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TRUE or FALSE: A small, fixed phase offset in the receiver demodulatingAM with suppressed carrier produces an undesirable low frequency modulated version of the analog message.

Try different frequency offsets gam = [ . 014 , 0 . 1 , 1 . 0 , 10 ] . How well does the recovered message m ( t ) match the actual message w ( t ) ? For each case, what is the spectrum of m ( t ) ? Hint: look over more than just the first 1 / 10 second to see the effect.

Consider the system shown in [link] . Show that the output of the system is 2 A 0 w ( t ) cos ( 2 π f c t ) , as indicated.

Create a M atlab routine to implement the square-law mixing modulator of [link] .

  1. Create a signal w ( t ) that has bandwidth 100 Hz
  2. Modulate the signal to 1000 Hz.
  3. Demodulate using the AM demodulator from AM.m (to recover the original w ( t ) ).
The square-law mixing transmitter of Exercises 5-9 through 5-11.
The square-law mixing transmitter of Exercises [link] through [link] .

Exercise [link] essentially creates a transmitter and receiver based on the square-law modulator(rather than the more standard mixing modulator). Using this system:

  1. Show how the received signal degrades if the phase of the cosine wave is not known exactly.
  2. Show how the received signal degrades if the frequency of the cosine wave is not exact.
  3. Show how the received signal degrades if the bandpass filter is not centered at the specified frequency.

Consider the transmission system of [link] . The message signal w ( t ) has magnitude spectrum shown in part (a).The transmitter in part (b) produces the transmitted signal x ( t ) which passes through the channel in part (c). The channel scales thesignal and adds narrowband interferers to create the received signal r ( t ) . The transmitter and channel parameters are Φ 1 = 0 . 3 radians, f 1 = 24 . 1 kHz, f 2 = 23 . 9 kHz, f 3 = 27 . 5 kHz, f 4 = 29 . 3 kHz, and f 5 = 22 . 6 kHz. Thereceiver processing r ( t ) is shown in [link] (d). All bandpass and lowpass filters are considered ideal with a gainof unity in the passband and zero in the stopband.

  1. Sketch | R ( f ) | for - 30 kHz f 30kHz. Clearly indicate the amplitudes and frequencies of key points in the sketch.
  2. Assume that Φ 2 is chosen to maximize the magnitude of y ( t ) and reflects the value of Φ 1 and the delays imposed by the two ideal bandpass filters that form thereceived signal r ( t ) . Select the receiver parameters f 6 , f 7 , f 8 , and f 9 , so the receiver output y ( t ) is a scaled version of w ( t ) .
The transmission system for Exercise 5-12: (a) magnitude spectrum of the messsage, (b) the transmitter, (c) the channel, and (d) the receiver.
The transmission system for Exercise [link] : (a) magnitude spectrum of the messsage,(b) the transmitter, (c) the channel, and (d) the receiver.

An analog baseband message signal w ( t ) has all energy between - B and B Hz. It is upconverted to the transmitted passband signal x ( t ) via AM with suppressed carrier

x ( t ) = w ( t ) cos ( 2 π f c t + Φ c )

where a carrier frequency f c > 10 B . The channel is a pure delay and the received signal r is r ( t ) = x ( t - d ) where the delay d = n T c + T c / α is an integer multiple n 0 of the carrier period T c ( = 1 / f c ) plus a fraction of T c given by α > 1 . The mixer at the receiver is perfectly synchronizedto the transmitter so that the mixer output y ( t ) is

y ( t ) = r ( t ) cos ( 2 π f c t + Φ r ) .

The receiver mixer phase may not match the transmitter mixer phase Φ c . The receiver lowpass filters y to produce

v ( t ) = LPF { y ( t ) }

where the lowpass filter is ideal with unity passband gain, linear passband phase with zero phase at zero frequency, and cutoff frequency 1 . 2 B .

  1. Write a formula for the receiver mixer output y ( t ) as a function of f c , Φ c , d , α , Φ r , and w ( t ) (without use of x , r , n , or T c ).
  2. Determine the amplitude of the minimum and maximum values of y ( t ) for α = 4 .
  3. For α = 6 , n = 42 , Φ c = 0 . 2 radians, and T c = 20 μ sec, determine Φ r that maximizes the magnitude of the maximum and minimum values of v ( t ) .

Questions & Answers

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Damian Reply
research.net
kanaga
Introduction about quantum dots in nanotechnology
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there is no specific books for beginners but there is book called principle of nanotechnology
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s.
fullerene is a bucky ball aka Carbon 60 molecule. It was name by the architect Fuller. He design the geodesic dome. it resembles a soccer ball.
Tarell
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Damian
That is a great question Damian. best way to answer that question is to Google it. there are hundreds of applications for buck minister fullerenes, from medical to aerospace. you can also find plenty of research papers that will give you great detail on the potential applications of fullerenes.
Tarell
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Mostly, they use nano carbon for electronics and for materials to be strengthened.
Virgil
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CYNTHIA
carbon nanotubes has various application in fuel cells membrane, current research on cancer drug,and in electronics MEMS and NEMS etc
NANO
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s. Reply
Yeah, it is a pain to say the least. You basically have to heat the substarte up to around 1000 degrees celcius then pass phosphene gas over top of it, which is explosive and toxic by the way, under very low pressure.
Harper
Do you know which machine is used to that process?
s.
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SUYASH Reply
for screen printed electrodes ?
SUYASH
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s. Reply
of graphene you mean?
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in general
s.
Graphene has a hexagonal structure
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Cied
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Source:  OpenStax, Software receiver design. OpenStax CNX. Aug 13, 2013 Download for free at http://cnx.org/content/col11510/1.3
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