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This method accepts an incoming complex sample value and the position in the series associated with that sample. The method corrects the real and imaginarytransform values for that complex sample to reflect the specified position in the input series.

After correcting the transform values for the sample on the basis of position, the method updates the corresponding real and imaginary valuescontained in array objects that are used to accumulate the real and imaginary values for all of the samples.

References to the array objects are received as input parameters. Outgoing results are scaled by an incoming parameter in an attempt to cause the outputvalues to fall within a reasonable range in case someone wants to plot them.

The incoming parameter named length specifies the number of output samples that are to be produced.

Hopefully this explanation will make it possible for you to understand the code in Listing 4 .

Note in particular the use of the Math.cos and Math.sin methods to apply the cosine and sine curves in the correction of the transforms of the individual complex samples. This is used to produceresults similar to those shown in Figure 5 through Figure 7 .

A real FFT program would probably compute the cosine and sine values only once, put them in a table and extract them from the table when needed.

Note the use of the position and length parameters in the computation of the angle that is passed as an argument to the Math.cos and Math.sin methods.

Also note how the correction is made separately on the real and imaginary parts of the input. This produces results similar to those shown in Figure 7 after those results are added in the accumulators.

Back to the main method

Returning now to the main method, the code in Listing 5 prepares the input data and the output arrays for the first case that we will look at. This case islabeled as Case A.

Listing 5. The remainder of the main method.
System.out.println("Case A"); double[]realInA = {0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1};double[] imagInA ={0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0}; double[]realOutA = new double[16];double[] imagOutA = new double[16]; //Perform the transform and display the// transformed results for the original // complex series.transform.doIt(realInA,imagInA,2.0,realOutA, imagOutA);display(realOutA,imagOutA);

Note that for Case A, the input complex series contains non-zero values only in the real part. Also, most of the values in the real part are zero.

The graphic form of Case A

Case A is shown in graphic form in Figure 9 . As you can see, the input series consists of two non-zero values in the real part. All the values in theimaginary part are zero.

Figure 9. Case A. Transform of a real sample with two non-zero values.
missing image

The real part of the transform of the complex input series looks like one cycle of a cosine curve. All of the values in the imaginary part of thetransform result are zero.

The numeric output for Case A

As you saw in Listing 5 , the code in the main method calls a method named display to display the complex transform output in numeric form on the screen. The output produced by Listing 5 is shown in Figure 10 . (Note that I manually inserted line breaks to force the material to fit in this narrowpublication format.)

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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