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That's it for dsp029

That's about it for the program named Dsp029 . If you understand this program, you are well ahead of the game. The overall structurefor the programs named Dsp028 and Dsp030 are very similar to the structure for Dsp029 . The big difference is the manner in which they populate the array objects with the data that is to beplotted. Instead of simply plotting sinusoids, they perform spectral analysis on sinusoids and provide the results of the spectral analysis to be plotted.

Using the interface named graphintfc01

As you learned earlier, this is a very simple interface. However, because the class named Dsp029 implements the interface, the interface definition file must be in the same directory as the source file for Dsp029 in order to successfully compile Dsp029 . Therefore, I have provided a complete listing of GraphIntfc01 in Listing 17 near the end of the module.

The program named Graph06

A complete listing of the program named Graph06 is provided in Listing 18 near the end of the module. This is simply a newer version of graphics display programs that I explained in the earlier module titled Plotting Engineering and Scientific Data using Java . Therefore, I won't repeat that explanation here. The comments at the beginning and spreadthroughout the program provide considerable information about it.

Operational aspects of graph06

However, an explanation of the operational aspects of the program will be useful here. You can use this program to display the output produced by Dsp029 by entering the following at the command line prompt:

java Graph06 Dsp029

As you saw in Figure 3 and other previous figures, this program provides the following text fields for user input, along with a button labeled Graph :

  • xMin = minimum x-axis value
  • xMax = maximum x-axis value
  • yMin = minimum y-axis value
  • yMax = maximum y-axis value
  • xTicInt = tic interval on x-axis
  • yTicInt = tic interval on y-axis
  • xCalcInc = calculation interval

These text fields make it possible for you to adjust the plotting parameters and to re-plot the graphs as many times as needed.

You can modify any of these parameters and then click the Graph button to cause the five functions to be re-plotted according to the newplotting parameters.

Spectral Analysis using a DFT Algorithm

Now that you have a good idea where we are heading, it's time to start doing some spectral analysis.

Let's begin by looking at some output obtained by performing a spectral analysis on the same five sinusoids shown in Figure 3 . The parameters used to perform this spectral analysis are shown in Figure 8 . (I will explain each of these parameters as we go along.)

Figure 8. Parameters for spectral analysis.
Data length: 400 Sample for zero time: 0Lower frequency bound: 0.0 Upper frequency bound: 1.0Number spectra: 5 Frequencies0.03125 0.06250.125 0.250.5 Amplitudes90.0 90.090.0 90.090.0

Although more parameters are required to perform spectral analysis than are required to simply generate and plot the sinusoids, the number of sinusoids, thefrequencies of the sinusoids, and the amplitudes of the sinusoids in Figure 8 are the same as in Figure 2 .

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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