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Homework exercises on rational expressions and equations.

3x 2 + 5x 8 6x + 16 size 12{ { {3x rSup { size 8{2} } +5x - 8} over {6x+"16"} } } {} × 4x 3 + x 3x 3 3x size 12{ { {4x rSup { size 8{3} } +x} over {3x rSup { size 8{3} } - 3x} } } {}

  • A

    Simplify
  • B

    What values of x are not allowed in the original expression?
  • C

    What values of x are not allowed in your simplified expression?

2 4x 3 x + 3 2x 3 + 3x 2 + x size 12{ { {2} over {4x rSup { size 8{3} } - x} } + { {3} over {2x rSup { size 8{3} } +3x rSup { size 8{2} } +x} } } {}

  • A

    Simplify
  • B

    What values of x are not allowed in the original expression?
  • C

    What values of x are not allowed in your simplified expression?

x 2 + 9 x 2 - 4 x 2 + 7 x + 12 x 2 + 2 x - 8

  • A

    Simplify
  • B

    What values of x are not allowed in the original expression?
  • C

    What values of x are not allowed in your simplified expression?
  • D

    Test your answer by choosing an x value and plugging it into the original expression, and your simplified expression. Do they yield the same answer?

x x 2 - 25 + <something> = x 2 + 1 x 3 9x 2 + 20 x size 12{ { {x rSup { size 8{2} } +1} over {x rSup { size 8{3} } - 9x rSup { size 8{2} } +"20"x} } } {}

  • A

    What is the something?
  • B

    What values of x are not allowed in the original expression?
  • C

    What values of x are not allowed in your simplified expression?

x 6 x 3 = x + 18 2x + 7 size 12{ { {x - 6} over {x - 3} } = { {x+"18"} over {2x+7} } } {}

  • A

    Solve for x . You should get two answers.
  • B

    Check by plugging one of your answers back into the original equation.

If f ( x ) = 1 x size 12{ { {1} over {x} } } {} , find f ( x + h ) f ( x ) h size 12{ { {f \( x+h \) - f \( x \) } over {h} } } {} .

The first item, f ( x + h ) , is a composite function!

Simplify as much as possible.

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Source:  OpenStax, Math 1508 (lecture) readings in precalculus. OpenStax CNX. Aug 24, 2011 Download for free at http://cnx.org/content/col11354/1.1
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