<< Chapter < Page Chapter >> Page >

[link] shows how viscosity is measured for a fluid. Two parallel plates have the specific fluid between them. The bottom plate is held fixed, while the top plate is moved to the right, dragging fluid with it. The layer (or lamina) of fluid in contact with either plate does not move relative to the plate, and so the top layer moves at v size 12{v} {} while the bottom layer remains at rest. Each successive layer from the top down exerts a force on the one below it, trying to drag it along, producing a continuous variation in speed from v size 12{v} {} to 0 as shown. Care is taken to insure that the flow is laminar; that is, the layers do not mix. The motion in [link] is like a continuous shearing motion. Fluids have zero shear strength, but the rate at which they are sheared is related to the same geometrical factors A size 12{A} {} and L size 12{L} {} as is shear deformation for solids.

The figure shows the laminar flow of fluid between two rectangular plates each of area A. The bottom plate is shown as fixed. The distance between the plates is L. The top plate is shown to be pushed to right with a force F. The direction of movement of the layer of fluid in contact with the top plate is also toward right with velocity v. The fluid in contact with the plate in the bottom is shown to be in rest with v equals zero. As we see through the layers above the one on the bottom plate, each show a small displacement toward right in increasing order of value with the topmost layer showing the maximum.
The graphic shows laminar flow of fluid between two plates of area A size 12{A} {} . The bottom plate is fixed. When the top plate is pushed to the right, it drags the fluid along with it.

A force F size 12{F} {} is required to keep the top plate in [link] moving at a constant velocity v size 12{v} {} , and experiments have shown that this force depends on four factors. First, F size 12{F} {} is directly proportional to v size 12{v} {} (until the speed is so high that turbulence occurs—then a much larger force is needed, and it has a more complicated dependence on v size 12{v} {} ). Second, F size 12{F} {} is proportional to the area A size 12{A} {} of the plate. This relationship seems reasonable, since A size 12{A} {} is directly proportional to the amount of fluid being moved. Third, F size 12{F} {} is inversely proportional to the distance between the plates L size 12{L} {} . This relationship is also reasonable; L size 12{L} {} is like a lever arm, and the greater the lever arm, the less force that is needed. Fourth, F size 12{F} {} is directly proportional to the coefficient of viscosity , η size 12{η} {} . The greater the viscosity, the greater the force required. These dependencies are combined into the equation

F = η vA L , size 12{F=η { { ital "vA"} over {L} } } {}

which gives us a working definition of fluid viscosity     η size 12{η} {} . Solving for η size 12{η} {} gives

η = FL vA , size 12{F=η { { ital "FL"} over { ital "vA"} } } {}

which defines viscosity in terms of how it is measured. The SI unit of viscosity is N m/ [ ( m/s ) m 2 ] = ( N/m 2 ) s or Pa s size 12{N cdot "m/" \[ \( "m/s" \) m rSup { size 8{2} } \] = \( "N/m" rSup { size 8{2} } \) "sorPa" cdot s} {} . [link] lists the coefficients of viscosity for various fluids.

Viscosity varies from one fluid to another by several orders of magnitude. As you might expect, the viscosities of gases are much less than those of liquids, and these viscosities are often temperature dependent. The viscosity of blood can be reduced by aspirin consumption, allowing it to flow more easily around the body. (When used over the long term in low doses, aspirin can help prevent heart attacks, and reduce the risk of blood clotting.)

Laminar flow confined to tubes—poiseuille’s law

What causes flow? The answer, not surprisingly, is pressure difference. In fact, there is a very simple relationship between horizontal flow and pressure. Flow rate Q size 12{Q} {} is in the direction from high to low pressure. The greater the pressure differential between two points, the greater the flow rate. This relationship can be stated as

Q = P 2 P 1 R , size 12{Q= { {P rSub { size 8{2} } - P rSub { size 8{1} } } over {R} } } {}

where P 1 size 12{P rSub { size 8{1} } } {} and P 2 size 12{P rSub { size 8{2} } } {} are the pressures at two points, such as at either end of a tube, and R size 12{R} {} is the resistance to flow. The resistance R size 12{R} {} includes everything, except pressure, that affects flow rate. For example, R size 12{R} {} is greater for a long tube than for a short one. The greater the viscosity of a fluid, the greater the value of R size 12{R} {} . Turbulence greatly increases R size 12{R} {} , whereas increasing the diameter of a tube decreases R size 12{R} {} .

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply
Practice Key Terms 5

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, College physics. OpenStax CNX. Jul 27, 2015 Download for free at http://legacy.cnx.org/content/col11406/1.9
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'College physics' conversation and receive update notifications?

Ask