Problem-solving strategies for the methods of heat transfer
Examine the situation to determine what type of heat transfer is involved.
Identify the type(s) of heat transfer—conduction, convection, or radiation.
Identify exactly what needs to be determined in the problem (identify the unknowns). A written list is very useful.
Make a list of what is given or can be inferred from the problem as stated (identify the knowns).
Solve the appropriate equation for the quantity to be determined (the unknown).
For conduction, equation
$\frac{Q}{t}=\frac{\text{kA}({T}_{2}-{T}_{1})}{d}$ is appropriate.
[link] lists thermal conductivities. For convection, determine the amount of matter moved and use equation
$Q=\text{mc}\text{\Delta}T$ , to calculate the heat transfer involved in the temperature change of the fluid. If a phase change accompanies convection, equation
$Q={\text{mL}}_{\text{f}}$ or
$Q={\text{mL}}_{\text{v}}$ is appropriate to find the heat transfer involved in the phase change.
[link] lists information relevant to phase change. For radiation, equation
$\frac{{Q}_{\text{net}}}{t}=\sigma eA\left({T}_{2}^{4}-{T}_{1}^{4}\right)$ gives the net heat transfer rate.
Insert the knowns along with their units into the appropriate equation and obtain numerical solutions complete with units.
Check the answer to see if it is reasonable. Does it make sense?
Summary
Radiation is the rate of heat transfer through the emission or absorption of electromagnetic waves.
The rate of heat transfer depends on the surface area and the fourth power of the absolute temperature:
$\frac{Q}{t}=\sigma eA{T}^{4}\text{,}$
where
$\sigma =5\text{.67}\times {\text{10}}^{-8}\phantom{\rule{0.25em}{0ex}}\text{J/s}\cdot {\text{m}}^{2}\cdot {\text{K}}^{4}$ is the Stefan-Boltzmann constant and
$e$ is the emissivity of the body. For a black body,
$e=1$ whereas a shiny white or perfect reflector has
$e=0$ , with real objects having values of
$e$ between 1 and 0. The net rate of heat transfer by radiation is
where
${T}_{1}$ is the temperature of an object surrounded by an environment with uniform temperature
${T}_{2}$ and
$e$ is the emissivity of the
object .
Conceptual questions
When watching a daytime circus in a large, dark-colored tent, you sense significant heat transfer from the tent. Explain why this occurs.
Satellites designed to observe the radiation from cold (3 K) dark space have sensors that are shaded from the Sun, Earth, and Moon and that are cooled to very low temperatures. Why must the sensors be at low temperature?
Why are thermometers that are used in weather stations shielded from the sunshine? What does a thermometer measure if it is shielded from the sunshine and also if it is not?
At what net rate does heat radiate from a
$\text{275}{\text{-m}}^{2}$ black roof on a night when the roof’s temperature is
$\text{30.}\mathrm{0\xba}\text{C}$ and the surrounding temperature is
$\text{15.}\mathrm{0\xba}\text{C}$ ? The emissivity of the roof is 0.900.
$-\text{21}\text{.}7\text{kW}$ Note that the negative answer implies heat loss to the surroundings.
(a) Cherry-red embers in a fireplace are at
$\text{850\xba}\text{C}$ and have an exposed area of
$0\text{.}\text{200}\phantom{\rule{0.25em}{0ex}}{\text{m}}^{2}$ and an emissivity of 0.980. The surrounding room has a temperature of
$\text{18}\text{.}\mathrm{0\xba}\text{C}$ . If 50% of the radiant energy enters the room, what is the net rate of radiant heat transfer in kilowatts? (b) Does your answer support the contention that most of the heat transfer into a room by a fireplace comes from infrared radiation?
fundamental unit are independent quantities that do not depend on any other unit while derived unit are quantities that depend on two or more units for it definition
Explain why magnetic damping might not be effective on an object made of several thin conducting layers separated by insulation? can someone please explain this i need it for my final exam
An object made of several thin conducting layers separated by insulation may not be affected by magnetic damping because the eddy current produced in each layer due to induction will be very small and the opposing magnetic flux produced by the eddy currents will be very small
Muhammad
What is thê principle behind movement of thê taps control
İt iş diffucult to have idêal machine because of FRİCTİON definitely reduce thê efficiency
Oluwakayode
It is difficult to have an ideal machine in real life situation because in ideal machines all the input energy should be converted to output energy . But , some part of energy is always lost in overcoming friction and input energy is always greater than output energy . Hence , no machine is ideal.
Muhammad
if the classica theory of specific heat is valid,what would be the thermal energy of one kmol of copper at the debye temperature (for copper is 340k)