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The real part of the spectrum is symmetrical

The real part of the complex spectrum is shown in the second plot from the top in Figure 1 . It will become important later to note that the real part of the spectrum is symmetrical about the folding frequency near the center of theplot (at the eighth tick mark) .

Without attempting to explain why, I will simply tell you that the real part of the Fourier transform of a complex series whose imaginary part is all zeros (like a typical sampled time series for real-world data) is always symmetrical about the folding frequency.

The imaginary part of the spectrum is asymmetrical

The imaginary part of the complex spectrum is shown in the third plot from the top. Again, it will become important later to note that the imaginary partof the spectrum is asymmetrical about the folding frequency.

Once again, without attempting to explain why, the imaginary part of the Fourier transform of a complex series whose imaginary part is all zeros (like a typical sampled time series for real-world data) is always asymmetrical about the folding frequency.

The converse is also true

It is also true that the values of the imaginary part of the Fourier transform of a complex spectrum whose real part is symmetrical about the foldingfrequency and whose imaginary part is asymmetrical about the folding frequency will all be zero. I will take advantage of these facts later to simplify thecomputing and plotting process.

The amplitude spectrum

The amplitude spectrum is shown in the fourth plot down from the top. Recall from previous modules that the amplitude values are always positive, consistingof the square root of the sum of the squares of the real and imaginary parts.

The output time series

The output time series, produced by performing an inverse Fourier transform on the complex spectrum is shown in the bottom plot in Figure 1 . Compare the bottom plot to the top plot. As you can see, they are the same, demonstratingthe reversible nature of the Fourier transform.

The program named Dsp035

I will discuss this program in fragments. A complete listing of the program is provided in Listing 14 near the end of the module.

The beginning of the class named Dsp035

The beginning of the class for Dsp035 , including the declaration of some variables and the creation of some array objects is shown in Listing 1 . This code is straightforward.

Listing 1. The beginning of the class named Dsp035.
class Dsp035 implements GraphIntfc01{ final double pi = Math.PI;int len = 256; double[]timeDataIn = new double[len];double[] realSpect = new double[len]; double[]imagSpect = new double[len];double[] angle = new double[len];//unused double[]magnitude = new double[len];double[] timeDataOut = new double[len];

Beginning of the constructor

The constructor begins in Listing 2 . The code in Listing 2 creates the input time series data shown in the top plot of Figure 1 .

Listing 2. Beginning of the constructor.
public Dsp035(){//constructor //Create the raw data pulsestimeDataIn[0] = 0;timeDataIn[1] = 50;//... //code deleted for brevity//... timeDataIn[254]= -80; timeDataIn[255]= -80; //Create raw data sinusoidfor(int x = len/3;x<3*len/4;x++){ timeDataIn[x]= 80.0 * Math.sin( 2*pi*(x)*1.0/20.0);}//end for loop

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
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Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
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Mulaudzi Reply
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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