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  • Write the general solution to a nonhomogeneous differential equation.
  • Solve a nonhomogeneous differential equation by the method of undetermined coefficients.
  • Solve a nonhomogeneous differential equation by the method of variation of parameters.

In this section, we examine how to solve nonhomogeneous differential equations. The terminology and methods are different from those we used for homogeneous equations, so let’s start by defining some new terms.

General solution to a nonhomogeneous linear equation

Consider the nonhomogeneous linear differential equation

a 2 ( x ) y + a 1 ( x ) y + a 0 ( x ) y = r ( x ) .

The associated homogeneous equation

a 2 ( x ) y + a 1 ( x ) y + a 0 ( x ) y = 0

is called the complementary equation    . We will see that solving the complementary equation is an important step in solving a nonhomogeneous differential equation.

Definition

A solution y p ( x ) of a differential equation that contains no arbitrary constants is called a particular solution    to the equation.

General solution to a nonhomogeneous equation

Let y p ( x ) be any particular solution to the nonhomogeneous linear differential equation

a 2 ( x ) y + a 1 ( x ) y + a 0 ( x ) y = r ( x ) .

Also, let c 1 y 1 ( x ) + c 2 y 2 ( x ) denote the general solution to the complementary equation. Then, the general solution to the nonhomogeneous equation is given by

y ( x ) = c 1 y 1 ( x ) + c 2 y 2 ( x ) + y p ( x ).

Proof

To prove y ( x ) is the general solution, we must first show that it solves the differential equation and, second, that any solution to the differential equation can be written in that form. Substituting y ( x ) into the differential equation, we have

a 2 ( x ) y + a 1 ( x ) y + a 0 ( x ) y = a 2 ( x ) ( c 1 y 1 + c 2 y 2 + y p ) + a 1 ( x ) ( c 1 y 1 + c 2 y 2 + y p ) + a 0 ( x ) ( c 1 y 1 + c 2 y 2 + y p ) = [ a 2 ( x ) ( c 1 y 1 + c 2 y 2 ) + a 1 ( x ) ( c 1 y 1 + c 2 y 2 ) + a 0 ( x ) ( c 1 y 1 + c 2 y 2 ) ] + a 2 ( x ) y p + a 1 ( x ) y p + a 0 ( x ) y p = 0 + r ( x ) = r ( x ).

So y ( x ) is a solution.

Now, let z ( x ) be any solution to a 2 ( x ) y + a 1 ( x ) y + a 0 ( x ) y = r ( x ) . Then

a 2 ( x ) ( z y p ) + a 1 ( x ) ( z y p ) + a 0 ( x ) ( z y p ) = ( a 2 ( x ) z + a 1 ( x ) z + a 0 ( x ) z ) ( a 2 ( x ) y p + a 1 ( x ) y p + a 0 ( x ) y p ) = r ( x ) r ( x ) = 0 ,

so z ( x ) y p ( x ) is a solution to the complementary equation. But, c 1 y 1 ( x ) + c 2 y 2 ( x ) is the general solution to the complementary equation, so there are constants c 1 and c 2 such that

z ( x ) y p ( x ) = c 1 y 1 ( x ) + c 2 y 2 ( x ).

Hence, we see that z ( x ) = c 1 y 1 ( x ) + c 2 y 2 ( x ) + y p ( x ).

Verifying the general solution

Given that y p ( x ) = x is a particular solution to the differential equation y + y = x , write the general solution and check by verifying that the solution satisfies the equation.

The complementary equation is y + y = 0 , which has the general solution c 1 cos x + c 2 sin x . So, the general solution to the nonhomogeneous equation is

y ( x ) = c 1 cos x + c 2 sin x + x .

To verify that this is a solution, substitute it into the differential equation. We have

y ( x ) = c 1 sin x + c 2 cos x + 1 and y ( x ) = c 1 cos x c 2 sin x .

Then

y ( x ) + y ( x ) = c 1 cos x c 2 sin x + c 1 cos x + c 2 sin x + x = x .

So, y ( x ) is a solution to y + y = x .

Got questions? Get instant answers now!
Got questions? Get instant answers now!

Given that y p ( x ) = −2 is a particular solution to y 3 y 4 y = 8 , write the general solution and verify that the general solution satisfies the equation.

y ( x ) = c 1 e x + c 2 e 4 x 2

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In the preceding section, we learned how to solve homogeneous equations with constant coefficients. Therefore, for nonhomogeneous equations of the form a y + b y + c y = r ( x ) , we already know how to solve the complementary equation, and the problem boils down to finding a particular solution for the nonhomogeneous equation. We now examine two techniques for this: the method of undetermined coefficients and the method of variation of parameters.

Practice Key Terms 4

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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