<< Chapter < Page
  Radicals   Page 1 / 1
Chapter >> Page >
This module covers techniques for the simplification of radicals.

Simplifying radicals

The property ab size 12{ sqrt { ital "ab"} } {} = a size 12{ sqrt {a} } {} b size 12{ sqrt {b} } {} can be used to simplify radicals. The key is to break the number inside the root into two factors, one of which is a perfect square .

Simplifying a radical

75 size 12{ sqrt {"75"} } {}
= 25 3 because 25•3 is 75, and 25 is a perfect square
= 25 3 because ab size 12{ sqrt { ital "ab"} } {} = a size 12{ sqrt {a} } {} b size 12{ sqrt {b} } {}
= 5 3 size 12{ sqrt {3} } {} because 25 =5

So we conclude that 75 size 12{ sqrt {"75"} } {} =5 3 size 12{ sqrt {3} } {} . You can confirm this on your calculator (both are approximately 8.66).

We rewrote 75 as 25 3 because 25 is a perfect square. We could, of course, also rewrite 75 as 5 15 , but—although correct—that would not help us simplify, because neither number is a perfect square.

Simplifying a radical in two steps

180
= 9•20 because 9 20 is 180, and 9 is a perfect square
= 9 20 because ab size 12{ sqrt { ital "ab"} } {} = a size 12{ sqrt {a} } {} b size 12{ sqrt {b} } {}
= 3 20 So far, so good. But wait! We’re not done!
= 3 4•5 There’s another perfect square to pull out!
= 3 4 5
= 3 ( 2 ) 5
= 6 5 Now we’re done.

The moral of this second example is that after you simplify, you should always look to see if you can simplify again .

A secondary moral is, try to pull out the biggest perfect square you can. We could have jumped straight to the answer if we had begun by rewriting 180 as 36 5 .

This sort of simplification can sometimes allow you to combine radical terms, as in this example:

Combining radicals

75 size 12{ sqrt {"75"} } {} 12 size 12{ sqrt {"12"} } {}
= 5 3 size 12{ sqrt {3} } {} –2 3 size 12{ sqrt {3} } {} We found earlier that 75 size 12{ sqrt {"75"} } {} = 5 3 size 12{ sqrt {3} } {} . Use the same method to confirm that 12 size 12{ sqrt {"12"} } {} = 2 3 size 12{ sqrt {3} } {} .
= 3 3 size 12{ sqrt {3} } {} 5 of anything minus 2 of that same thing is 3 of it, right?

That last step may take a bit of thought. It can only be used when the radical is the same. Hence, 2 size 12{ sqrt {2} } {} + 3 size 12{ sqrt {3} } {} cannot be simplified at all. We were able to simplify 75 size 12{ sqrt {"75"} } {} 12 size 12{ sqrt {"12"} } {} only by making the radical in both cases the same .

So why does 5 3 size 12{ sqrt {3} } {} –2 3 size 12{ sqrt {3} } {} = 3 3 size 12{ sqrt {3} } {} ? It may be simplest to think about verbally: 5 of these things, minus 2 of the same things, is 3 of them. But you can look at it more formally as a factoring problem, if you see a common factor of 3 size 12{ sqrt {3} } {} .

5 3 size 12{ sqrt {3} } {} –2 3 size 12{ sqrt {3} } {} = 3 size 12{ sqrt {3} } {} ( 5 2 ) = 3 size 12{ sqrt {3} } {} ( 3 ) .

Of course, the process is exactly the same if variable are involved instead of just numbers!

Combining radicals with variables

x 3 2 + x 5 2
= x 3 + x 5 Remember the definition of fractional exponents!
= x 2 * x + x 4 * x As always, we simplify radicals by factoring them inside the root...
x 2 * x + x 4 * x and then breaking them up...
= x x + x 2 x and then taking square roots outside!
= ( x 2 + x ) x Now that the radical is the same, we can combine.

Rationalizing the denominator

It is always possible to express a fraction with no square roots in the denominator.

Is it always desirable? Some texts are religious about this point: “You should never have a square root in the denominator.” I have absolutely no idea why. To me, 1 2 size 12{ { {1} over { sqrt {2} } } } {} looks simpler than 2 2 size 12{ { { sqrt {2} } over {2} } } {} ; I see no overwhelming reason for forbidding the first or preferring the second.

However, there are times when it is useful to remove the radicals from the denominator: for instance, when adding fractions. The trick for doing this is based on the basic rule of fractions: if you multiply the top and bottom of a fraction by the same number, the fraction is unchanged. This rule enables us to say, for instance, that 2 3 size 12{ { {2} over {3} } } {} is exactly the same number as 2 3 3 3 size 12{ { {2 cdot 3} over {3 cdot 3} } } {} = 6 9 size 12{ { {6} over {9} } } {} .

In a case like 1 2 size 12{ { {1} over { sqrt {2} } } } {} , therefore, you can multiply the top and bottom by 2 size 12{ sqrt {2} } {} .

