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This module is from Fundamentals of Mathematics by Denny Burzynski and Wade Ellis, Jr. This module discusses how to estimate by clustering. By the end of the module students should understand the concept of clustering and be able to estimate the result of adding more than two numbers when clustering occurs using the clustering technique.

Section overview

  • Estimation by Clustering

Cluster

When more than two numbers are to be added, the sum may be estimated using the clustering technique. The rounding technique could also be used, but if several of the numbers are seen to cluster (are seen to be close to) one particular number, the clustering technique provides a quicker estimate. Consider a sum such as

32 + 68 + 29 + 73 size 12{"32 "+" 68 "+" 29 "+" 73"} {}

Notice two things:

  1. There are more than two numbers to be added.
  2. Clustering occurs.
    1. Both 68 and 73 cluster around 70, so 68 + 73 size 12{"68 "+" 73"} {} is close to 80 + 70 = 2 ( 70 ) = 140 size 12{"80"+"70"=2 \( "70" \) ="140"} {} .
      The expression 32 + 68 + 29 + 71. 32 and 29 are grouped together with a line, and 68 and 71 are grouped in the same way.
    2. Both 32 and 29 cluster around 30, so 32 + 29 size 12{"32 "+" 29"} {} is close to 30 + 30 = 2 ( 30 ) = 60 size 12{"30 "+" 30"=2 \( "30" \) ="60"} {} .

The sum may be estimated by

2 30 + 2 70 = 6 + 140 = 200

In fact, 32 + 68 + 29 + 73 = 202 size 12{"32 "+" 68 "+" 29 "+" 73 "=" 202"} {} .

Sample set a

Estimate each sum. Results may vary.

27 + 48 + 31 + 52 size 12{"27 "+" 48 "+" 31 "+" 52"} {} .

27 and 31 cluster near 30. Their sum is about 2 30 = 60 size 12{"2 " cdot " 30 "=" 60"} {} .

48 and 52 cluster near 50. Their sum is about 2 50 = 100 size 12{"2 " cdot " 50 "="100"} {} .

Thus, 27 + 48 + 31 + 5 2 size 12{"27"+"48"+"31"+5"2 "} {} is about ( 2 30 ) + ( 2 50 ) = 60 + 100 = 160

In fact, 27 + 48 + 31 + 52 = 158 size 12{"27 "+" 48 "+" 31 "+" 52 "=" 158"} {} .

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88 + 21 + 19 + 91 size 12{"88 "+" 21 "+" 19 "+" 91"} {} .

88 and 91 cluster near 90. Their sum is about 2 90 = 180 size 12{"2 " cdot " 90 "=" 180"} {} .

21 and 19 cluster near 20. Their sum is about 2 20 = 40 size 12{"2 " cdot " 20 "=" 40"} {} .

Thus, 88 + 21 + 19 + 91 size 12{"88 "+" 21 "+" 19 "+" 91"} {} is about ( 2 90 ) + ( 2 20 ) = 180 + 40 = 220

In fact, 88 + 21 + 19 + 91 = 219 size 12{"88 "+" 21 "+" 19 "+" 91 "=" 219"} {} .

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17 + 21 + 48 + 18 size 12{"17 "+" 21 "+" 48 "+" 18"} {} .

17, 21, and 18 cluster near 20. Their sum is about 3 20 = 60 size 12{"3 " cdot " 20 "=" 60"} {} .

48 is about 50.

Thus, 17 + 21 + 48 + 18 size 12{"17 "+" 21 "+" 48 "+" 18"} {} is about ( 3 20 ) + 50 = 60 + 50 = 110

In fact, 17 + 21 + 48 + 18 = 104 size 12{"17 "+" 21 "+" 48 "+" 18 "=" 104"} {} .

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61 + 48 + 49 + 57 + 52 size 12{"61 "+" 48 "+" 49 "+" 57 "+" 52"} {} .

61 and 57 cluster near 60. Their sum is about 2 60 = 120 size 12{"2 " cdot " 60 "=" 120"} {} .

48, 49, and 52 cluster near 50. Their sum is about 3 50 = 150 size 12{3 cdot " 50 "=" 150"} {} .

Thus, 61 + 48 + 49 + 57 + 52 size 12{"61 "+" 48 "+" 49 "+" 57 "+" 52"} {} is about ( 2 60 ) + ( 3 50 ) = 120 + 150 = 270

In fact, 61 + 48 + 49 + 57 + 52 = 267 size 12{"61 "+" 48 "+" 49 "+" 57 "+" 52 "=" 267"} {} .

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706 + 321 + 293 + 684 size 12{"706 "+" 321 "+" 293 "+" 684"} {} .

706 and 684 cluster near 700. Their sum is about 2 700 = 1,400 size 12{"2 " cdot " 700 "=" 1,400"} {} .

321 and 293 cluster near 300. Their sum is about 2 300 = 600 size 12{"2 " cdot " 300 "=" 600"} {} .

Thus, 706 + 321 + 293 + 684 size 12{"706 "+" 321 "+" 293 "+" 684"} {} is about ( 2 700 ) + ( 2 300 ) = 1,400 + 600 = 2,000

In fact, 706 + 321 + 293 + 684 = 2,004 size 12{"706 "+" 321 "+" 293 "+" 684 "=" 2,004"} {} .

