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This test determines whether a fish is a salmon or a trout based on different color features that are detected using the 2-D DWT

One of the most important features of different fish are the colors of their heads, tails, and bodies. This test breaks downthe different color matricies into blocks of similar colors and uses them to detect what color the different parts of the fish'sbody are.

The first part of the process is to run the 2-D DWT on each of the color matricies. It is run 3 times so that the resulting picture is 1/8 of theresolution of the original matricies, and there are only high values where the color is relatively constant for a largearea. This essentially provides a method for Low-Pass filtering the picture and finding only large blocks of color.

Next, the picture is filtered by dropping any values that are lower than a threshold and setting any values over thatthreshold to 1. This drops all areas in the picture that are not very intense, or where the values are not constant for alarge area. Now, the picture has only ones whereever the large blocks of color are.

The next step is to count all the different blocks of ones, which is done by using the Matlab command, bwlabel . Next, each block is examined one by one to see what size it is, and where in the picture itslocated. From this, it can be determined what color the body, head, and tail of the fish is. If they match the pattern foreither type of fish, then the test classifies it as that type. Because this is the hardest test to satisfy, it is also the mostheavily weighted test in the entire process.

Feature testing image

The features for each of the colors(red, green, then blue) for a sample sockeye salmon picture.

Code for feature detection

% This function takes in a 3D image matrix of three colors, red, green, and blue and uses the % 2-D DWT to low poss filter them and decrease their resolution. It then looks for blocks of% color and outputs a matrix with the size, and location of each of the different features of % each color. These can then be analyzed to see if they show evidence of a specific fish type.function [rfeats,gfeats,bfeats] = featuredet(image)redimage = image(:,:,1); greenimage = image(:,:,2);blueimage = image(:,:,3); rfeats = [0 0 0 0 0 0 0 0]; gfeats = [0 0 0 0 0 0 0 0]; bfeats = [0 0 0 0 0 0 0 0]; % Run the 2-D DWT on the different colors to reduce the resolution of the picture and% effectively low-pass filter the image. dwtr = dwt2(redimage, 'haar');dwtr2 = dwt2(dwtr, 'haar'); dwtr3 = dwt2(dwtr2, 'haar');%dwtr3feat = (dwtr3 > 6) dwtr4 = dwt2(dwtr3, 'haar');%dwtr4feat = (dwtr4 > 13); dwtg = dwt2(greenimage, 'haar');dwtg2 = dwt2(dwtg, 'haar'); dwtg3 = dwt2(dwtg2, 'haar');dwtg4 = dwt2(dwtg3, 'haar'); dwtb = dwt2(blueimage, 'haar');dwtb2 = dwt2(dwtb, 'haar'); dwtb3 = dwt2(dwtb2, 'haar');dwtb4 = dwt2(dwtb3, 'haar'); % Set everything below a threshold to 0 and everything above to 1 and then% number every group of ones in the binary image [redfeatures, numred]= bwlabel(dwtr3>5); [greenfeatures, numgreen]= bwlabel(dwtg3>5); [bluefeatures, numblue]= bwlabel(dwtb3>5); % Cycle through each different feature and find its location and sizefor a = 1:numred rowval = sum(redfeatures==a);colval = sum((redfeatures==a)')'; sizeval = size(redfeatures);j = 1; left = 0;while rowval(j)<1 left = j;j = j+1; endj = 1; right = sizeval(2);while rowval(sizeval(2)-j+1)<1 right = sizeval(2)-j+1;j = j+1; endj = 1; top = 0;while colval(j)<1 top = j;j = j+1; endj = 1; bottom = sizeval(1);while colval(sizeval(1)-j+1)<1 bottom = sizeval(1)-j+1;j = j+1; endsumval = sum(rowval); rfeats(a,:) = [top bottom bottom-top left right right-left (right-left)./(bottom-top) sumval]; endfor b = 1:numgreen rowval = sum(greenfeatures==b);colval = sum((greenfeatures==b)')'; sizeval = size(greenfeatures);j = 1; while rowval(j)<1 left = j;j = j+1; endj = 1; while rowval(sizeval(2)-j+1)<1 right = sizeval(2)-j+1;j = j+1; endj = 1; while colval(j)<1 top = j;j = j+1; endj = 1; while colval(sizeval(1)-j+1)<1 bottom = sizeval(1)-j+1;j = j+1; endsumval = sum(rowval); gfeats(b,:) = [top bottom bottom-top left right right-left (right-left)./(bottom-top) sumval]; endfor c = 1:numblue rowval = sum(bluefeatures==c);colval = sum((bluefeatures==c)')'; sizeval = size(bluefeatures);j = 1; while rowval(j)<1 left = j;j = j+1; endj = 1; while rowval(sizeval(2)-j+1)<1 right = sizeval(2)-j+1;j = j+1; endj = 1; while colval(j)<1 top = j;j = j+1; endj = 1; while colval(sizeval(1)-j+1)<1 bottom = sizeval(1)-j+1;j = j+1; endsumval = sum(rowval); bfeats(c,:) = [top bottom bottom-top left right right-left (right-left)./(bottom-top) sumval]; end

