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Equations of motion

  1. A car starts off at 10 m · s - 1 and accelerates at 1 m · s - 2 for 10 s. What is its final velocity?
  2. A train starts from rest, and accelerates at 1 m · s - 2 for 10 s. How far does it move?
  3. A bus is going 30 m · s - 1 and stops in 5 s. What is its stopping distance for this speed?
  4. A racing car going at 20 m · s - 1 stops in a distance of 20 m. What is its acceleration?
  5. A ball has a uniform acceleration of 4 m · s - 1 . Assume the ball starts from rest. Determine the velocity and displacement at the end of 10 s.
  6. A motorcycle has a uniform acceleration of 4 m · s - 1 . Assume the motorcycle has an initial velocity of 20 m · s - 1 . Determine the velocity and displacement at the end of 12 s.
  7. An aeroplane accelerates uniformly such that it goes from rest to 144 km · hr - 1 in 8 s. Calculate the acceleration required and the total distance that it has traveled in this time.

Applications in the real-world

What we have learnt in this chapter can be directly applied to road safety. We can analyse the relationship between speed and stopping distance. The following worked example illustrates this application.

A truck is travelling at a constant velocity of 10 m · s - 1 when the driver sees a child 50 m in front of him in the road. He hits the brakes to stop the truck. The truck accelerates at a rate of -1.25 m · s - 2 . His reaction time to hit the brakes is 0,5 seconds. Will the truck hit the child?

  1. It is useful to draw a timeline like this one:

    We need to know the following:

    • What distance the driver covers before hitting the brakes.
    • How long it takes the truck to stop after hitting the brakes.
    • What total distance the truck covers to stop.
  2. Before the driver hits the brakes, the truck is travelling at constant velocity. There is no acceleration and therefore the equations of motion are not used. To find the distance traveled, we use:

    v = D t 10 = d 0 , 5 d = 5 m

    The truck covers 5 m before the driver hits the brakes.

  3. We have the following for the motion between B and C:

    v i = 10 m · s - 1 v f = 0 m · s - 1 a = - 1 , 25 m · s - 2 t = ?

    We can use [link]

    v f = v i + a t 0 = 10 + ( - 1 , 25 ) t - 10 = - 1 , 25 t t = 8 s
  4. For the distance we can use [link] or [link] . We will use [link] :

    Δ x = ( v i + v f ) 2 t Δ x = 10 + 0 s ( 8 ) Δ x = 40 m
  5. The total distance that the truck covers is D A B + D B C = 5 + 40 = 45 meters . The child is 50 meters ahead. The truck will not hit the child.

Summary

  • A reference point is a point from where you take your measurements.
  • A frame of reference is a reference point with a set of directions.
  • Your position is where you are located with respect to your reference point.
  • The displacement of an object is how far it is from the reference point. It is the shortest distance between the object and the reference point. It has magnitude and direction because it is a vector.
  • The distance of an object is the length of the path travelled from the starting point to the end point. It has magnitude only because it is a scalar.
  • A vector is a physical quantity with magnitude and direction.
  • A scalar is a physical quantity with magnitude only.
  • Speed ( s ) is the distance covered ( D ) divided by the time taken ( Δ t ):
    s = D Δ t
  • Average velocity ( v ) is the displacement ( Δ x ) divided by the time taken ( Δ t ):
    v = Δ x Δ t
  • Instantaneous speed is the speed at a specific instant in time.
  • Instantaneous velocity is the velocity at a specific instant in time.
  • Acceleration ( a ) is the change in velocity ( Δ x ) over a time interval ( Δ t ):
    a = Δ v Δ t
  • The gradient of a position - time graph ( x vs. t ) give the velocity.
  • The gradient of a velocity - time graph ( v vs. t ) give the acceleration.
  • The area under a velocity - time graph ( v vs. t ) give the displacement.
  • The area under an acceleration - time graph ( a vs. t ) gives the velocity.
  • The graphs of motion are summarised in [link] .
  • The equations of motion are used where constant acceleration takes place:
    v f = v i + a t Δ x = ( v i + v f ) 2 t Δ x = v i t + 1 2 a t 2 v f 2 = v i 2 + 2 a Δ x

