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Percent relative humidity

We define percent relative humidity    as the ratio of vapor density to saturation vapor density, or

percent relative humidity = vapor density saturation vapor density × 100 size 12{ size 11{"percent relative humidity"= { { size 11{"vapor density"}} over { size 11{"saturation vapor density"}} } times "100"}} {}

We can use this and the data in [link] to do a variety of interesting calculations, keeping in mind that relative humidity is based on the comparison of the partial pressure of water vapor in air and ice.

Calculating humidity and dew point

(a) Calculate the percent relative humidity on a day when the temperature is 25 . 0 º C size 12{"25" "." 0°C} {} and the air contains 9.40 g of water vapor per m 3 size 12{m rSup { size 8{3} } } {} . (b) At what temperature will this air reach 100% relative humidity (the saturation density)? This temperature is the dew point. (c) What is the humidity when the air temperature is 25 . 0 º C size 12{"25" "." 0°C} {} and the dew point is 10 . 0 º C size 12{ +- "10" "." 0°C} {} ?

Strategy and Solution

(a) Percent relative humidity is defined as the ratio of vapor density to saturation vapor density.

percent relative humidity = vapor density saturation vapor density × 100 size 12{ size 11{"percent relative humidity"= { { size 11{"vapor density"}} over { size 11{"saturation vapor density"}} } times "100"}} {}

The first is given to be 9 . 40 g/m 3 size 12{9 "." "40 g/m" rSup { size 8{3} } } {} , and the second is found in [link] to be 23 . 0 g/m 3 size 12{"23" "." "0 g/m" rSup { size 8{3} } } {} . Thus,

percent relative humidity = 9 . 40 g/m 3 23 . 0 g/m 3 × 100 = 40 . 9 .% size 12{ size 11{"percent relative humidity"= { { size 11{9 "." "40 g/m" rSup { size 8{3} } }} over { size 12{"23" "." "0 g/m" rSup { size 8{3} } } } } ´"100"="40" "." 9% "." }} {}

(b) The air contains 9 . 40 g/m 3 size 12{9 "." "40 g/m" rSup { size 8{3} } } {} of water vapor. The relative humidity will be 100% at a temperature where 9 . 40 g/m 3 size 12{9 "." "40 g/m" rSup { size 8{3} } } {} is the saturation density. Inspection of [link] reveals this to be the case at 10 . 0 º C size 12{"10" "." 0°C} {} , where the relative humidity will be 100%. That temperature is called the dew point for air with this concentration of water vapor.

(c) Here, the dew point temperature is given to be 10 . 0 º C size 12{ +- "10" "." 0°C} {} . Using [link] , we see that the vapor density is 2 . 36 g/m 3 size 12{2 "." "36 g/m" rSup { size 8{3} } } {} , because this value is the saturation vapor density at 10 . 0 º C size 12{ +- "10" "." 0°C} {} . The saturation vapor density at 25 . 0 º C size 12{"25" "." 0°C} {} is seen to be 23 . 0 g/m 3 size 12{"23" "." "0 g/m" rSup { size 8{3} } } {} . Thus, the relative humidity at 25 . 0 º C size 12{"25" "." 0°C} {} is

percent relative humidity = 2 . 36 g/m 3 23 . 0 g/m 3 × 100 = 10 . 3 % . size 12{ size 11{"percent relative humidity"= { { size 11{2 "." "36 g/m" rSup { size 8{3} } }} over { size 12{"23" "." "0 g/m" rSup { size 8{3} } } } } ×"100"="10" "." 3% "." }} {}

Discussion

The importance of dew point is that air temperature cannot drop below 10 . 0 º C size 12{"10" "." 0°C} {} in part (b), or 10 . 0 º C size 12{ +- "10" "." 0°C} {} in part (c), without water vapor condensing out of the air. If condensation occurs, considerable transfer of heat occurs (discussed in Heat and Heat Transfer Methods ), which prevents the temperature from further dropping. When dew points are below 0 ºC size 12{0°C} {} , freezing temperatures are a greater possibility, which explains why farmers keep track of the dew point. Low humidity in deserts means low dew-point temperatures. Thus condensation is unlikely. If the temperature drops, vapor does not condense in liquid drops. Because no heat is released into the air, the air temperature drops more rapidly compared to air with higher humidity. Likewise, at high temperatures, liquid droplets do not evaporate, so that no heat is removed from the gas to the liquid phase. This explains the large range of temperature in arid regions.

Why does water boil at 100 º C size 12{"100"°C} {} ? You will note from [link] that the vapor pressure of water at 100 º C size 12{"100"°C} {} is 1 . 01 × 10 5 Pa size 12{1 "." "01"´"10" rSup { size 8{5} } " Pa"} {} , or 1.00 atm. Thus, it can evaporate without limit at this temperature and pressure. But why does it form bubbles when it boils? This is because water ordinarily contains significant amounts of dissolved air and other impurities, which are observed as small bubbles of air in a glass of water. If a bubble starts out at the bottom of the container at 20 º C size 12{"20"°C} {} , it contains water vapor (about 2.30%). The pressure inside the bubble is fixed at 1.00 atm (we ignore the slight pressure exerted by the water around it). As the temperature rises, the amount of air in the bubble stays the same, but the water vapor increases; the bubble expands to keep the pressure at 1.00 atm. At 100 º C size 12{"100"°C} {} , water vapor enters the bubble continuously since the partial pressure of water is equal to 1.00 atm in equilibrium. It cannot reach this pressure, however, since the bubble also contains air and total pressure is 1.00 atm. The bubble grows in size and thereby increases the buoyant force. The bubble breaks away and rises rapidly to the surface—we call this boiling! (See [link] .)

Questions & Answers

Pls guys am having problem on these topics: latent heat of fusion, specific heat capacity and the sub topics under them.Pls who can help?
hamidat Reply
Thanks George,I appreciate.
hamidat
this will lead you rightly of the formula to use
Abolarin
Most especially it is the calculatory aspects that is giving me issue, but with these new strength that you guys have given me,I will put in my best to understand it again.
hamidat
you can bring up a question and let's see what we can do to it
Abolarin
the distance between two suasive crests of water wave traveling of 3.6ms1 is 0.45m calculate the frequency of the wave
Idris Reply
v=f×lemda where the velocity is given and lends also given so simply u can calculate the frequency
Abdul
You are right my brother, make frequency the subject of formula and equate the values of velocity and lamda into the equation, that all.
hamidat
lExplain what happens to the energy carried by light that it is dimmed by passing it through two crossed polarizing filters.
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What is specific heat capacity?
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i want jamb related question on this asap🙏
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Practice Key Terms 4

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Source:  OpenStax, College physics. OpenStax CNX. Jul 27, 2015 Download for free at http://legacy.cnx.org/content/col11406/1.9
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