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Practice set a

Use the clustering method to estimate each sum.

28 + 51 + 31 + 47 size 12{"28 "+" 51 "+" 31 "+" 47"} {}

( 2 30 ) + ( 2 50 ) = 60 + 100 = 160

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42 + 39 + 68 + 41 size 12{"42 "+" 39 "+" 68 "+" 41"} {}

( 3 40 ) + 70 = 120 + 70 = 190

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37 + 39 + 83 + 42 + 79 size 12{"37 "+" 39 "+" 83 "+" 42 "+" 79"} {}

( 3 40 ) + ( 2 80 ) = 120 + 160 = 280

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612 + 585 + 830 + 794 size 12{"612 "+" 585 "+" 830 "+" 794"} {}

( 2 600 ) + ( 2 800 ) = 1,200 + 1,600 = 2,800

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Exercises

Use the clustering method to estimate each sum. Results may vary.

28 + 51 + 31 + 47 size 12{"28"+"51"+"31"+"47"} {}

2 30 + 2 50 = 160   157 size 12{2 left ("30" right )+2 left ("50" right )="160" left ("157" right )} {}

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42 + 19 + 39 + 23 size 12{"42"+"19"+"39"+"23"} {}

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88 + 62 + 59 + 90 size 12{"88"+"62"+"59"+"90"} {}

2 90 + 2 60 = 300   299 size 12{2 left ("90" right )+2 left ("60" right )="300" left ("299" right )} {}

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76 + 29 + 33 + 82 size 12{"76"+"29"+"33"+"82"} {}

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19 + 23 + 87 + 21 size 12{"19"+"23"+"87"+"21"} {}

3 20 + 90 = 150   150 size 12{3 left ("20" right )+"90"="150" left ("150" right )} {}

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41 + 28 + 42 + 37 size 12{"41"+"28"+"42"+"37"} {}

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89 + 32 + 89 + 93 size 12{"89"+"32"+"89"+"93"} {}

3 90 + 30 = 300   303 size 12{3 left ("90" right )+"30"="300" left ("303" right )} {}

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73 + 72 + 27 + 71 size 12{"73"+"72"+"27"+"71"} {}

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43 + 62 + 61 + 55 size 12{"43"+"62"+"61"+"55"} {}

40 + 3 60 = 220   221 size 12{"40"+3 left ("60" right )="220" left ("221" right )} {}

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31 + 77 + 31 + 27 size 12{"31"+"77"+"31"+"27"} {}

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57 + 34 + 28 + 61 + 62 size 12{"57"+"34"+"28"+"61"+"62"} {}

3 60 + 2 30 = 240   242 size 12{3 left ("60" right )+2 left ("30" right )="240" left ("242" right )} {}

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94 + 18 + 23 + 91 + 19 size 12{"94"+"18"+"23"+"91"+"19"} {}

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103 + 72 + 66 + 97 + 99 size 12{"103"+"72"+"66"+"97"+"99"} {}

3 100 + 2 70 = 440   437 size 12{3 left ("100" right )+2 left ("70" right )="440" left ("437" right )} {}

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42 + 121 + 119 + 124 + 41 size 12{"42"+"121"+"119"+"124"+"41"} {}

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19 + 24 + 87 + 23 + 91 + 93 size 12{"19"+"24"+"87"+"23"+"91"+"93"} {}

3 20 + 3 90 = 330   337 size 12{3 left ("20" right )+3 left ("90" right )="330" left ("337" right )} {}

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108 + 61 + 63 + 96 + 57 + 99 size 12{"108"+"61"+"63"+"96"+"57"+"99"} {}

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518 + 721 + 493 + 689 size 12{"518"+"721"+"493"+"689"} {}

2 500 + 2 700 = 2, 400   2, 421 size 12{2 left ("500" right )+2 left ("700" right )=2,"400" left (2,"421" right )} {}

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981 + 1208 + 1214 + 1006 size 12{"981"+"1208"+"1214"+"1006"} {}

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23 + 81 + 77 + 79 + 19 + 81 size 12{"23"+"81"+"77"+"79"+"19"+"81"} {}

2 20 + 4 80 = 360   360 size 12{2 left ("20" right )+4 left ("80" right )="360" left ("360" right )} {}

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94 + 68 + 66 + 101 + 106 + 71 + 110 size 12{"94"+"68"+"66"+"101"+"106"+"71"+"110"} {}

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Exercises for review

( [link] ) Specify all the digits greater than 6.

7, 8, 9

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( [link] ) Find the product: 2 3 9 14 7 12 size 12{ { {2} over {3} } cdot { {9} over {"14"} } cdot { {7} over {"12"} } } {} .

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( [link] ) Convert 0.06 to a fraction.

3 50 size 12{ { {3} over {"50"} } } {}

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( [link] ) Write the proportion in fractional form: "5 is to 8 as 25 is to 40."

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( [link] ) Estimate the sum using the method of rounding: 4,882 + 2,704 size 12{"4,882 "+" 2,704"} {} .

4, 900 + 2, 700 = 7, 600   ( 7, 586 ) size 12{4,"900"+2,"700"=7,"600" \( 7,"586" \) } {}

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Source:  OpenStax, Fundamentals of mathematics. OpenStax CNX. Aug 18, 2010 Download for free at http://cnx.org/content/col10615/1.4
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