End of chapter exercises: motion in one dimension

  1. Give one word/term for the following descriptions.
    1. The shortest path from start to finish.
    2. A physical quantity with magnitude and direction.
    3. The quantity defined as a change in velocity over a time period.
    4. The point from where you take measurements.
    5. The distance covered in a time interval.
    6. The velocity at a specific instant in time.
  2. Choose an item from column B that match the description in column A. Write down only the letter next to the question number. You may use an item from column B more than once.
    Column A Column B
    a. The area under a velocity - time graph gradient
    b. The gradient of a velocity - time graph area
    c. The area under an acceleration - time graph velocity
    d. The gradient of a displacement - time graph displacement
    acceleration
    slope
  3. Indicate whether the following statements are TRUE or FALSE. Write only 'true' or 'false'. If the statement is false, write down the correct statement.
    1. A scalar is the displacement of an object over a time interval.
    2. The position of an object is where it is located.
    3. The sign of the velocity of an object tells us in which direction it is travelling.
    4. The acceleration of an object is the change of its displacement over a period in time.
  4. [SC 2003/11] A body accelerates uniformly from rest for t 0 seconds after which it continues with a constant velocity. Which graph is the correct representation of the body's motion?
    (a) (b) (c) (d)
  5. [SC 2003/11] The velocity-time graphs of two cars are represented by P and Q as shown
    The difference in the distance travelled by the two cars (in m) after 4 s is ...
    1. 12
    2. 6
    3. 2
    4. 0
  6. [IEB 2005/11 HG] The graph that follows shows how the speed of an athlete varies with time as he sprints for 100 m.
    Which of the following equations can be used to correctly determine the time t for which he accelerates?
    1. 100 = ( 10 ) ( 11 ) - 1 2 ( 10 ) t
    2. 100 = ( 10 ) ( 11 ) + 1 2 ( 10 ) t
    3. 100 = 10 t + 1 2 ( 10 ) t 2
    4. 100 = 1 2 ( 0 ) t + 1 2 ( 10 ) t 2
  7. [SC 2002/03 HG1] In which one of the following cases will the distance covered and the magnitude of the displacement be the same?
    1. A girl climbs a spiral staircase.
    2. An athlete completes one lap in a race.
    3. A raindrop falls in still air.
    4. A passenger in a train travels from Cape Town to Johannesburg.
  8. [SC 2003/11] A car, travelling at constant velocity, passes a stationary motor cycle at a traffic light. As the car overtakes the motorcycle, the motorcycle accelerates uniformly from rest for 10 s. The following displacement-time graph represents the motions of both vehicles from the traffic light onwards.
    1. Use the graph to find the magnitude of the constant velocity of the car.
    2. Use the information from the graph to show by means of calculation that the magnitude of the acceleration of the motorcycle, for the first 10 s of its motion is 7,5 m · s - 2 .
    3. Calculate how long (in seconds) it will take the motorcycle to catch up with the car (point X on the time axis).
    4. How far behind the motorcycle will the car be after 15 seconds?
  9. [IEB 2005/11 HG] Which of the following statements is true of a body that accelerates uniformly?
    1. Its rate of change of position with time remains constant.
    2. Its position changes by the same amount in equal time intervals.
    3. Its velocity increases by increasing amounts in equal time intervals.
    4. Its rate of change of velocity with time remains constant.
  10. [IEB 2003/11 HG1] The velocity-time graph for a car moving along a straight horizontal road is shown below.
    Which of the following expressions gives the magnitude of the average velocity of the car?
    1. Area A t
    2. Area A + Area B t
    3. Area B t
    4. Area A - Area B t
  11. [SC 2002/11 SG] A car is driven at 25 m · s - 1 in a municipal area. When the driver sees a traffic officer at a speed trap, he realises he is travelling too fast. He immediately applies the brakes of the car while still 100 m away from the speed trap.
    1. Calculate the magnitude of the minimum acceleration which the car must have to avoid exceeding the speed limit, if the municipal speed limit is 16.6 m · s - 1 .
    2. Calculate the time from the instant the driver applied the brakes until he reaches the speed trap. Assume that the car's velocity, when reaching the trap, is 16.6 m · s - 1 .
  12. A traffic officer is watching his speed trap equipment at the bottom of a valley. He can see cars as they enter the valley 1 km to his left until they leave the valley 1 km to his right. Nelson is recording the times of cars entering and leaving the valley for a school project. Nelson notices a white Toyota enter the valley at 11:01:30 and leave the valley at 11:02:42. Afterwards, Nelson hears that the traffic officer recorded the Toyota doing 140 km · hr - 1 .
    1. What was the time interval ( Δ t ) for the Toyota to travel through the valley?
    2. What was the average speed of the Toyota?
    3. Convert this speed to km · hr - 1 .
    4. Discuss whether the Toyota could have been travelling at 140km · hr - 1 at the bottom of the valley.
    5. Discuss the differences between the instantaneous speed (as measured by the speed trap) and average speed (as measured by Nelson).
  13. [IEB 2003/11HG] A velocity-time graph for a ball rolling along a track is shown below. The graph has been divided up into 3 sections, A, B and C for easy reference. (Disregard any effects of friction.)
    1. Use the graph to determine the following:
      1. the speed 5 s after the start
      2. the distance travelled in Section A
      3. the acceleration in Section C
    2. At time t 1 the velocity-time graph intersects the time axis. Use an appropriate equation of motion to calculate the value of time t 1 (in s).
    3. Sketch a displacement-time graph for the motion of the ball for these 12 s. (You do not need to calculate the actual values of the displacement for each time interval, but do pay attention to the general shape of this graph during each time interval.)
  14. In towns and cities, the speed limit is 60 km · hr - 1 . The length of the average car is 3.5 m, and the width of the average car is 2 m. In order to cross the road, you need to be able to walk further than the width of a car, before that car reaches you. To cross safely, you should be able to walk at least 2 m further than the width of the car (4 m in total), before the car reaches you.
    1. If your walking speed is 4 km · hr - 1 , what is your walking speed in m · s - 1 ?
    2. How long does it take you to walk a distance equal to the width of the average car?
    3. What is the speed in m · s - 1 of a car travelling at the speed limit in a town?
    4. How many metres does a car travelling at the speed limit travel, in the same time that it takes you to walk a distance equal to the width of car?
    5. Why is the answer to the previous question important?
    6. If you see a car driving toward you, and it is 28 m away (the same as the length of 8 cars), is it safe to walk across the road?
    7. How far away must a car be, before you think it might be safe to cross? How many car-lengths is this distance?
  15. A bus on a straight road starts from rest at a bus stop and accelerates at 2 m · s - 2 until it reaches a speed of 20 m · s - 1 . Then the bus travels for 20 s at a constant speed until the driver sees the next bus stop in the distance. The driver applies the brakes, stopping the bus in a uniform manner in 5 s.
    1. How long does the bus take to travel from the first bus stop to the second bus stop?
    2. What is the average velocity of the bus during the trip?

