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27 . The predicted value for y is: y ^ = 2.3 – 0.1(4.1) = 1.89. The value of 2.32 is more than two standard deviations from the predicted value, so it qualifies as an outlier.
Residual for (4.1, 2.34): 2.32 – 1.89 = 0.43 (0.43>2(0.13))

13.1: one-way anova

28 .

  1. Each sample is drawn from a normally distributed population
  2. All samples are independent and randomly selected.
  3. The populations from which the samples are draw have equal standard deviations.
  4. The factor is a categorical variable.
  5. The response is a numerical variable.

29 . H 0 : μ 1 = μ 2 = μ 3 = μ 4
H a : At least two of the group means μ 1, μ 2, μ 3, μ 4 are not equal.

30 . The independent samples t -test can only compare means from two groups, while one-way ANOVA can compare means of more than two groups.

31 . Each sample appears to have been drawn from a normally distributed populations, the factor is a categorical variable (method), the outcome is a numerical variable (test score), and you were told the samples were independent and randomly selected, so those requirements are met. However, each sample has a different standard deviation, and this suggests that the populations from which they were drawn also have different standard deviations, which is a violation of an assumption for one-way ANOVA. Further statistical testing will be necessary to test the assumption of equal variance before proceeding with the analysis.

32 . One of the assumptions for a one-way ANOVA is that the samples are drawn from normally distributed populations. Since two of your samples have an approximately uniform distribution, this casts doubt on whether this assumption has been met. Further statistical testing will be necessary to determine if you can proceed with the analysis.

13.2: the F Distribution

33 . SS within is the sum of squares within groups, representing the variation in outcome that cannot be attributed to the different feed supplements, but due to individual or chance factors among the calves in each group.

34 . SS between is the sum of squares between groups, representing the variation in outcome that can be attributed to the different feed supplements.

35 . k = the number of groups = 4
n 1 = the number of cases in group 1 = 30
n = the total number of cases = 4(30) = 120

36 . SS total = SS within + SS between so SS between = SS total SS within
621.4 – 374.5 = 246.9

37 . The mean squares in an ANOVA are found by dividing each sum of squares by its respective degrees of freedom ( df ).
For SS total , df = n – 1 = 120 – 1 = 119.
For SS between , df = k – 1 = 4 – 1 = 3.
For SS within , df = 120 – 4 = 116.
MS between = 246.9 3 = 82.3
MS within = 374.5 116 = 3.23

38 . F = M S b e t w e e n M S w i t h i n = 82.3 3.23 = 25.48

39 . It would be larger, because you would be dividing by a smaller number. The value of MS between would not change with a change of sample size, but the value of MS within would be smaller, because you would be dividing by a larger number ( df within would be 136, not 116). Dividing a constant by a smaller number produces a larger result.

13.3: facts about the F Distribution

40 . All but choice c, –3.61. F Statistics are always greater than or equal to 0.

Questions & Answers

Suppose from the 1,000 freshmen that took the entrance examination, it was found out that the standard deviation was 10 a. How many students passed the test if the passing score is set 75? b. What scores comprise the middle 95% of all scores?
Sweet Reply
Hi
HAYATUL
can you answer my question.
Sweet
during a prize distribution ceremony the first 10 students of a class where are asked to take their seats in the first roar of 10 seats according to their preference .what is the probability that they will sit in the order of their ranks?
Punam Reply
10%
ATTAH
In a survey of 100 stocks on NASDAQ, the average percent increase for the past year was 9% for NASDAQ stocks.
Noor Reply
what is primary data and it's various types of collection of data?
Xaib Reply
If a random variable X takes only two values -2 and 1 such that 2 P[X=- 2]=P[X=1]=P, then find variance of x.
Dikshita Reply
2.5
Anirban
how!
Alif
can u show the solution pls?
Punam
the mean of random variable following binomial distribution is 10. the numbers of trails are 30. What the approximate value of variance?
AMIT Reply
what is chis square
Remelyn Reply
A chi-square (χ2) statistic is a test that measures how a model compares to actual observed data.
kalim
descriptive statistics basic
Sangeetha
Hi Friends
Sangeetha
tamil people yaaraavathu irukkingala
Sangeetha
what is the median of the following set of number:3,3,3,4,5,6,7,8,8,9?
Sur Reply
3
Mbemah
5.6
Alekya
(5+6)/2=5.5555.......=5.6
Lyrical
(5+6)/2=5.5 that is the median
moniba
hi friends am new here, hope am welcome
nathan
hi friends am new here, hope am welcome
nathan
1.5
nathan
differences between Intervals and Ratio measurement scales
VIP Reply
interval is the distinct from a starting point to the peak of a certain distance
Mbemah
the taking of a certain range accurately in a divisional way
Mbemah
i need the solution for exercise sums
Siva Reply
descriptive statistics sums I need
Sangeetha
statistics discovered?
Kaleem Reply
internet
Kamranali
dev OS
Virendra
searching for motivation to learn stat
Nija
purpose of of statistics
mukesh
ya..
mukesh
tamil people yaraavathu inrukkingala
Sangeetha
Odisha ru kau bhai mane achha?
Hemanta
I want to learn my MSC by statistics who can help me ?
Abebe
@Avirup interest person
Abebe
good morning
Sangeetha
Dr good morning
mukhtar
in statistical inferences we use population parameter to infer sample statistics
anupama Reply
Yes
lukman
how do we calculate decile
Drix Reply
how do we calculate class boundaries
Syed
The lower class boundary is found by subtracting 0.5 units from the lowerclass limit and the upper class boundary is found by adding 0.5 units to the upper class limit. The difference between the upper and lowerboundaries of any class.
Ekene
The lower class boundary is found by subtracting 0.5 units from the lowerclass limit and the upper class boundary is found by adding 0.5 units to the upper class limit. The difference between the upper and lowerboundaries of any class.
Ekene
complete definition plz
Zarifa Reply
what are the advantages and disadvantages of primary and secondary data
Elisha Reply
advantage of primary data 1) specific 2) Accurate 3)ownership 4)up to date information 5) control Disadvantage of primary data 1) Expensive 2) time consuming 3) feasibility.
Xaib

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Source:  OpenStax, Introductory statistics. OpenStax CNX. May 06, 2016 Download for free at http://legacy.cnx.org/content/col11562/1.18
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