# 0.2 Practice tests (1-4) and final exams  (Page 33/36)

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The number of people living on American farms has declined steadily during the 20 th century. Here are data on the farm population (in millions of persons) from 1935 to 1980.

Year 1935 1940 1945 1950 1955 1960 1965 1970 1975 1980
Population 32.1 30.5 24.4 23.0 19.1 15.6 12.4 9.7 8.9 7.2

31 . The linear regression equation is $\stackrel{^}{y}$ = 1166.93 – 0.5868 x . What was the expected farm population (in millions of persons) for 1980?

1. 7.2
2. 5.1
3. 6.0
4. 8.0

32 . In linear regression, which is the best possible SSE ?

1. 13.46
2. 18.22
3. 24.05
4. 16.33

33 . In regression analysis, if the correlation coefficient is close to one what can be said about the best fit line?

1. It is a horizontal line. Therefore, we can not use it.
2. There is a strong linear pattern. Therefore, it is most likely a good model to be used.
3. The coefficient correlation is close to the limit. Therefore, it is hard to make a decision.
4. We do not have the equation. Therefore, we cannot say anything about it.

Use the following information to answer the next three exercises: A study of the career plans of young women and men sent questionnaires to all 722 members of the senior class in the College of Business Administration at the University of Illinois. One question asked which major within the business program the student had chosen. Here are the data from the students who responded.

Female Male
Accounting 68 56
Economics 5 6
Finance 61 59

34 . The distribution for the test is:

1. ${{\mathrm{Chi}}^{2}}_{8}$ .
2. ${{\mathrm{Chi}}^{2}}_{3}$ .
3. ${t}_{721}$ .
4. $N\left(0,1\right)$ .

35 . The expected number of female who choose finance is:

1. 37.
2. 61.
3. 60.
4. 70.

36 . The p -value is 0.0127 and the level of significance is 0.05. The conclusion to the test is:

1. there is insufficient evidence to conclude that the choice of major and the gender of the student are not independent of each other.
2. there is sufficient evidence to conclude that the choice of major and the gender of the student are not independent of each other.
3. there is sufficient evidence to conclude that students find economics very hard.
4. there is in sufficient evidence to conclude that more females prefer administration than males.

37 . An agency reported that the work force nationwide is composed of 10% professional, 10% clerical, 30% skilled, 15% service, and 35% semiskilled laborers. A random sample of 100 San Jose residents indicated 15 professional, 15 clerical, 40 skilled, 10 service, and 20 semiskilled laborers. At α = 0.10 does the work force in San Jose appear to be consistent with the agency report for the nation? Which kind of test is it?

1. Chi 2 goodness of fit
2. Chi 2 test of independence
3. Independent groups proportions
4. Unable to determine

## Solutions

1 . b. independent

2 . c. $\frac{4}{16}\text{}$

3 . b. Two measurements are drawn from the same pair of individuals or objects.

4 . b. $\frac{68}{118}\text{}$

5 . d. $\frac{30}{52}\text{}$

6 . b. $\frac{8}{40}\text{}$

7 . b. 2.78

8 . a. 8.25

9 . c. 0.2870

10 . c. Normal

11 . d. H a : p A p B

12 . b. conclude that the pass rate for Math 1A is different than the pass rate for Math 1B when, in fact, the pass rates are the same.

13 . b. not reject H 0

binomial distribution tends to normal distribution
if sample size n very large and probability tends to 0.5 if these both conditions are satisfied by binomial distribution it would tends to normal distribution
sravani
n tends to infinite i.e large Probability tends to 0 i.e indefinitely small. np = lamda
Anji
the above is poison to Bin
Anji
no of trails n tends to indefinitely large..i.e infine neither p nor q is very small Then bin tends to normal
Anji
if the death of of the snow is my yard is normally distributed with the m is equals to 2.5 and what is the probability that a randomly chosen location with have a no that between 2.25 and 2.76
hey
Shubham
🤔
Iqra
hello
Sakshi
hii
Rushikesh
helow
why Statistics so hard
Mohd
ho geya solve
Sakshi
it's not hard
Sakshi
it is hard 😭
Mohd
solution?
Abdul
hii
it's just need to be concentrate
Akinyemi
exactly..... concentration is very important
Iqra
rewrite the question
what is the true statement about random variable?
A consumer advocate agency wants to estimate the mean repair cost of a washing machine. the agency randomly selects 40 repair cost and find the mean to be $100.00.The standards deviation is$17.50. Construct a 90% confidence interval for the mean.
pls I need understand this statistics very will is giving me problem
Sixty-four third year high school students were given a standardized reading comprehension test. The mean and standard deviation obtained were 52.27 and 8.24, respectively. Is the mean significantly different from the population mean of 50? Use the 5% level of significance.
No
Ariel
how do I find the modal class
look for the highest occuring number in the class
Kusi
the probability of an event occuring is defined as?
The probability of an even occurring is expected event÷ event being cancelled or event occurring / event not occurring
Gokuna
what is simple bar chat
Simple Bar Chart is a Diagram which shows the data values in form of horizontal bars. It shows categories along y-axis and values along x-axis. The x-axis displays above the bars and y-axis displays on left of the bars with the bars extending to the right side according to their values.
statistics is percentage only
the first word is chance for that we use percentages
it is not at all that statistics is a percentage only
Shambhavi
I need more examples
how to calculate sample needed
mole of sample/mole ratio or Va Vb
Gokuna
how to I solve for arithmetic mean
Yeah. for you to say.
James
yes
niharu
how do I solve for arithmetic mean
niharu
add all the data and divide by the number of data sets. For example, if test scores were 70, 60, 70, 80 the total is 280 and the total data sets referred to as N is 4. Therfore the mean or arthritmatic average is 70. I hope this helps.
Jim
*Tan A - Tan B = sin(A-B)/CosA CosB ... *2sinQ/Cos 3Q = tan 3Q - tan Q