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Define a function f on the closed interval [ 0 , 1 ] by f ( x ) = x .

  1. For each positive integer n , let P n be the partition of [ 0 , 1 ] given by the points { 0 < 1 / n < 2 / n < 3 / n < ... < ( n - 1 ) / n < 1 } . Define a step function h n on [ 0 , 1 ] by setting h n ( x ) = i / n if i - 1 n < x < i n , and h n ( i / n ) = i / n for all 0 i n . Prove that | f ( x ) - h n ( x ) | < 1 / n for all x [ 0 , 1 ] , and then conclude that f is the uniform limit of the h n 's whence f I ( [ 0 , 1 ] ) .
  2. Show that
    h n = i = 1 n i n 2 = n ( n + 1 ) 2 n 2 .
  3. Show that 0 1 f ( t ) d t = 1 / 2 . The next exercise establishes some additional properties of integrable functions on an interval [ a , b ] .

Let [ a , b ] be a closed and bounded interval, and let f be an element of I ( [ a , b ] ) .

  1. Show that, for each ϵ > 0 there exists a step function h on [ a , b ] such that | f ( x ) - h ( x ) | < ϵ for all x [ a , b ] .
  2. For each positive integer n let h n be a step function satisfying the conclusion of part (a) for ϵ = 1 / n . Define k n = h n - 1 / n and l n = h n + 1 / n . Show that k n and l n are step functions, that k n ( x ) < f ( x ) < l n ( x ) for all x [ a , b ] , and that | l n ( x ) - k n ( x ) | = l n ( x ) - k n ( x ) = 2 / n for all x . Hence, a b ( l n - k n ) = 2 n ( b - a ) .
  3. Conclude from part (b) that, given any ϵ > 0 , there exist step functions k and l such that k ( x ) f ( x ) l ( x ) for which ( l ( x ) - k ( x ) ) < ϵ .
  4. Prove that there exists a sequence { j n } of step functions on [ a , b ] , for which j n ( x ) j n + 1 ( x ) f ( x ) for all x , that converges uniformly to f . Show also that there exists a sequence { j n ' } of step functions on [ a , b ] , for which j n ' ( x ) j n + 1 ' ( x ) f ( x ) for all x , that converges uniformly to f . That is, if f I ( [ a , b ] ) , then f is the uniform limit of a nondecreasing sequence of step functions and also is the uniformlimit of a nonincreasing sequence of step functions. HINT: To construct the j n 's and j n ' 's, use the step functions k n and l n of part (b), and recall that the maximum and minimum of step functions is again a step function.
  5. Show that if f ( x ) 0 for all x [ a , b ] , and g is defined by g ( x ) = f ( x ) , then g I ( [ a , b ] ) . HINT: Write f = lim h n where h n ( x ) 0 for all x and n . Then use part (g) of Exercise 3.28.
  6. (Riemann sums again.) Show that, given an ϵ > 0 , there exists a partition P such that if Q = { x 0 < x 1 < ... < x n } is any partition finer than P , and { w i } are any points for which w i ( x i - 1 , x i ) , then
    | a b f ( t ) d t - i = 1 n f ( w i ) ( x i - x i - 1 ) | < ϵ .
    HINT: Let P be a partition for which both the step functions k and l of part (c) are constant on the open subintervals of P . Verify that for any finer partition Q , l ( w i ) f ( w i ) k ( w i ) , and hence
    i l ( w i ) ( x i - x i - 1 ) i f ( w i ) ( x i - x i - 1 ) i k ( w i ) ( x i - x i - 1 ) .

A bounded real-valued function f on a closed bounded interval [ a , b ] is called Riemann-integrable if, given any ϵ > 0 , there exist step functions k and l , on [ a , b ] for which k ( x ) f ( x ) l ( x ) for all x , such that ( l - k ) < ϵ . We denote the set of all functions on [ a , b ] that are Riemann-integrable by I R ( [ a , b ] ) .

REMARK The notion of Riemann-integrability was introduced by Riemann in the mid nineteenth century and was the first formal definition of integrability.Since then several other definitions have been given for an integral, culminating in the theory of Lebesgue integration.The definition of integrability that we are using in this book is slightly different and less general from that of Riemann, and both of these are very different and less general fromthe definition given by Lebesgue in the early twentieth century. Part (c) of [link] above shows that the functions we are calling integrable are necessarily Riemann-integrable.We will see in [link] that there are Riemann-integrable functions that are not integrable in our sense. In both cases, Riemann's and ours, an integrable function f must be trapped between two step functions k and l . In our definition, we must have l ( x ) - k ( x ) < ϵ for all x [ a , b ] , while in Riemann's definition, we only need that l - k < ϵ . The distinction is that a small step function must have a small integral, but it isn't necessary for a step function to be (uniformly) small in order for it tohave a small integral. It only has to be small on most of the interval [ a , b ] .

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Source:  OpenStax, Analysis of functions of a single variable. OpenStax CNX. Dec 11, 2010 Download for free at http://cnx.org/content/col11249/1.1
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