s speed becomes zero.
  3. The object’s acceleration continues to increase at a constant rate.
  4. The object accelerates, but in the opposite direction.
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A parachutist’s fall to Earth is determined by two opposing forces. A gravitational force of 539 N acts on the parachutist. After 2 s, she opens her parachute and experiences an air resistance of 615 N. At what speed is the parachutist falling after 10 s?

Since m = F / a , the parachutist has a mass of 539 N/9 .8 km/s 2 = 55 kg .

For the first 2 s, the parachutist accelerates at 9.8 m/s 2 .

v = a t = 9.8 m s 2 2 s = 17.6 m s

Her speed after 2 s is 19.6 m/s.

From 2 s to 10 s, the net force on the parachutist is 539 N – 615 N, or 76 N upward.

a = F m = 76 N 55 kg = 1.4 m s 2

Since v = v 0 + a t , v = 17.6 m/s 2 + ( 1.4 m/s 2 ) ( 8 s) = 6.5 m/s 2 .

At 10 s, the parachutist is falling to Earth at 8.4 m/s.

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A flight attendant pushes a cart down the aisle of a plane in flight. In determining the acceleration of the cart relative to the plane, which factor do you not need to consider?

  1. The friction of the cart’s wheels.
  2. The force with which the flight attendant’s feet push on the floor.
  3. The velocity of the plane.
  4. The mass of the items in the cart.
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A landscaper is easing a wheelbarrow full of soil down a hill. Define the system you would analyze and list all the forces that you would need to include to calculate the acceleration of the wheelbarrow.

The system includes the gardener and the wheelbarrow with its contents. The following forces are important to include: the weight of the wheelbarrow, the weight of the gardener, the normal force for the wheelbarrow and the gardener, the force of the gardener pushing against the ground and the equal force of the ground pushing back against the gardener, and any friction in the wheelbarrow’s wheels.

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Two water-skiers, with masses of 48 kg and 61 kg, are preparing to be towed behind the same boat. When the boat accelerates, the rope the skiers hold onto accelerates with it and exerts a net force of 290 N on the skiers. At what rate will the skiers accelerate?

  1. 10.8 m/s 2
  2. 2.7 m/s 2
  3. 6.0 m/s 2 and 4.8 m/s 2
  4. 5.3 m/s 2
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A figure skater has a mass of 40 kg and her partner's mass is 50 kg. She pushes against the ice with a force of 120 N, causing her and her partner to move forward. Calculate the pair’s acceleration. Assume that all forces opposing the motion, such as friction and air resistance, total 5.0 N.

The system undergoing acceleration is the two figure skaters together.

Net force = 120 N 5 .0 N = 115 N .

Total mass = 40 kg + 50 kg = 90 kg .

Using Newton’s second law, we have that

a = F m = 115 N 90 kg = 1.28 m s 2

The pair accelerates forward at 1.28 m/s 2 .

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Section summary

  • Newton’s third law of motion    represents a basic symmetry in nature. It states: Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that the first body exerts.
  • A thrust    is a reaction force that pushes a body forward in response to a backward force. Rockets, airplanes, and cars are pushed forward by a thrust reaction force.

Conceptual questions

When you take off in a jet aircraft, there is a sensation of being pushed back into the seat. Explain why you move backward in the seat—is there really a force backward on you? (The same reasoning explains whiplash injuries, in which the head is apparently thrown backward.)

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A device used since the 1940s to measure the kick or recoil of the body due to heart beats is the “ballistocardiograph.” What physics principle(s) are involved here to measure the force of cardiac contraction? How might we construct such a device?

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Describe a situation in which one system exerts a force on another and, as a consequence, experiences a force that is equal in magnitude and opposite in direction. Which of Newton’s laws of motion apply?

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Why does an ordinary rifle recoil (kick backward) when fired? The barrel of a recoilless rifle is open at both ends. Describe how Newton’s third law applies when one is fired. Can you safely stand close behind one when it is fired?

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An American football lineman reasons that it is senseless to try to out-push the opposing player, since no matter how hard he pushes he will experience an equal and opposite force from the other player. Use Newton’s laws and draw a free-body diagram of an appropriate system to explain how he can still out-push the opposition if he is strong enough.

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Newton’s third law of motion tells us that forces always occur in pairs of equal and opposite magnitude. Explain how the choice of the “system of interest” affects whether one such pair of forces cancels.

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Problem exercises

What net external force is exerted on a 1100-kg artillery shell fired from a battleship if the shell is accelerated at 2 . 40 × 10 4 m/s 2 size 12{2 "." "40"´"10" rSup { size 8{4} } " m/s" rSup { size 8{2} } } {} ? What is the magnitude of the force exerted on the ship by the artillery shell?

Force on shell: 2 . 64 × 10 7 N size 12{2 "." "64" times "10" rSup { size 8{7} } `N} {}

Force exerted on ship = 2 . 64 × 10 7 N size 12{ - 2 "." "64" times "10" rSup { size 8{7} } `N} {} , by Newton’s third law

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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800 N on him. The mass of the losing player plus equipment is 90.0 kg, and he is accelerating at 1 . 20 m/s 2 size 12{1 "." "20"" m/s" rSup { size 8{2} } } {} backward. (a) What is the force of friction between the losing player’s feet and the grass? (b) What force does the winning player exert on the ground to move forward if his mass plus equipment is 110 kg? (c) Draw a sketch of the situation showing the system of interest used to solve each part. For this situation, draw a free-body diagram and write the net force equation.

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Source:  OpenStax, College physics for ap® courses. OpenStax CNX. Nov 04, 2016 Download for free at https://legacy.cnx.org/content/col11844/1.14
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