Code for feature analysis

% This function takes a 3D image and runs the feature detector on it, which gives matricies% containing the sizes and shapes of the different features. It then decides what color the % fish's body, head, and tail are, or whether the can't be determined by the features.function [body,head,tail] = featureanalyzer(fishimage);[rfeats,gfeats,bfeats] = featuredet(fishimage);impfeats = [0 0 0; 0 0 0; 0 0 0];% This section takes each feature located by the feature detector and decides if they % are evidence or a body, head, or tail of the fish being that color.for a = 1:size(rfeats,1) % If the feature is extremely long, it is a bodyif and(rfeats(a,6)>30, rfeats(a,8)>30) impfeats(1,1) = 1;end % If the feature is far to the right, it is a headif and(rfeats(a,4)>38, rfeats(a,8)>20) impfeats(1,2) = 1;end % If the features is far to the left, it is a tailif and(rfeats(a,5)<25, rfeats(a,8)>6) impfeats(1,3) = 1;end endfor b = 1:size(gfeats,1) if and(gfeats(b,6)>30, gfeats(b,8)>30)impfeats(2,1) = 1; endif and(gfeats(b,4)>38, gfeats(b,8)>10) impfeats(2,2) = 1;end if and(gfeats(b,5)<25, gfeats(b,8)>6) impfeats(2,3) = 1;end endfor c = 1:size(bfeats,1) if and(bfeats(c,6)>30, bfeats(c,8)>30)impfeats(3,1) = 1; endif and(bfeats(c,4)>38, bfeats(c,8)>10) impfeats(3,2) = 1;end if and(bfeats(c,5)<25, bfeats(c,8)>6) impfeats(3,3) = 1;end end% This section looks at each of the columns of the feature matrix and then % outputs which color pattern they are.if and(impfeats(1,1) == 1, and(impfeats (2,1) == 1, impfeats (3,1) == 1)) body = 'rgb';end if and(impfeats(1,1) == 1, and(impfeats (2,1) == 1, impfeats (3,1) == 0))body = 'rg '; endif and(impfeats(1,1) == 1, and(impfeats (2,1) == 0, impfeats (3,1) == 1)) body = 'rb ';end if and(impfeats(1,1) == 1, and(impfeats (2,1) == 0, impfeats (3,1) == 0))body = 'r '; endif and(impfeats(1,1) == 0, and(impfeats (2,1) == 1, impfeats (3,1) == 1)) body = 'gb ';end if and(impfeats(1,1) == 0, and(impfeats (2,1) == 1, impfeats (3,1) == 0))body = 'g '; endif and(impfeats(1,1) == 0, and(impfeats (2,1) == 0, impfeats (3,1) == 1)) body = 'b ';end if and(impfeats(1,1) == 0, and(impfeats (2,1) == 0, impfeats (3,1) == 0))body = 'cbd'; endif and(impfeats(1,2) == 1, and(impfeats (2,2) == 1, impfeats (3,2) == 1))head = 'rgb'; endif and(impfeats(1,2) == 1, and(impfeats (2,2) == 1, impfeats (3,2) == 0)) head = 'rg ';end if and(impfeats(1,2) == 1, and(impfeats (2,2) == 0, impfeats (3,2) == 1))head = 'rb '; endif and(impfeats(1,2) == 1, and(impfeats (2,2) == 0, impfeats (3,2) == 0)) head = 'r ';end if and(impfeats(1,2) == 0, and(impfeats (2,2) == 1, impfeats (3,2) == 1))head = 'gb '; endif and(impfeats(1,2) == 0, and(impfeats (2,2) == 1, impfeats (3,2) == 0)) head = 'g ';end if and(impfeats(1,2) == 0, and(impfeats (2,2) == 0, impfeats (3,2) == 1))head = 'b '; endif and(impfeats(1,2) == 0, and(impfeats (2,2) == 0, impfeats (3,2) == 0)) head = 'cbd';endif and(impfeats(1,3) == 1, and(impfeats (2,3) == 1, impfeats (3,3) == 1)) tail = 'rgb';end if and(impfeats(1,3) == 1, and(impfeats (2,3) == 1, impfeats (3,3) == 0))tail = 'rg '; endif and(impfeats(1,3) == 1, and(impfeats (2,3) == 0, impfeats (3,3) == 1)) tail = 'rb ';end if and(impfeats(1,3) == 1, and(impfeats (2,3) == 0, impfeats (3,3) == 0))tail = 'r '; endif and(impfeats(1,3) == 0, and(impfeats (2,3) == 1, impfeats (3,3) == 1)) tail = 'gb ';end if and(impfeats(1,3) == 0, and(impfeats (2,3) == 1, impfeats (3,3) == 0))tail = 'g '; endif and(impfeats(1,3) == 0, and(impfeats (2,3) == 0, impfeats (3,3) == 1)) tail = 'b ';end if and(impfeats(1,3) == 0, and(impfeats (2,3) == 0, impfeats (3,3) == 0))tail = 'cbd'; end

