<< Chapter < Page Chapter >> Page >

This is illustrated by the program in Listing 5 . This program contains an overridden version of a superclass method named meth . The subclass version uses the value of an incoming parameter to decide whether to call thesuperclass version and then to call some of its own code, or to execute its own code exclusively.

Listing 5 . The program named Super4 .
/*File Super4.java Copyright 2002, R.G.BaldwinIllustrates calling the superclass version of an overridden method fromcode in the subclass version. Tested using JDK 1.4.0 under Win 2000.The output from this program is: In mainEntering overridden method in subclass Incoming parameter is falseSubclass version only is called Back in or still in subclass versionGoodbye from subclass version Entering overridden method in subclassIncoming parameter is true SuperClass method calledBack in or still in subclass version Goodbye from subclass versionBack in main **************************************/class SuperClass{ //Following method is overridden in// the subclass. void meth(boolean par){System.out.println( "Incoming parameter is " + par);System.out.println( "SuperClass method called");}//end meth }//end SuperClass class definition//===================================// class Super4 extends SuperClass{//Following method overrides method // in the superclassvoid meth(boolean par){ System.out.println("Entering overridden method " + "in subclass");//Decide whether to call // superclass versionif(par) //Call superclass versionsuper.meth(par); else{//Don't call superclass version System.out.println("Incoming parameter is " + par); System.out.println("Subclass version only is " + "called");}//end else //Execute some additional codeSystem.out.println( "Back in or still in subclass "+ "version"); System.out.println("Goodbye from subclass version"); System.out.println();//blank line}//end overridden meth() //---------------------------------//public static void main( String[]args){ //instantiate an object of// this type Super4 obj = new Super4();System.out.println("In main"); //Call overridden version of// method obj.meth(false);//Call superclass version of // methodobj.meth(true); System.out.println("Back in main");}//end main method }//End Super4 class definition.

Only one statement contains super

The super keyword is used in only one statement in the program in Listing 5 . That statement appears in the subclass version of an overridden method, and is as follows:

super.meth(par);

This statement is inside the body of an if statement. If the value of par is true, then this statement is executed, causing the superclass version of the method named meth to be executed (passing the value of par as a parameter to the superclass method). When the method returns, the remaining code in the subclass version of the method is executed.

If the value of par is false, the above statement is bypassed, and the superclass version of the method doesn't get executed. In this case, only thecode in the subclass version is executed.

Summary

I have discussed and illustrated the use of the this keyword in the following common situations:

  • To bypass local variables or parameters that hide member variables having the same name, in order to access the member variable.
  • To make it possible for one overloaded constructor to call another overloaded constructor in the same class.
  • To pass a reference to the current object to a method belonging to a different object (as in implementing callbacks, for example).

I have also discussed and illustrated the use of the super keyword in the following situations:

  • To bypass the overridden version of a method in a subclass and execute the version in the superclass.
  • To bypass a member variable in a subclass in order to access a member variable having the same name in a superclass.
  • To cause a constructor in a subclass to call a parameterized constructorin the immediate superclass.

What's next?

The next module in this collection will teach you how to use exception handling in Java.

Miscellaneous

This section contains a variety of miscellaneous information.

Housekeeping material
  • Module name: Java OOP: The this and super Keywords
  • File: Java1628.htm
  • Published: 08/08/13
Disclaimers:

Financial : Although the Connexions site makes it possible for you to download a PDF file for thismodule at no charge, and also makes it possible for you to purchase a pre-printed version of the PDF file, you should beaware that some of the HTML elements in this module may not translate well into PDF.

I also want you to know that, I receive no financial compensation from the Connexions website even if you purchase the PDF version of the module.

In the past, unknown individuals have copied my modules from cnx.org, converted them to Kindle books, and placed them for sale on Amazon.com showing me as the author. Ineither receive compensation for those sales nor do I know who does receive compensation. If you purchase such a book, please beaware that it is a copy of a module that is freely available on cnx.org and that it was made and published withoutmy prior knowledge.

Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.

-end-

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Object-oriented programming (oop) with java' conversation and receive update notifications?

Ask