Questions & Answers

I only see partial conversation and what's the question here!
Crow Reply
what about nanotechnology for water purification
RAW Reply
please someone correct me if I'm wrong but I think one can use nanoparticles, specially silver nanoparticles for water treatment.
Damian
what is the stm
Brian Reply
is there industrial application of fullrenes. What is the method to prepare fullrene on large scale.?
Rafiq
industrial application...? mmm I think on the medical side as drug carrier, but you should go deeper on your research, I may be wrong
Damian
How we are making nano material?
LITNING Reply
what is a peer
LITNING Reply
What is meant by 'nano scale'?
LITNING Reply
What is STMs full form?
LITNING
scanning tunneling microscope
Sahil
how nano science is used for hydrophobicity
Santosh
Do u think that Graphene and Fullrene fiber can be used to make Air Plane body structure the lightest and strongest. Rafiq
Rafiq
what is differents between GO and RGO?
Mahi
what is simplest way to understand the applications of nano robots used to detect the cancer affected cell of human body.? How this robot is carried to required site of body cell.? what will be the carrier material and how can be detected that correct delivery of drug is done Rafiq
Rafiq
what is Nano technology ?
Bob Reply
write examples of Nano molecule?
Bob
The nanotechnology is as new science, to scale nanometric
brayan
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Damian
Is there any normative that regulates the use of silver nanoparticles?
Damian Reply
what king of growth are you checking .?
Renato
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
Stoney Reply
why we need to study biomolecules, molecular biology in nanotechnology?
Adin Reply
?
Kyle
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
Adin
why?
Adin
what school?
Kyle
biomolecules are e building blocks of every organics and inorganic materials.
Joe
anyone know any internet site where one can find nanotechnology papers?
Damian Reply
research.net
kanaga
sciencedirect big data base
Ernesto
Introduction about quantum dots in nanotechnology
Praveena Reply
what does nano mean?
Anassong Reply
nano basically means 10^(-9). nanometer is a unit to measure length.
Bharti
do you think it's worthwhile in the long term to study the effects and possibilities of nanotechnology on viral treatment?
Damian Reply
absolutely yes
Daniel
how to know photocatalytic properties of tio2 nanoparticles...what to do now
Akash Reply
it is a goid question and i want to know the answer as well
Maciej
characteristics of micro business
Abigail
for teaching engĺish at school how nano technology help us
Anassong
How can I make nanorobot?
Lily
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Source:  OpenStax, Physics - grade 10 [caps 2011]. OpenStax CNX. Jun 14, 2011 Download for free at http://cnx.org/content/col11298/1.3
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