Questions & Answers

Application of nanotechnology in medicine
what is variations in raman spectra for nanomaterials
Jyoti Reply
I only see partial conversation and what's the question here!
Crow Reply
what about nanotechnology for water purification
RAW Reply
please someone correct me if I'm wrong but I think one can use nanoparticles, specially silver nanoparticles for water treatment.
Damian
yes that's correct
Professor
I think
Professor
what is the stm
Brian Reply
is there industrial application of fullrenes. What is the method to prepare fullrene on large scale.?
Rafiq
industrial application...? mmm I think on the medical side as drug carrier, but you should go deeper on your research, I may be wrong
Damian
How we are making nano material?
LITNING Reply
what is a peer
LITNING Reply
What is meant by 'nano scale'?
LITNING Reply
What is STMs full form?
LITNING
scanning tunneling microscope
Sahil
how nano science is used for hydrophobicity
Santosh
Do u think that Graphene and Fullrene fiber can be used to make Air Plane body structure the lightest and strongest. Rafiq
Rafiq
what is differents between GO and RGO?
Mahi
what is simplest way to understand the applications of nano robots used to detect the cancer affected cell of human body.? How this robot is carried to required site of body cell.? what will be the carrier material and how can be detected that correct delivery of drug is done Rafiq
Rafiq
if virus is killing to make ARTIFICIAL DNA OF GRAPHENE FOR KILLED THE VIRUS .THIS IS OUR ASSUMPTION
Anam
analytical skills graphene is prepared to kill any type viruses .
Anam
what is Nano technology ?
Bob Reply
write examples of Nano molecule?
Bob
The nanotechnology is as new science, to scale nanometric
brayan
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Damian
Is there any normative that regulates the use of silver nanoparticles?
Damian Reply
what king of growth are you checking .?
Renato
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
Stoney Reply
why we need to study biomolecules, molecular biology in nanotechnology?
Adin Reply
?
Kyle
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
Adin
why?
Adin
what school?
Kyle
biomolecules are e building blocks of every organics and inorganic materials.
Joe
anyone know any internet site where one can find nanotechnology papers?
Damian Reply
research.net
kanaga
sciencedirect big data base
Ernesto
Introduction about quantum dots in nanotechnology
Praveena Reply
hi
Loga
what does nano mean?
Anassong Reply
nano basically means 10^(-9). nanometer is a unit to measure length.
Bharti
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Source:  OpenStax, Ece 301 projects fall 2003. OpenStax CNX. Jan 22, 2004 Download for free at http://cnx.org/content/col10223/1.5
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