1 2 size 12{ { {1} over { sqrt {2} } } } {} = 1 * 2 2 * 2 = 2 2 size 12{ { { sqrt {2} } over {2} } } {}

What about a more complicated case, such as 12 1 + 3 size 12{ { { sqrt {"12"} } over {1+ sqrt {3} } } } {} ? You might think we could simplify this by multiplying the top and bottom by ( 1 + 3 size 12{ sqrt {3} } {} ), but that doesn’t work: the bottom turns into ( 1 + 3 ) 2 = 1 + 2 3 size 12{ sqrt {3} } {} + 3 , which is at least as ugly as what we had before.

The correct trick for getting rid of ( 1 + 3 size 12{ sqrt {3} } {} ) is to multiply it by ( 1 3 size 12{ sqrt {3} } {} ). These two expressions, identical except for the replacement of a+ by a- , are known as conjugates . What happens when we multiply them? We don’t need to use FOIL if we remember that

( x + y ) ( x - y ) = x 2 - y 2

Using this formula, we see that

( 1 + 3 ) ( 1 - 3 ) = 1 2 - ( 3 ) 2 = 1 - 3 = - 2

So the square root does indeed go away. We can use this to simplify the original expression as follows.

Rationalizing using the conjugate of the denominator

12 1 + 3 size 12{ { { sqrt {"12"} } over {1+ sqrt {3} } } } {} = 12 ( 1 - 3 ) ( 1 + 3 ) ( 1 - 3 ) = 12 - 36 1 - 3 = 2 3 - 6 -2 = - 3 + 3

As always, you may want to check this on your calculator. Both the original and the simplified expression are approximately 1.268.

Of course, the process is the same when variables are involved.

Rationalizing with variables

1 x x size 12{ { {1} over {x - sqrt {x} } } } {} = 1 x + x x x x + x size 12{ { {1 left (x+ sqrt {x} right )} over { left (x - sqrt {x} right ) left (x+ sqrt {x} right )} } } {} = x + x x 2 x size 12{ { {x+ sqrt {x} } over {x rSup { size 8{2} } - x} } } {}

Once again, we multiplied the top and the bottom by the conjugate of the denominator : that is, we replaced a- with a+ . The formula ( x + a ) ( x - a ) = x 2 - a 2 enabled us to quickly multiply the terms on the bottom, and eliminated the square roots in the denominator.

Questions & Answers

How we are making nano material?
LITNING Reply
what is a peer
LITNING Reply
What is meant by 'nano scale'?
LITNING Reply
What is STMs full form?
LITNING
scanning tunneling microscope
Sahil
what is Nano technology ?
Bob Reply
write examples of Nano molecule?
Bob
The nanotechnology is as new science, to scale nanometric
brayan
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Damian
Is there any normative that regulates the use of silver nanoparticles?
Damian Reply
what king of growth are you checking .?
Renato
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
Stoney Reply
why we need to study biomolecules, molecular biology in nanotechnology?
Adin Reply
?
Kyle
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
Adin
why?
Adin
what school?
Kyle
biomolecules are e building blocks of every organics and inorganic materials.
Joe
anyone know any internet site where one can find nanotechnology papers?
Damian Reply
research.net
kanaga
sciencedirect big data base
Ernesto
Introduction about quantum dots in nanotechnology
Praveena Reply
what does nano mean?
Anassong Reply
nano basically means 10^(-9). nanometer is a unit to measure length.
Bharti
do you think it's worthwhile in the long term to study the effects and possibilities of nanotechnology on viral treatment?
Damian Reply
absolutely yes
Daniel
how to know photocatalytic properties of tio2 nanoparticles...what to do now
Akash Reply
it is a goid question and i want to know the answer as well
Maciej
characteristics of micro business
Abigail
for teaching engĺish at school how nano technology help us
Anassong
How can I make nanorobot?
Lily
Do somebody tell me a best nano engineering book for beginners?
s. Reply
there is no specific books for beginners but there is book called principle of nanotechnology
NANO
how can I make nanorobot?
Lily
what is fullerene does it is used to make bukky balls
Devang Reply
are you nano engineer ?
s.
fullerene is a bucky ball aka Carbon 60 molecule. It was name by the architect Fuller. He design the geodesic dome. it resembles a soccer ball.
Tarell
what is the actual application of fullerenes nowadays?
Damian
That is a great question Damian. best way to answer that question is to Google it. there are hundreds of applications for buck minister fullerenes, from medical to aerospace. you can also find plenty of research papers that will give you great detail on the potential applications of fullerenes.
Tarell
what is the Synthesis, properties,and applications of carbon nano chemistry
Abhijith Reply
Mostly, they use nano carbon for electronics and for materials to be strengthened.
Virgil
is Bucky paper clear?
CYNTHIA
carbon nanotubes has various application in fuel cells membrane, current research on cancer drug,and in electronics MEMS and NEMS etc
NANO
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
Privacy Information Security Software Version 1.1a
Good
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get the best Algebra and trigonometry course in your pocket!





Source:  OpenStax, Radicals. OpenStax CNX. Mar 03, 2011 Download for free at http://cnx.org/content/col11280/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Radicals' conversation and receive update notifications?

Ask