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Listing 6 computes new values for the red and green components based on the existing color values for the pixel and the scalefactors computed in Listing 5 .

Listing 6 . Apply the scale factors.
pixel.setGreen((int)(green * greenScale)); pixel.setBlue((int)(blue * blueScale));}//end for loop

Then Listing 6 calls the setGreen and setBlue methods on the Pixel object to set the green and blue color values to the newly computed values.

The end of the for loop

Listing 6 also signals the end of the for loop that began in Listing 4 .

Display the modified image

Finally, Listing 7 calls the explore method again to display the image shown in Figure 2 .

Listing 7 . Display the modified image.
pic.explore(); }//end run method}//end class Prob03Runner

The end of the run method

Listing 7 also signals the end of the run method and the end of the Prob03Runner class.

Return control to main

The run method terminates and returns control to the main method shown in Listing 1 .

The code in the main method calls a getter method to get a reference to the Picture object.

The reference is passed to the println method, which displays the information about the Picture object in the last line of Figure 3 .

The program terminates

Then the main method terminates, at which time the program terminates and returns control to the operating system.

Run the program

I encourage you to copy the code from Listing 8 , compile it and execute it. Experiment with the code, making changes, andobserving the results of your changes. Make certain that you can explain why your changes behave as they do.

You can download a copy of the required input image file here .


In this module, I showed you how to implement an algorithm that causes the green and blue color values in an image to change in a linear fashion going fromleft to right across the image.

What's next?

You will learn more about abstract methods, abstract classes, and overridden methods in the next lesson. Very importantly, you will learn more about overriding the toString method.

While not a requirement of the course, you can select the following links to view optional online video lectures on the material in thismodule.


This section contains a variety of miscellaneous information.

Housekeeping material
  • Module name: Java OOP: Implementing a space-wise linear color-modification algorithm
  • File: Java3006.htm
  • Published: 07/30/12

Financial : Although the Connexions site makes it possible for you to download a PDF file for thismodule at no charge, and also makes it possible for you to purchase a pre-printed version of the PDF file, you should beaware that some of the HTML elements in this module may not translate well into PDF.

I also want you to know that, I receive no financial compensation from the Connexions website even if you purchase the PDF version of the module.

In the past, unknown individuals have copied my modules from cnx.org, converted them to Kindle books, and placed them for sale on Amazon.com showing me as the author. Ineither receive compensation for those sales nor do I know who does receive compensation. If you purchase such a book, please beaware that it is a copy of a module that is freely available on cnx.org and that it was made and published withoutmy prior knowledge.

Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.

Complete program listing

A complete listing of the program discussed in this module is shown in Listing 8 below.

Listing 8 . Complete program listing.
/*File Prob03 Copyright 2008 R.G.Baldwin *********************************************************/public class Prob03{ public static void main(String[]args){ Prob03Runner obj = new Prob03Runner();obj.run(); System.out.println(obj.getPicture());}//end main }//end class Prob03//======================================================// class Prob03Runner{//Instantiate the Picture object. private Picture pic = new Picture("Prob03.jpg");public Prob03Runner(){//constructor System.out.println("Dick Baldwin");}//end constructor //----------------------------------------------------////Accessor method public Picture getPicture(){return pic;}//----------------------------------------------------// //This method is where the action is.public void run(){ pic.addMessage("Dick Baldwin",10,20);//Display a PictureExplorer object. pic.explore();//Get an array of Pixel objects. Pixel[]pixels = pic.getPixels(); //Declare working variablesPixel pixel = null; int green = 0;int blue = 0; int width = pic.getWidth();double greenScale = 0; double blueScale = 0;//Scale the blue and green color components according // to the algorithm given above.//Do not scale the red component. for(int cnt = 0;cnt<pixels.length;cnt++){ //Get blue and green values for current pixel.pixel = pixels[cnt];green = pixel.getGreen(); blue = pixel.getBlue();//Compute the column number and use it to compute // the scale factor.int col = cnt%width; greenScale = (double)(width - col)/width;blueScale = (double)(col)/width; //Apply the scale factor.pixel.setGreen((int)(green * greenScale)); pixel.setBlue((int)(blue * blueScale));}//end for loop //Display a PictureExplorer object.pic.explore(); }//end run method}//end class Prob03Runner


Questions & Answers

what is math number
Tric Reply
x-2y+3z=-3 2x-y+z=7 -x+3y-z=6
Sidiki Reply
Need help solving this problem (2/7)^-2
Simone Reply
what is the coefficient of -4×
Mehri Reply
the operation * is x * y =x + y/ 1+(x × y) show if the operation is commutative if x × y is not equal to -1
Alfred Reply
An investment account was opened with an initial deposit of $9,600 and earns 7.4% interest, compounded continuously. How much will the account be worth after 15 years?
Kala Reply
lim x to infinity e^1-e^-1/log(1+x)
given eccentricity and a point find the equiation
Moses Reply
12, 17, 22.... 25th term
Alexandra Reply
12, 17, 22.... 25th term
College algebra is really hard?
Shirleen Reply
Absolutely, for me. My problems with math started in First grade...involving a nun Sister Anastasia, bad vision, talking & getting expelled from Catholic school. When it comes to math I just can't focus and all I can hear is our family silverware banging and clanging on the pink Formica table.
I'm 13 and I understand it great
I am 1 year old but I can do it! 1+1=2 proof very hard for me though.
Not really they are just easy concepts which can be understood if you have great basics. I am 14 I understood them easily.
hi vedant can u help me with some assignments
find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
If f(x) = x-2 then, f(3) when 5f(x+1) 5((3-2)+1) 5(1+1) 5(2) 10
how do they get the third part x = (32)5/4
kinnecy Reply
make 5/4 into a mixed number, make that a decimal, and then multiply 32 by the decimal 5/4 turns out to be
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
sure. what is your question?
okay, so you have 6 raised to the power of 2. what is that part of your answer
I don't understand what the A with approx sign and the boxed x mean
it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
so you not have an equal sign anywhere in the original equation?
is it a question of log
I rally confuse this number And equations too I need exactly help
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Commplementary angles
Idrissa Reply
im all ears I need to learn
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greetings from Iran
salut. from Algeria
A soccer field is a rectangle 130 meters wide and 110 meters long. The coach asks players to run from one corner to the other corner diagonally across. What is that distance, to the nearest tenths place.
Kimberly Reply
Jeannette has $5 and $10 bills in her wallet. The number of fives is three more than six times the number of tens. Let t represent the number of tens. Write an expression for the number of fives.
August Reply
What is the expressiin for seven less than four times the number of nickels
Leonardo Reply
How do i figure this problem out.
how do you translate this in Algebraic Expressions
linda Reply
why surface tension is zero at critical temperature
I think if critical temperature denote high temperature then a liquid stats boils that time the water stats to evaporate so some moles of h2o to up and due to high temp the bonding break they have low density so it can be a reason
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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